Answer:
The minimum number of bits necessary to address 8K words is 13.
Explanation:
You have the number of words to address that is 8000 words, a word is the smallest addressable memory unit.
8000 words can be addressed with 
units. Now you have to find the value of n that approximates to the number of words.
So you can see that 13 bits are needed to address 8K words.
There are some function which can be performed with database but not with a spread sheet, these functions include:
1. Enforcement of data type.
2. Support for self documentation.
3. Defining the relationship among constraints in order to ensure consistency of data.
Answer:
<em>Ethernet cables, Network Adapters, Modem, Routers, Switches.</em>
Explanation:
<em>The devices that are required in setting up a wired network for the 5 computer comprises of the following devices </em>
- <em>Ethernet Cables</em>
- <em>Network Adapters</em>
- <em>Modem/Router</em>
- <em>Network Switch</em>
<em>Ethernet cables: They are called network cables or RJ-45 cables used to in connecting two or more computers together. it has different categories called, the untwisted pair and twisted pair Ethernet, with a speed from 10-1000</em>
<em>Network Adapters : This adapters allows a computer device to connect and interface with a network computer</em>
<em>Modem/Routers : A router is a device that that sits in the middle between your local computers and modems. it takes receives information or gets information from the modem and delivers it to the computer</em>
<em>Network switch: it connects more than two computers together to a network and share data among themselves and other devices on the network</em>
Answer:
The code to this question can be given as:
Code:
int i,j,count_previous=0,count_next=0; //define variable
for (j=0; j<n; j++) //loop for array
{
if (x[0]==x[j]) //check condition
{
count_previous++; //increment value by 1.
}
}
for (i=0; i<n; i++) //loop
{
for (j=0; j<n; j++)
{
if (x[i]==x[j]) //check condition
{
count_next++; //increment value by 1.
}
}
if (count_previous>count_next) //check condition
{
mode=x[i-1];
}
else
{
mode=x[i];
count_previous=count_next; //change value.
count_next= 0 ; //assign value.
}
}
Explanation:
In the question it is define that x is array of the string elements that is already define in the question so the code for perform operation in the array is given above. In the code firstly we define the variable that is i, j, count_previous, count_next. The variable i,j is used in the loop and variable count_previous and count_next we assign value 0 that is used for check the values of array. Then we define the for loop in this loop we use conditional statement in the if block we check that array of zero element is equal to array of j value then the count_previous is increase by 1. Then we use nested loop It is also known as loop in a loop. In this first loop is used for array and the second loop is used for check array element.In this we use the condition that if array x of i value is equal to array x of j then count_next will increment by 1.Then we use another condition that is if count_previous is greater then count_next then mode of x is decrement by 1. else mode equal to array and count_previous holds the value of count_next and count_next is equal to 0.
