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ICE Princess25 [194]
2 years ago
7

Which telecommunications device is widely used in industries that require closed communication?

Computers and Technology
2 answers:
forsale [732]2 years ago
7 0

Answer:

<u>D. walkie-talkies </u>

Explanation:

<u>walkie-talkies </u>are used in industries that require closed communication

Stella [2.4K]2 years ago
3 0

The telecommunications device that  is widely used in industries that require closed communication are walkie-talkies. Correct answer: D

Walkie-talkies are hand-held, portable, two-way radio transceivers which enable secure communication between the two points, without being part of a network.

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Which of the following is an advantage of inserting a page number field in your document rather than inserting each page number
Artyom0805 [142]

The advantage of inserting the page number field is that the page number field could show the current page number.

The following information should be relevant with respect to the page number:

  • The page number field & the actual page number should be formatted.
  • The page number field & the actual page number both could be inserted into the header or footer.
  • The page number field & the actual page number could be easily inserted into the document.

Therefore we can conclude that the advantage of inserting the page number field is that the page number field could show the current page number.

Learn more about the page number here: brainly.com/question/3063419

8 0
2 years ago
If a user was complaining about a "slow computer" due to a program that uses a significant amount of memory, what part or parts
Sedaia [141]

Answer:

The Random-Access Memory (RAM) should be upgraded.

Explanation:

Since the particuar apllication is taking alot of memory space it means that an ugrade/ installation of a bigger RAM would help the system work better while using the program

6 0
2 years ago
Each frame is composed of a number of colors recorded in digital format; we call these pixels. What information does the number
Nookie1986 [14]
I'd say the size of the frame.

The size, quantity and color combination of pixels is measured in terms of display resolution. A resolution, however, is the number of pixels in an image and is identified by the width and the height. How you’ve set the resolution for the display screen will determine the specific size of the pixels.






7 0
2 years ago
Remember that ""state space"" refers to the space of all potential possibilities. Which dichotomous questions below will success
egoroff_w [7]

Answer:

Please check options are not given. Please check explanation for corrected version.

Explanation:

Options are not mentioned. Please post the complete question.

However, if "below" is removed, the question makes sense. I am taking it that way.

Dichotomous question means those questions which has two outcomes: true or false.

For the given condition, this is possible only if:

  • coin shows head and dice shows 1
  • coin shows head and dice shows 2
  • head, 3
  • head, 4
  • head, 5
  • head, 6
  • tails, and all above cases

However, each time, each mentioned condition should be strictly followed.

And fewer outcome than 1 is virtually or realistically impossible, as both coin and dice will roll out one outcome in any condition certainly.

7 0
2 years ago
Suppose your company has decided that it needs to make certain busy servers faster. Processes in the workload spend 60% of their
vekshin1

Answer:

CPU need 50% much faster

disk need 100% much faster

Explanation:

given data

workload spend time CPU  = 60%

workload spend time I/O = 40%

achieve overall system speedup = 25%

to find out

How much faster does CPU need and How much faster does the disk need

solution

we apply here Amdahl’s law for the overall speed of a computer that is express as

S = \frac{1}{(1-f)+ \frac{f}{k} }      .............................1

here f is fraction of work i.e 0.6 and S is overall speed  i.e 100% + 25% = 125 % and k is speed up of component

so put all value in equation 1 we get

S = \frac{1}{(1-f)+ \frac{f}{k} }  

1.25 = \frac{1}{(1-0.6)+ \frac{0.6}{k} }  

solve we get

k = 1.5

so we can say  CPU need 50% much faster

and

when f = 0.4 and S = 125 %

put the value in equation 1

S = \frac{1}{(1-f)+ \frac{f}{k} }  

1.25 = \frac{1}{(1-0.4)+ \frac{0.4}{k} }  

solve we get

k = 2

so here disk need 100% much faster

7 0
2 years ago
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