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Yuri [45]
2 years ago
11

Multiple Choice: We have been assigned the task of developing a software testing tool (tester) that can assess reachability of s

tatements in a program. Namely, given a program and a statement x in the program (line in the code), the tester should produce a sequence of inputs that demonstrates that the program can reach statement x, or declare that statement x is not reachable under any input sequence. What should we respond to the manager who assigned this task
Computers and Technology
1 answer:
egoroff_w [7]2 years ago
6 0

Answer:

A. There is no algorithm to decide whether this can be done or not.

Explanation:

We should respond to the manager who assigned this task that there is no algorithm to decide whether this can be done or not. This is because there are many unknowns with the program that is provided. There are various programming languages and each one has its own structure and requirements in order to test them. Also, each function is created differently with different inputs that are necessary and different algorithms used. It is impossible to design a single algorithm that works to test every single provided program. That is why testers have to create custom test cases for each function.

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blank one: light colored

blank two: bold format??

not sure but here is my best guess

8 0
2 years ago
Escribe, en los siguientes cuadros, los conceptos que correspondan
Fofino [41]

Answer:

Débito o debe                                                         Crédito o haber

Préstamo de la cooperativa                                          Efectivo

Gasto de arriendo                                              Cuentas por cobrar

Cuentas por pagar                                          Documentos por cobrar

Gasto de publicidad                                                Capital social

Hipoteca por pagar                                                       Ventas

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Bancos (en el caso que deba productos bancarios)

Explanation:

3 0
2 years ago
3. Megan and her brother Marco have a side business where they shop at flea markets, garage sales, and estate
Neko [114]

Answer:

a

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4 0
2 years ago
Write a function that implements another stack function, peek. Peek returns the value of the first element on the stack without
devlian [24]

Answer:

See explaination

Explanation:

StackExample.java

public class StackExample<T> {

private final static int DEFAULT_CAPACITY = 100;

private int top;

private T[] stack = (T[])(new Object[DEFAULT_CAPACITY]);

/**

* Returns a reference to the element at the top of this stack.

* The element is not removed from the stack.

* atreturn element on top of stack

* atthrows EmptyCollectionException if stack is empty

*/

public T peek() throws EmptyCollectionException

{

if (isEmpty())

throw new EmptyCollectionException("stack");

return stack[top-1];

}

/**

* Returns true if this stack is empty and false otherwise.

* atreturn true if this stack is empty

*/

public boolean isEmpty()

{

return top < 0;

}

}

//please replace "at" with the at symbol

Note:

peek() method will always pick the first element from stack. While calling peek() method when stack is empty then it will throw stack underflow error. Since peek() method will always look for first element ffrom stack there is no chance for overflow of stack. So overflow error checking is not required. In above program we handled underflow error in peek() method by checking whether stack is an empty or not.

3 0
2 years ago
Write a function summarize_letters that receives a string and returns a list of tuples containing the unique letters and their f
marysya [2.9K]

Answer:

Explanation:

2nd part

def summarize_letters(string):

#Initializaing a empty dictionary

character_counter = {}

#converting all the characters to lowercase

string_lower = string.lower()

for i in string_lower:

#checking if the chacter presents in the dictionary then increase it by one and also to check if the character is alphabet

if i in character_counter and i.isalpha():

character_counter[i] = character_counter[i]+1

#checking if the character not present in the dictionary then assign 1

if i not in character_counter and i.isalpha():

character_counter[i] = 1

#converting the dictionary to list of tuples

list_of_tuples = [(k, v) for k, v in character_counter.items()]

return list_of_tuples

#3rd Part

#initializing a string of characters in alphabets

alphabets = 'a b b b b B A c e f g d h i j k B l m M n o p q r s P t u v w x y z'

print(summarize_letters(alphabets))

#importing the string module

import string

#pulling all the alphabets

alphabet = set(string.ascii_lowercase)

#checking if our hardcoded string has all the alphabets

if set(alphabets.lower()) >= alphabet:

print('The string ' +alphabets+' has all the letters in the alphabet ')

3 0
2 years ago
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