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yan [13]
1 year ago
8

A large offshore oil platform needs to transmit signals between different devices on the platform with high reliability and low

latency. However, they are unable to cover the platform with their existing Wi-Fi connections.What is the best solution for the platform in this scenario?
Computers and Technology
1 answer:
Brilliant_brown [7]1 year ago
6 0

This is based on getting a more efficient network.

<u><em>Best solution will be for them to install a private 5G connection on the platform</em></u><u>.</u>

<u> </u>

  • Now, we are told that they are not able to cover the platform with the Wi-Fi connections they are currently using.

Now, they need a connection that has high reliability and lower latency.

  • Now,  lower latency simply means there is little to no delay between the connection sending and receiving information. That means it can process a very high volume of data with very little delay. This indicates a very fast and efficient connection.

  • Since they are currently using Wi-Fi, it means they need something with a faster speed.

Wi-Fi could be 4G operates at around a frequency of 2.4GHz and speed of  while the one of 5G operates around 30 GHz.

  • Also, latency of 4G Wi-Fi is around 50 milliseconds while 5G is around 1 millisecond.

  • Also, the speed of 5G could be up to 20 GB per second which is almost 20 times more than that of 4G.

Thus, 5G is faster and also has a much lower latency than 4G Wi-Fi.

Thus, the best solution will be for them to install a private 5G connection on the platform.

Read more at; brainly.in/question/46252999

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Create an array w with values 0, 0.1, 0.2, . . . , 3. Write out w[:], w[:-2], w[::5], w[2:-2:6]. Convince yourself in each case
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w = [i/10.0 for i in range(0,31,1)]

w[:]  = [0.0, 0.1, 0.2, 0.3, 0.4, 0.5, 0.6, 0.7, 0.8, 0.9, 1.0, 1.1, 1.2, 1.3, 1.4, 1.5, 1.6, 1.7, 1.8, 1.9, 2.0, 2.1, 2.2, 2.3, 2.4, 2.5, 2.6, 2.7, 2.8, 2.9, 3.0]

w[:-2] = [0.0, 0.1, 0.2, 0.3, 0.4, 0.5, 0.6, 0.7, 0.8, 0.9, 1.0, 1.1, 1.2, 1.3, 1.4, 1.5, 1.6, 1.7, 1.8, 1.9, 2.0, 2.1, 2.2, 2.3, 2.4, 2.5, 2.6, 2.7, 2.8]

w[::5]= [0.0, 0.5, 1.0, 1.5, 2.0, 2.5, 3.0]

w[2:-2:6] = [0.2, 0.8, 1.4, 2.0, 2.6]

Explanation:

List slicing (as it is called in python programming language ) is the creation of list by defining  start, stop, and step parameters.

w = [i/10.0 for i in range(0,31,1)]

The line of code above create the list w with values 0, 0.1, 0.2, . . . , 3.

w[:]  = [0.0, 0.1, 0.2, 0.3, 0.4, 0.5, 0.6, 0.7, 0.8, 0.9, 1.0, 1.1, 1.2, 1.3, 1.4, 1.5, 1.6, 1.7, 1.8, 1.9, 2.0, 2.1, 2.2, 2.3, 2.4, 2.5, 2.6, 2.7, 2.8, 2.9, 3.0]

since start, stop, and step parameters are not defined, the output returns all the list elements.

w[:-2] = [0.0, 0.1, 0.2, 0.3, 0.4, 0.5, 0.6, 0.7, 0.8, 0.9, 1.0, 1.1, 1.2, 1.3, 1.4, 1.5, 1.6, 1.7, 1.8, 1.9, 2.0, 2.1, 2.2, 2.3, 2.4, 2.5, 2.6, 2.7, 2.8]

w[:-2] since  stop is -2, the output returns all the list elements from the beginning to just before the second to the last element.

w[::5]= [0.0, 0.5, 1.0, 1.5, 2.0, 2.5, 3.0]

w[::5] since  step is -2, the output returns  the list elements at index 0, 5, 10, 15, 20, 25,30

w[2:-2:6] = [0.2, 0.8, 1.4, 2.0, 2.6]

the output returns the list elements from the element at index 2  to just before the second to the last element, using step size of 6.

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