A saftey issue because what is the car malfunctions or red light or police jus drive yo own car
Answer:
servers to be upgraded are : APPLICATION AND LOAD BALANCING SERVERS
servers still appropriate to use : DNS AND DHCP SERVERS
Explanation:
The recommendations to be made in line with what the new director of information is asking for includes :
1 ) For the servers to be upgraded : The servers that requires upgrades includes the APPLICATION SERVER and LOAD BALANCING SERVER. this is because these two servers are critical to the growth/expansion of any business, and they handle large volume of data
Recommendations on the servers upgrade includes:
Hardware : 2.3 GHz Intel Xeon Gold 5118 12-Core
CPU chip set : Socket: FCLGA3647, Type: NSBM
Speed : processor 3.2 GHz
caching: > 100 Gb
2) For servers that do not necessarily need to be upgraded : The servers that do not need immediate upgrade are DNS and DHCP
Answer:
The code to this question can be given as:
Code:
int i,j,count_previous=0,count_next=0; //define variable
for (j=0; j<n; j++) //loop for array
{
if (x[0]==x[j]) //check condition
{
count_previous++; //increment value by 1.
}
}
for (i=0; i<n; i++) //loop
{
for (j=0; j<n; j++)
{
if (x[i]==x[j]) //check condition
{
count_next++; //increment value by 1.
}
}
if (count_previous>count_next) //check condition
{
mode=x[i-1];
}
else
{
mode=x[i];
count_previous=count_next; //change value.
count_next= 0 ; //assign value.
}
}
Explanation:
In the question it is define that x is array of the string elements that is already define in the question so the code for perform operation in the array is given above. In the code firstly we define the variable that is i, j, count_previous, count_next. The variable i,j is used in the loop and variable count_previous and count_next we assign value 0 that is used for check the values of array. Then we define the for loop in this loop we use conditional statement in the if block we check that array of zero element is equal to array of j value then the count_previous is increase by 1. Then we use nested loop It is also known as loop in a loop. In this first loop is used for array and the second loop is used for check array element.In this we use the condition that if array x of i value is equal to array x of j then count_next will increment by 1.Then we use another condition that is if count_previous is greater then count_next then mode of x is decrement by 1. else mode equal to array and count_previous holds the value of count_next and count_next is equal to 0.
The below code will help you to solve the given problem and you can execute and cross verify with sample input and output.
#include<stdio.h>
#include<string.h>
int* uniqueValue(int input1,int input2[])
{
int left, current;
static int arr[4] = {0};
int i = 0;
for(i=0;i<input1;i++)
{
current = input2[i];
left = 0;
if(current > 0)
left = arr[(current-1)];
if(left == 0 && arr[current] == 0)
{
arr[current] = input1-current;
}
else
{
for(int j=(i+1);j<input1;j++)
{
if(arr[j] == 0)
{
left = arr[(j-1)];
arr[j] = left - 1;
}
}
}
}
return arr;
}
I think the most suitable chart to be used is a pie chart. A pie chart is used to show percentages and the best way to show relative sizes of data in your set. It is a good way to show which language is spoken more in the classroom, which is least spoken and at a glance. I hope my answer helps.
