Answer:
<em>a. fetch</em>
Explanation:
<em>The device collects a program command from its memory during the run cycle of the fetch.
</em>
It then defines and performs the activities needed for that command. The CPU continuously repeats the cycle of fetching, decoding, and executing a command while the computer is switched on.
The way in which this client is benefiting from switching to a cloud-based enterprise platform is in terms of<em><u> efficiency.</u></em>
An enterprise platform is a base upon which companies can<u> build on the technology they have</u>. Some of the many benefits of this include:
- <em>Efficiency </em>
- Simplicity
- Expandability
and many more. A cloud-based enterprise platform allows a company to keep up to modern-day standards and stay competitive.
A cloud-based enterprise platform allows all of the users to access the data remotely, making work much more simple and removing the space limitations of on-site legacy systems, which allows the client to expand and hire new workers.
One of the ways in which this client is benefiting from switching to a <em>cloud-based enterprise platform</em> is in terms of efficiency. By removing the on-site model of work, this client will allow her workers to access the database and interchange information which other sectors all from a single server, <u>increasing efficiency greatly.</u>
To learn more visit:
brainly.com/question/24053883?referrer=searchResults
Answer:
This is Elijah from FLVS hihi :DDDDDDDDDDDDDDDDDDDDDDDDDDDDD CVS
Explanation:
Answer:
See explaination
Explanation:
#include<iostream>
#include<stack>
#include <algorithm> // std::make_heap, std::pop_heap, std::push_heap, std::sort_heap
#include <vector> // std::vector
using namespace std;
void StaticArray()
{
unsigned int array[64536];
for(unsigned int i=0;i<64536;i++)
array[i]=i;
}
void Stack()
{
stack<unsigned int> mystack;
for(unsigned int i=0;i<64536;i++)
mystack.push(i);
}
void Heap()
{
unsigned int myints[64536];
for(unsigned int i=0;i<64536;i++)
myints[i]=i;
vector<unsigned int> v(myints,myints+64535);
make_heap (v.begin(),v.end());
push_heap (v.begin(),v.end());
}
int main()
{
StaticArray();
Stack();
Heap();
return 0;
}