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omeli [17]
2 years ago
9

A remediation liaison makes sure all personnel are aware of and comply with an organization's policies.

Computers and Technology
1 answer:
Ratling [72]2 years ago
8 0

Answer:

False.

Explanation:

I believe this should be the work of a compliance liaison. Assume you have opened up an organization that is growing each day. You have employees who are required to be compliant with all the security standards and policies. Hiring a compliance liaison will ensure that these compliances are being carried out. Each department in an organization should work with a compliance liaison to ensure that its employees understand and comply fully with all security policies.

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Which of the given assertion methods will return true for the code given below? Student student1 = new Student(); Student studen
Svetradugi [14.3K]

Answer:

The true statements are :

A. assertEquals(student1,student2)  

C. assertSame(student1,student3)

Explanation:

AssertEquals() asserts that the objects are equal, but assertSame() asserts that the passed two objects refer to the same object or not, if found same they return true, else return false.

6 0
2 years ago
Write an expression that continues to bid until the user enters 'n'.
alisha [4.7K]

Answer:

1)

Add this while statement to the code:

while(keep_going!='n'):  

#the program keeps asking user to continue bidding until the user enter 'n' to stop.

2)

Here is the code for ACTIVITY 53.3. While loop: Insect growth:

num_insects = int(input())

while num_insects <= 100:

   print(num_insects, end=' ')

   num_insects = num_insects * 2

 

Explanation:

Here is the complete code for 1)

import random

random.seed (5)

keep_going='-'

next_bid = 0

while(keep_going!='n'):

   next_bid = next_bid + random.randint(1, 10)

   print('I\'ll bid $%d!' % (next_bid))

   print('continue bidding?', end='')

   keep_going = input()

Here the the variable keep_going is initialized to a character dash keep_going='-'

The statement keep_going = input() has an input() function which is used to take input from user and this input value entered by user is stored in keep_going variable. while(keep_going!='n'):  is a while loop that keeps iterating until keep_going is not equal to 'n'.    print('continue bidding?', end='')  statement prints the continue bidding? message on the output screen. For example the user enters 'y' when this message appears on screen. So keep_going = 'y' . So the operation in this statement next_bid = next_bid + random.randint(1, 10) is executed in which next_bid is added to some randomly generated integer within the range of 1 to 10 and print('I\'ll bid $%d!' % (next_bid))  prints the result on the screen. Then the user is prompted again to continue biffing. Lets say user enters 'n' this time. So keep_going = 'n'. Now the while loop breaks when user enters 'n' and the program ends.

2)

num_insects = int(input()) #the user is prompted to input an integer

while num_insects <= 100: #the loop keeps iterating until value of num_insects exceeds 100

   print(num_insects, end=' ') #prints the value of num_insects  

   num_insects = num_insects * 2 #the value of num_insects is doubled

For example user enters 8. So

num_insects = 8

Now the while loop checks if this value is less than or equal to 100. This is true because 8 is less than 100. So the body of while loop executes:

   print(num_insects, end=' ') statement prints the value of num_insects

So 8 is printed on the screen.

num_insects = num_insects * 2 statement doubles the value of num_insects So this becomes:

num_insects = 8 * 2

num_insects = 16

Now while loop checks if 16 is less than 100 which is again true so next 16 is printed on the output screen and doubled as:

num_insects = 16 * 2

num_insects = 32

Now while loop checks if 32 is less than 100 which is again true so next 32 is printed on the output screen and doubled as:

num_insects = 32 * 2

num_insects = 64

Now while loop checks if 64 is less than 100 which is again true so next 64 is printed on the output screen and doubled as:

num_insects = 64 * 2

num_insects = 128

Now while loop checks if 128 is less than 100 which is false so the program stops and the output is:

8 16 32 64  

The programs along with their output is attached.

7 0
2 years ago
Write a function named printtriangle that receives a parameter that holds a non-negative integer value and prints a triangle of
NemiM [27]
Static void PrintTriangle(int n){    for(;n>0;n--) {                Console.WriteLine(new String('*', n));    }}
5 0
2 years ago
A 1.17 g sample of an alkane hydrocarbon gas occupies a volume of 674 mL at 28°C and 741 mmHg. Alkanes are known to have the gen
Nina [5.8K]

Answer:

C3H8

Explanation:

Step 1:

Data obtained from the question. This includes the following:

Mass of alkane = 1.17g

Volume (V) = 674 mL

Temperature (T) = 28°C

Pressure (P) = 741 mmHg.

Gas constant (R) = 0.08206 atm.L/Kmol

Step 2:

Conversion to appropriate unit.

For Volume:

1000mL = 1L

Therefore, 674mL = 674/1000 = 0.674L

For Temperature:

Temperature (Kelvin) = Temperature (celsius) + 273

Temperature (celsius) = 28°C

Temperature (Kelvin) = 28°C + 273 = 301K

For Pressure:

760mmHg = 1atm

Therefore, 741 mmHg = 741/760 = 0.975atm

Step 3:

Determination of the number of mole of the alkane..

The number of mole of the alkane can be obtained by using the ideal gas equation. This is illustrated below:

Volume (V) = 0.674L

Temperature (T) = 301K

Pressure (P) = 0.975atm

Gas constant (R) = 0.08206 atm.L/Kmol

Number of mole (n) =?

PV = nRT

n = PV /RT

n = (0.975 x 0.674)/(0.08206x301)

n = 0.0266 mole

Step 4:

Determination of the molar mass of the alkane.

Mass of alkane = 1.17g

Number of mole of the alkane = 0.0266mole

Molar Mass of the alkane =?

Number of mole = Mass/Molar Mass

Molar Mass = Mass/number of mole

Molar Mass of the alkane = 1.17/0.0266 = 44g/mol

Step 5:

Determination of the molecular formula of the alkane.

This is illustrated below:

The general formula for the alkane is CnH2n+2

To obtain the molecular formula for the alkane we shall assume n = 1, 2, 3 or more till we arrive at molar Mass of 44.

When n = 1

CnH2n+2 = CH4 = 12 + (4x1) = 16g/mol

When n = 2

CnH2n+2 = C2H6 = (12x2) + (6x1) = 30g/mol

When n = 3

CnH2n+2 = C3H8 = (12x3) + (8x1) = 44g/mol

We can see that when n is 3, the molar mass is 44g/mol.

Therefore, the molecular formula for the alkane is C3H8.

7 0
2 years ago
How can we make our programs behave differently each time they are run?
tensa zangetsu [6.8K]

Answer:

By given the right speech as much as the answers must be

Explanation:

By given the right speech as much as the answers must be

7 0
1 year ago
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