Answer:
subnets=65536
Explanation:
As we know that,
-->interface ID portion of address starts from 64
--> we have 48 network prefix
so
available bits for subnet are = 64-48= 16
so with 16 bit address we can create subnet = 2^16 = 65535
Answer:
O(n^2)
Explanation:
The number of elements in the array X is proportional to the algorithm E runs time:
For one element (i=1) -> O(1)
For two elements (i=2) -> O(2)
.
.
.
For n elements (i=n) -> O(n)
If the array has n elements the algorithm D will call the algorithm E n times, so we have a maximum time of n times n, therefore the worst-case running time of D is O(n^2)
Answer:
double ComputeGasVolume(double pressure, double temperature, double moles){
double volume = moles*GAS_CONST*temperature/pressure;
return volume;
}
Explanation:
You may insert this function just before your main function.
Create a function called ComputeGasVolume that takes three parameters, pressure, temperature, and moles
Using the given formula, PV = nRT, calculate the volume (V = nRT/P), and return it.
Answer:
See explanation
Explanation:
The attachment show that you've attempted the question already.
I'll assist in making corrections to your source code.
First, edit line 5 to
if(r<= 255 and g<=255 and b <=255):
Then edit line 8 to:
if(r>= 255):
Then edit line 11 to:
if(g>= 255):
Lastly, edit line 14 to:
if(b>= 255):
<em>Other part of the attachment is correct</em>
Answer:
When the transmission exceeds 667 packets
Explanation:
In computer networking, a packet is a chunk of data transmitted across the network. The packet size of an Ethernet network is 1.5kilobytes, while the packet size of an IP packet payload is 64 kilobytes.
A switch is a physical network device that connects nodes or workstations while communicating the packets (or frames). The I/O bus size bandwidth is 1Gbps which allows approximately 667 packets. Once this packet size is crossed, the bus becomes a limiting factor or bottle neck.
