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harkovskaia [24]
2 years ago
8

Discuss how the user-designer communications gap can cause a good project to go bad.

Computers and Technology
1 answer:
Mila [183]2 years ago
3 0
This gap between user-designer communications <span>can cause a good project to go bad i</span>f the user is not able to process what is required to be fixed in order for the project to run smoothly. The user may have one way of fixing something while the designer has another. In this case, the designer understands how the project fully works while the user does not and this may end up compromising the whole project.

The law that “designers are not users” and “users are not designers” should always be followed.




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The Gas-N-Clean Service Station sells gasoline and has a car wash. Fees for the car wash are $1.25 with a gasoline purchase of $
beks73 [17]

Answer:

d = {"R":2.89,"P":3.09, "S":3.39, "N":0}

noofgallons = input("Enter number of Gallons:")

gastype = input("Enter Gas type/; R,P,S,N")

cwr = input("Is Car Was Requieed")

if(gastype == "R"):

   gal == nooffgallons * d['R']

   if (cwr=="y" and gal<10):

       gal+=3.00;

       elif(cwr=="y" and gal>=10):

           gal+=1.25

           elif(cwr=="n"):

               gal=gal

   elif(gastype==P):

       gal== nooffgallons * d['P']

       if(cwr="y" and gal<10):

           gal+=3.00;

           elif(cwr=="y"and gal>=10):

           gal+=1.25

           elif(cwr=="n"):

               gal=gal

       elif(gastype ==S):

           gal=noofgallons *d['S']

           if(cwr="y" and gal<10):

               gal+=3.00;

               elif(cwr=="y"and gal>=10):

                   gal+=1.25

                   elif(cwr=="n"):

                       gal=gal

                       

                       

print("tptal cost paid"+ gal)

The above program uses a dictionary for storing gasoline types and their cost, and dictionary is always constant, and hence its fulfilled the requirement of keeping it constant. And car wash is treated accordingly. And if elif else ladder has been used to calculate the total number of gallons.

Rest part is self explanatory.

Explanation:

The code is self explanatory.

7 0
2 years ago
You would like the user of a program to enter a customer’s last name. Write a statement thaUse the variables k, d, and s so that
mojhsa [17]

Answer:

1st question:

Use the variables k, d, and s so that they can read three different values from standard input an integer, a float, and a string respectively. On one line, print these variables in reverse order with exactly one space in between each. On a second line, print them in the original order with one space in between them.

Solution:

In Python:

k = input()  #prompts user to input value of k i.e. integer value

d = input()  #prompts user to input value of d i.e. float value

s = input()  #prompts user to input value of s i.e. a string

print (s, d, k)  #displays these variable values in reverse order

print (k, d, s)#displays these variable values in original order

In C++:

#include <iostream>    // to use input output functions

using namespace std;   //to identify objects like cin cout

int main() {    //start of main function

  int k;   //declare int type variable to store an integer value

  float d; //  declare float type variable to store a float value

  string s;   //  declare string type variable to store an integer value

  cin >> k >> d >> s;    //reads the value of k, d and s

  cout << s << " " << d << " " << k << endl;     //displays these variables values in reverse order

  cout << k << " " << d << " " << s << endl;   } // displays these variable values in original order

Explanation:

2nd question:

You would like the user of a program to enter a customer’s last name. Write a statement that asks user "Last Name:" and assigns input to a string variable called last_name.

Solution:

In Python:

last_name = input("Last Name:")

# input function is used to accept input from user and assign the input value to last_name variable

In C++:

string last_name;  //declares a string type variable named last_name

cout<<"Last Name: ";  // prompts user to enter last name by displaying this message Last Name:

cin>>last_name; // reads and assigns the input value to string variable last_name

The programs alongwith their outputs are attached.

6 0
2 years ago
What is the distance rn between the point of application of n⃗ and the axis of rotation? what is the distance rw between the poi
Mandarinka [93]

Complete Question.

A. Suppose that you are holding a pencil balanced on its point. If you release the pencil and it begins to fall, what will be the angular acceleration when it has an angle of 10.0 degrees from the vertical?

B. What is the distance rn between the point of application of n⃗ and the axis of rotation?

C. What is the distance rw between the point of application of w⃗ and the axis? enter your answers in meters separated by a comma?

Answer:

A. â = - 17rad/s²

B. rn = 0, meters

C. rw = 0.074, meters

Explanation:

Where;

l = length of the pencil

θ = angle between the vertical line and the pencil

â = angular acceleration.

The torque due to weight about the pivotal point is negative since it's clockwise;

t = - mg(l/2)sinØ ..... equation 1

torque with respect to angular acceleration;

t = Iâ ..... equation 2

The moment of Inertia of the pencil about one end;

I = (ml²)/3

Substituting I into equation 2;

t = [(ml²)/3]×â

Equating the equation, we have;

[(ml²)/3]×â = - mg(l/2)sinØ

â = (-3gsinØ)/2l

â = (-3*9.8*sin10°)/(2*0.15)

Angular acceleration, â = -17rad/s²

B. The normal force is acting at the normal force only, so the distance r n between the point of application of n ⃗ and the axis of rotation is zero because the axis of pencil is passing the same point of application w.

C. rn = (lcosØ)/2

rn = (0.15 * cos10°)/2

rn = (0.15 * 0.9848)/2

rn = (0.1477)/2

rn = 0.074m.

Since the gravity acts at exactly half of the length of pencil, distance r w between the point of application of w⃗ and the axis equals 0.074m.

8 0
2 years ago
Consider a short, 10-meter link, over which a sender can transmit at a rate of 150 bits/sec in both directions. Suppose that pac
Katarina [22]

Answer:

The Tp value 0.03 micro seconds as calculated in the explanation below is negligible. This would lead to a similar value of time delay for both persistent HTTP and non-persistent HTTP.

Thus, persistent HTTP is not faster than non-persistent HTTP with parallel downloads.

Explanation:

Given details are below:

Length of the link = 10 meters

Bandwidth = 150 bits/sec

Size of a data packet = 100,000 bits

Size of a control packet = 200 bits

Size of the downloaded object = 100Kbits

No. of referenced objects = 10

Ler Tp to be the propagation delay between the client and the server, dp be the propagation delay and dt be the transmission delay.

The formula below is used to calculate the total time delay for sending and receiving packets :

d = dp (propagation delay) + dt (transmission delay)

For Parallel downloads through parallel instances of non-persistent HTTP :

Bandwidth = 150 bits/sec

No. of referenced objects = 10

For each parallel download, the bandwith = 150/10

  = 15 bits/sec

10 independent connections are established, during parallel downloads,  and the objects are downloaded simultaneously on these networks. First, a request for the object was sent by a client . Then, the request was processed by the server and once the connection is set, the server sends the object in response.

Therefore, for parallel downloads, the total time required  is calculated as:

(200/150 + Tp + 200/150 + Tp + 200/150 + Tp + 100,000/150 + Tp) + (200/15 + Tp + 200/15 + Tp + 200/150 + Tp + 100,000/15 + Tp)

= ((200+200+200+100,00)/150 + 4Tp) + ((200+200+200+100,00)/15 + 4Tp)

= ((100,600)/150 + 4Tp) + ((100,600)/15 + 4Tp)

= (670 + 4Tp) + (6706 + 4Tp)

= 7377 + 8 Tp seconds

Thus, parallel instances of non-persistent HTTP makes sense in this case.

Let the speed of propogation  of the medium be 300*106 m/sec.

Then, Tp = 10/(300*106)

               = 0.03 micro seconds

The Tp value 0.03 micro seconds as calculated above is negligible. This would lead to a similar value of time delay for both persistent HTTP and non-persistent HTTP. Thus, persistent HTTP is not faster than non-persistent HTTP with parallel downloads.

4 0
2 years ago
Which formula would you enter into C3, and then AutoFill into C4 through C6, to calculate the percent sales (Pct.) for the regio
inna [77]

Answer:

In C3, you would enter the formula:

  • =B3/$B$7%

Explanation:

Let's assume the first row is 1 and it contains the titles of the columns.  For instance, the content of the cellss A1:C1 could be:

  • A1: Region
  • B1: Sales
  • C1: Percent Sales

Also, assume the second row is empty and the cells on the first column, A, contain the names of four regions. For instance, North, South, East, and West:

  • A3: North
  • A4: South
  • A5: East
  • A6: West

The cells B3:B6 contain the sales for the four regions. For instance:

  • B3: 200
  • B4: 300
  • B5: 100
  • B6: 400

Then, you must calculate the percent sales for every region, in the cells <em>C3:C6.</em>

That means, you must divide the sale of every region by the total of sales and multiply by 100.

To do that in the worksheet you do this:

<u>1. Sum the sales for the regions:</u>

  • In cell B7 introduce: =SUM(B3:B6)

<u>2. Calculate the percent sale for the first region:</u>

  • In cell C3 introduce: =B3/$B$7%

That means that the reference B3 is relative: when you copy that formula, the column (B) and the row (3) will change accordingly to the cell where you will copy it.

Thus, by using the Autofill into C4 through C6, the column wil remain unchanged (C) and the row will change to 4, 5, and 6, respectively.

The symbol $ used in $B$7 make the reference absolute. That means that they will not change. The symbol % makes that the result is multiplied by 100.

<u>3. When you use Autofull into C4 through C6, you obtain:</u>

  • C4: =B4/$B$7%
  • C5: =B5/$B$7%
  • C6: =B6/$B$7%
4 0
2 years ago
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