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yan [13]
1 year ago
8

A large offshore oil platform needs to transmit signals between different devices on the platform with high reliability and low

latency. However, they are unable to cover the platform with their existing Wi-Fi connections.What is the best solution for the platform in this scenario?
Computers and Technology
1 answer:
Brilliant_brown [7]1 year ago
6 0

This is based on getting a more efficient network.

<u><em>Best solution will be for them to install a private 5G connection on the platform</em></u><u>.</u>

<u> </u>

  • Now, we are told that they are not able to cover the platform with the Wi-Fi connections they are currently using.

Now, they need a connection that has high reliability and lower latency.

  • Now,  lower latency simply means there is little to no delay between the connection sending and receiving information. That means it can process a very high volume of data with very little delay. This indicates a very fast and efficient connection.

  • Since they are currently using Wi-Fi, it means they need something with a faster speed.

Wi-Fi could be 4G operates at around a frequency of 2.4GHz and speed of  while the one of 5G operates around 30 GHz.

  • Also, latency of 4G Wi-Fi is around 50 milliseconds while 5G is around 1 millisecond.

  • Also, the speed of 5G could be up to 20 GB per second which is almost 20 times more than that of 4G.

Thus, 5G is faster and also has a much lower latency than 4G Wi-Fi.

Thus, the best solution will be for them to install a private 5G connection on the platform.

Read more at; brainly.in/question/46252999

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Answer:

The program in C++ is as follows:

#include <iostream>

using namespace std;

double *sum_n_avg(double n1, double n2, double n3);

int main () {

   double n1, n2, n3;

   cout<<"Enter 3 inputs: ";

   cin>>n1>>n2>>n3;

   double *p;

   p = sum_n_avg(n1,n2,n3);

   cout<<"Sum: "<<*(p + 0) << endl;

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double *sum_n_avg(double n1, double n2, double n3) {

  static double arr[2];

  arr[0] = n1 + n2 + n3;

  arr[1] = arr[0]/3;

  return arr;

}

Explanation:

This defines the function prototype

double *sum_n_avg(double n1, double n2, double n3);

The main begins here

int main () {

This declares variables for input

   double n1, n2, n3;

This prompts the user for 3 inputs

   cout<<"Enter 3 inputs: ";

This gets user inputs

   cin>>n1>>n2>>n3;

This declares a pointer to get the returned values from the function

   double *p;

This passes n1, n2 and n3 to the function and gets the sum and average, in return.

   p = sum_n_avg(n1,n2,n3);

Print sum and average

<em>    cout<<"Sum: "<<*(p + 0) << endl;</em>

<em>    cout<<"Average: "<<*(p + 1) << endl;</em>

  return 0;

}

The function begins here

double *sum_n_avg(double n1, double n2, double n3) {

Declare a static array

  static double arr[2];

Calculate sum

  arr[0] = n1 + n2 + n3;

Calculate average

  arr[1] = arr[0]/3;

Return the array to main

  return arr;

}

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Answer:

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