Answer:
Below is an executive summary of this particular issue.
Explanation:
- Each organization has differential requirements and preferences. This same employment opportunities rely heavily on either the structure of the company and indeed the amount of equipment that it possesses.
- Hence, whenever they recruit an individual on a specific job, their work description can differ based on the organization's needs including growth.
/*
Since we have to check the first two options only as mentioned in last part of question the loop will work 2 times only and will compare the cost of first element and second and assign the healthoption accordingly
*/
for(int i =0;i<=1;i++){
if(annualCost[i]<annualCost[i+1]
best2 = healthOption[i]
else
best2 = healthOption[i+1]
}
Answer:
val > max
Explanation:
Assuming the values array is already created, inside the loop, we need to check if the val, a value in the values array, is greater than max. If it is greater than the max, that means it is our new max. Then we would set the max as the val. This way, if there is any value greater than max, it will be our max at the end of the loop.
