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nekit [7.7K]
2 years ago
14

Assume your friend just sent you 32 bits of pixel data (just the 0s and 1s for black and white pixels) that were encoded after s

ampling an image. Choose the two statements that are true.
------------------
The 32 bits of pixel data is enough to produce the image using the widget. Nothing else is needed.

------------------------
The digital image would be an exact copy of the analog image.

-----------------------------The correct width and height must be input into the pixelation widget to produce the image.

---------------------------The fact that only 32 bits were used to represent the image indicates relatively large sample squares were used. The digital image may vary from the analog image significantly.
Computers and Technology
1 answer:
lara31 [8.8K]2 years ago
3 0

Answer:

your friend just sent you 32 bits of pixel data (just the 0s and 1s for black and white pixels) that were encoded after sampling an image. Choose the two statements that are true.

------------------

The 32 bits of pixel data is enough to produce the image using the widget. Nothing else is needed.

------------------------

The digital image would be an exact copy of the analog image.

-----------------------------The correct width and height must be input into the pixelation widget to produce the image.

---------------------------The fact that only 32 bits were used to represent the image indicates relatively large sample squares were used. The digital image may vary from the analog image significantly

Explanation:

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Animated graphics that are displayed on the screen after a set of time when the computer is unattended.​
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Find a 95% confidence interval for the mean failure pressure for this type of roof panel.The article "Wind-Uplift Capacity of Re
aliya0001 [1]

Answer:

The 95% confidence interval would be given by (2.351;3.525)    

Explanation:

1) Previous concepts

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".

The margin of error is the range of values below and above the sample statistic in a confidence interval.

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

\bar X represent the sample mean  

\mu population mean (variable of interest)

s represent the sample standard deviation

n represent the sample size  

2) Confidence interval

The confidence interval for the mean is given by the following formula:

\bar X \pm t_{\alpha/2}\frac{s}{\sqrt{n}}   (1)

In order to calculate the mean and the sample deviation we can use the following formulas:  

\bar X= \sum_{i=1}^n \frac{x_i}{n} (2)  

s=\sqrt{\frac{\sum_{i=1}^n (x_i-\bar X)}{n-1}} (3)  

The mean calculated for this case is \bar X=2.938

The sample deviation calculated s=0.472

In order to calculate the critical value t_{\alpha/2} we need to find first the degrees of freedom, given by:

df=n-1=5-1=4

Since the Confidence is 0.95 or 95%, the value of \alpha=0.05 and \alpha/2 =0.025, and we can use excel, a calculator or a table to find the critical value. The excel command would be: "=-T.INV(0.025,4)".And we see that t_{\alpha/2}=2.78

Now we have everything in order to replace into formula (1):

2.938-2.78\frac{0.472}{\sqrt{5}}=2.351    

2.938+2.78\frac{0.472}{\sqrt{5}}=3.525    

So on this case the 95% confidence interval would be given by (2.351;3.525)    

5 0
2 years ago
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