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melisa1 [442]
2 years ago
13

Mathematical computations by a computer are faster than your quickest mathematical computations because the top speed of a neura

l impulse is about ________ times slower than the speed of electricity through the wired circuitry in a computer.
Computers and Technology
1 answer:
Tema [17]2 years ago
6 0

Answer:

3 million

Explanation:

According to my research on information technology, I can say that based on the information provided within the question the top speed of a neural impulse is about 3 million times slower than the speed of electricity through the wired circuitry in a computer. Neurons have been calculated as firing roughly 200 times per second, while a computer processing unit processes at about 600 million instructions per second.

I hope this answered your question. If you have any more questions feel free to ask away at Brainly.

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The terminal window wants to evaluate your current bash knowledge by using the ~/workspace/nested-directories folder:
tia_tia [17]

Answer:

a. cd into the nested directories/ nested - level - 1 / directory using an absolute path

Explanation:

The directory is a location on the hard disk, which is also called a folder. It contains the files and also contains the other directories called sub directories.

A path to a file is merged with a slash and determines the file or directory in the operating system. An absolute path is the location file or directory from the actual file system

The directory's absolute path starts with a slash, and all slashed in the directory separates the directions.

All directions in the absolute path are written on the left side. The last name in the path may belong to the file, and the pwd command can determine the current directory.

The relative path is the location of the file. It begins with the working directory. An absolute path is unambiguous and working with deeply nested directories.

There are two commands which are used such as

  • cd
  • pwd
  1. cd is used for changing directory
  2. pwd is used for the working directory

We easily navigate the file system with the help of an absolute path.

7 0
2 years ago
Recall the problem of finding the number of inversions. As in the text, we are given a sequence of n numbers a1, . . . , an, whi
Kay [80]

Answer:

The algorithm is very similar to the algorithm of counting inversions. The only change is that here we separate the counting of significant inversions from the merge-sort process.

Algorithm:

Let A = (a1, a2, . . . , an).

Function CountSigInv(A[1...n])

if n = 1 return 0; //base case

Let L := A[1...floor(n/2)]; // Get the first half of A

Let R := A[floor(n/2)+1...n]; // Get the second half of A

//Recurse on L. Return B, the sorted L,

//and x, the number of significant inversions in $L$

Let B, x := CountSigInv(L);

Let C, y := CountSigInv(R); //Do the counting of significant split inversions

Let i := 1;

Let j := 1;

Let z := 0;

// to count the number of significant split inversions while(i <= length(B) and j <= length(C)) if(B[i] > 2*C[j]) z += length(B)-i+1; j += 1; else i += 1;

//the normal merge-sort process i := 1; j := 1;

//the sorted A to be output Let D[1...n] be an array of length n, and every entry is initialized with 0; for k = 1 to n if B[i] < C[j] D[k] = B[i]; i += 1; else D[k] = C[j]; j += 1; return D, (x + y + z);

Runtime Analysis: At each level, both the counting of significant split inversions and the normal merge-sort process take O(n) time, because we take a linear scan in both cases. Also, at each level, we break the problem into two subproblems and the size of each subproblem is n/2. Hence, the recurrence relation is T(n) = 2T(n/2) + O(n). So in total, the time complexity is O(n log n).

Explanation:

5 0
2 years ago
Frank works for an organization that wishes to install a software program on a single server with multiple users connected. Whic
Helen [10]
The best answer to this question should be (A) Cloud Computing.

In general, cloud computing is the term used for the delivery of hosted services over the internet. We can also simply put cloud computing as the delivery of computing services like storage, servers, databases, software and more over the internet.




7 0
2 years ago
Write a static method named countLastDigits that accepts an array of integers as a parameter and examines its elements to determ
Crazy boy [7]

Answer:

See explaination for the program code

Explanation:

code:

public static int[] countLastDigits(int[] list) {

int[] count = new int[10];

for (int i = 0; i < list.length; i++) {

int digit = list[i] % 10;

count[digit]++;

}

return count;

}

8 0
2 years ago
Create a class named BaseballGame that contains data fields for two team names and scores for each team in each of nine innings.
m_a_m_a [10]

Answer:

Check the explanation

Explanation:

BaseballGame:

public class BaseballGame {

  protected String[] names = new String[2];

  protected int[][] scores;

  protected int innings;

  public BaseballGame() {

      innings = 9;

      scores = new int[2][9];

      for(int i = 0; i < 9; i++)

          scores[1][i] = scores[0][i] = -1;

  }

 

  public String getName(int team) {

      return names[team];

  }

  public void setNames(int team, String name) {

      names[team] = name;

  }

 

  public int getScore(int team, int inning) throws Exception {

      if(team < 0 || team >= 2)

          throw new Exception("Team is ut of bounds.");

      if(inning < 0 || inning >= innings)

          throw new Exception("Inning is ut of bounds.");

     

      return scores[team][inning];

  }

  public void setScores(int team, int inning, int score) throws Exception {

      if(team < 0 || team >= 2)

          throw new Exception("Team is ut of bounds.");

      if(inning < 0 || inning >= innings)

          throw new Exception("Inning is ut of bounds.");

      if(score < 0)

          throw new Exception("Score is ut of bounds.");

      for(int i = 0; i < inning; i++)

          if(scores[team][i] == -1)

              throw new Exception("Previous scores are not set.");

     

      scores[team][inning] = score;

  }

 

}

HighSchoolBaseballGame:

public class HighSchoolBaseballGame extends BaseballGame {

  public HighSchoolBaseballGame() {

      innings = 7;

      scores = new int[2][7];

      for(int i = 0; i < 7; i++)

          scores[1][i] = scores[0][i] = -1;

  }

}

LittleLeagueBaseballGame:

public class LittleLeagueBaseballGame extends BaseballGame {

  public LittleLeagueBaseballGame() {

      innings = 6;

      scores = new int[2][6];

      for(int i = 0; i < 6; i++)

          scores[1][i] = scores[0][i] = -1;

  }

}

6 0
2 years ago
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