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eimsori [14]
2 years ago
11

Summary: Given integer values for red, green, and blue, subtract the gray from each value. Computers represent color by combinin

g the sub-colors red, green, and blue (rgb). Each sub-color's value can range from 0 to 255. Thus (255, 0, 0) is bright red, (130, 0, 130) is a medium purple, (0, 0, 0) is black, (255, 255, 255) is white, and (40, 40, 40) is a dark gray. (130, 50, 130) is a faded purple, due to the (50, 50, 50) gray part. (In other words, equal amounts of red, green, blue yield gray). Given values for red, green, and blue, remove the gray part. Ex: If the input is: 130 50 130 the output is: 80 0 80 Find the smallest value, and then subtract it from all three values, thus removing the gray.Note: This page converts rgb values into colors.
the answer:
#include
using namespace std;
int main() {
int red;
int green;
int blue;
cin >> red >> green >> blue;
if ((red <= green) && (red <= blue)) {
cout << red;
}
else if ((green <= red) && (green <= blue)) {
cout << green;
}
else {
cout << blue;
}
return 0;
}
Computers and Technology
1 answer:
Dmitry_Shevchenko [17]2 years ago
5 0

Answer:

Follows are the code to this question:

#include<iostream>//defining header file

using namespace std;// use package

int main()//main method

{

int red,green,blue,x;//declaring integer variable

cin>> red >>green>>blue;//use input method to input value

if(red<green && red<blue)//defining if block that check red value is greater then green and blue  

{

x = red;//use x variable to store red value

}

else if(green<blue)//defining else if block that check green value greater then blue  

{

x= green; //use x variable to store green value

}

else//defining else block

{

x=blue;//use x variable to store blue value

}

red -= x;//subtract input integer value from x  

green -=x; //subtract input integer value from x

blue -= x;//subtract input integer value from x

cout<<red<<" "<<green<<" "<<blue;//print value

return 0;

}

Output:

130 50 130

80 0 80

Explanation:

In the given code, inside the main method, four integers "red, green, blue, and x" are defined, in which "red, green, and blue" is used for input the value from the user end. In the next step, a conditional statement is used, in the if block, it checks red variable value is greater than then "green and blue" variable. If the condition is true, it will store red variable value in "x", otherwise, it will goto else if block.

  • In this block, it checks the green variable value greater than the blue variable value. if the condition is true it will store the green variable value in x variable.
  • In the next step, else block is defined, that store blue variable value in x variable, at the last step input variable, is used that subtracts the value from x and print its value.      
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C....................
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Answer:

Transport mode

Explanation:

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Modify the sentence-generator program of Case Study so that it inputs its vocabulary from a set of text files at startup. The fi
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Answer:

Go to explaination for the program code.

Explanation:

Before running the program you need to have these files created like below in your unix box.

Unix Terminal> cat nouns.txt

BOY

GIRL

BAT

BALL

Unix Terminal> cat articles.txt

A

THE

Unix Terminal> cat verbs.txt

HIT

SAW

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Unix Terminal> cat prepositions.txt

WITH

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Unix Terminal>

Code:

#!/usr/local/bin/python3

import random

def getWords(filename):

fp = open(filename)

temp_list = list()

for each_line in fp:

each_line = each_line.strip()

temp_list.append(each_line)

words = tuple(temp_list)

fp.close()

return words

articles = getWords('articles.txt')

nouns = getWords('nouns.txt')

verbs = getWords('verbs.txt')

prepositions = getWords('prepositions.txt')

def sentence():

return nounPhrase() + " " + verbPhrase()

def nounPhrase():

return random.choice(articles) + " " + random.choice(nouns)

def verbPhrase():

return random.choice(verbs) + " " + nounPhrase() + " " + prepositionalPhrase()

def prepositionalPhrase():

return random.choice(prepositions) + " " + nounPhrase()

def main():

number = int(input('Enter number of sentences: '))

for count in range(number):

print(sentence())

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main()

kindly check attachment for code output and onscreen code.

6 0
2 years ago
python (Business: check ISBN-10) An ISBN-10 (International Standard Book Number) consists of 10 digits: d1d2d3d4d5d6d7d8d9d10. T
iogann1982 [59]

Answer:

<em>The programming language is not stated;</em>

<em>However, I'll answer this question using C++ programming language</em>

<em>The program uses few comments; See explanation section for more detail</em>

<em>Also, the program assumes that all input will always be an integer</em>

#include<iostream>

#include<sstream>

#include<string>

using namespace std;

int main()

{

string input;

cout<<"Enter the first 9 digits of an ISBN as a string: ";

cin>>input;

//Check length

if(input.length() != 9)

{

 cout<<"Invalid input\nLength must be exact 9";

}

else

{

 int num = 0;

//Calculate sum of products

for(int i=0;i<9;i++)

{

 num += (input[i]-'0') * (i+1);    

}

//Determine checksum

if(num%11==10)

{

 input += "X";

 cout<<"The ISBN-10 number is "<<input;

}

else

{

 ostringstream ss;

 ss<<num%11;

 string dig = ss.str();

 cout<<"The ISBN-10 number is "<<input+dig;

}

}  

 return 0;

}

Explanation:

string input;  -> This line declares user input as string

cout<<"Enter the first 9 digits of an ISBN as a string: ";  -> This line prompts the user for input

cin>>input;  -> The user input is stored here

if(input.length() != 9)  { cout<<"Invalid input\nLength must be exact 9";  }  -> Here, the length of input string is checked; If it's not equal to then, a message will be displayed to the screen

If otherwise, the following code segment is executed

else  {

int num = 0; -> The sum of products  of individual digit is initialized to 0

The sum of products  of individual digit is calculated as follows

for(int i=0;i<9;i++)

{

num += (input[i]-'0') * (i+1);

}

The next lines of code checks if the remainder of the above calculations divided by 11 is 10;

If Yes, X is added as a suffix to the user input

Otherwise, the remainder number is added as a suffix to the user input

if(num%11==10)  {  input += "X";  cout<<"The ISBN-10 number is "<<input; }

else

{

ostringstream ss;

ss<<num%11;

string dig = ss.str();

cout<<"The ISBN-10 number is "<<input+dig;

}

}  

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2 years ago
ArgumentException is an existing class that derives from Exception; you use it when one or more of a method’s arguments do not f
dybincka [34]

Answer:

The C# code is given below

Explanation:

using System;

public class SwimmingWaterTemperatur

{

public static void Main()

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try{

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}catch(Exception ex){

Console.WriteLine(ex);

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}

}

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return true;

}else if(temp>=32 && temp<=212){

return false;

}else{

throw new ArgumentException("Value does not fall within the exptected range.");

}

}

}

7 0
2 years ago
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