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bazaltina [42]
2 years ago
12

Peter took a selfie in his room. He was a wearing a light blue shirt. But he failed to realize that that shirt would clash in co

lor with the light blue walls in his room. He wants to edit this photo using editing software. Which tool can Peter use to darken the background in his photo?
Computers and Technology
2 answers:
Leto [7]2 years ago
7 0

Answer:

A wand tool is to do that in an editing software.

liubo4ka [24]2 years ago
6 0

Answer: Peter should use the <em>burn tool</em>

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Complete the program below that takes in one positive, odd, integer, n (at least 3), and prints a "diamond" shape of stars with
avanturin [10]

Answer:

n = int(input("Enter the n (positive odd integer): "))

for i in range(1, n+1, 2):

   print(i*"*")

for i in range(n-2, 0, -2):

   print(i*"*")

Explanation:

*The code is in Python.

Ask the user to enter the n

Create a for loop that iterates from 1 to n, incrementing by 2 in each iteration. Print the corresponding number of asterisks in each iteration

Create another for loop that iterates from n-2 to 1, decrementing by 2 in each iteration. Print the corresponding number of asterisks in each iteration

5 0
2 years ago
Problem 1a. Write a function named hasFinalLetter that takes two parameters 1. strList, a list of non-empty strings 2. letters,
mash [69]

Answer:

The answer is the programming in Python language has strings and characters that has to be declared in the method.

Explanation:

#method

def hasFinalLetter(strList,letters):

output = #output list

#for every string in the strList

for string in strList:

#findout the length of each string in strList

length = len(string)

#endLetter is last letter in each string

endLetter = string[length-1]

#for each letter in the letters list

for letter in letters:

#compare with endLetter

#if we found any such string

#add it to output list

if(letter == endLetter):

output.append(string)

#return the output list

return output

#TestCase 1 that will lead to return empty list

strList1 = ["user","expert","login","compile","Execute","stock"]

letters1 = ["a","b","y"]

print hasFinalLetter(strList1,letters1)

#TestCse2

strList2 = ["user","expert","login","compile","Execute","stock"]

letters2 = ["g","t","y"]

print hasFinalLetter(strList2,letters2)

#TestCase3

strList3 = ["user","expert","login","compile","Execute","stock"]

letters3 = ["k","e","n","t"]

print hasFinalLetter(strList3,letters3)

8 0
2 years ago
Assume that k corresponds to register $s0, n corresponds to register $s2 and the base of the array v is in $s1. What is the MIPS
BlackZzzverrR [31]

Answer:

hello your question lacks the C segment so here is the C segment

while ( k<n )

{v[k] = v[k+1];

     k = k+1; }

Answer : while:

   bge $s0, $s2, end   # while (k < n)

   addi $t0, $s0, 1    # $t0 = k+1

   sll $t0, $t0, 2     # making k+1 indexable

   add $t0, $t0, $s1   # $t0 = &v[k+1]

   lw $t0, 0($t0)      # $t0 = v[k+1]

   sll $t1, $s0, 2     # making k indexable

   add $t1, $t1, $s1   # $t1 = &v[k]

   sw $t0, 0($t1)      # v[k] = v[k+1]

   addi $s0, $s0, 1

   j while

end:

Explanation:

The MIPS assembly code corresponding to the C segment is

while:

   bge $s0, $s2, end   # while (k < n)

   addi $t0, $s0, 1    # $t0 = k+1

   sll $t0, $t0, 2     # making k+1 indexable

   add $t0, $t0, $s1   # $t0 = &v[k+1]

   lw $t0, 0($t0)      # $t0 = v[k+1]

   sll $t1, $s0, 2     # making k indexable

   add $t1, $t1, $s1   # $t1 = &v[k]

   sw $t0, 0($t1)      # v[k] = v[k+1]

   addi $s0, $s0, 1

   j while

end:

4 0
2 years ago
Simon wants to use an invoice template created by Office.com. The first step after selecting the File tab is to select
wlad13 [49]
The type of file which can be PNG, Jpg, etc.
4 0
2 years ago
python Write a class named Taxicab that has three **private** data members: one that holds the current x-coordinate, one that ho
Blizzard [7]

Answer:

see explaination

Explanation:

class Taxicab():

def __init__(self, x, y):

self.x_coordinate = x

self.y_coordinate = y

self.odometer = 0

def get_x_coord(self):

return self.x_coordinate

def get_y_coord(self):

return self.y_coordinate

def get_odometer(self):

return self.odometer

def move_x(self, distance):

self.x_coordinate += distance

# add the absolute distance to odometer

self.odometer += abs(distance)

def move_y(self, distance):

self.y_coordinate += distance

# add the absolute distance to odometer

self.odometer += abs(distance)

cab = Taxicab(5,-8)

cab.move_x(3)

cab.move_y(-4)

cab.move_x(-1)

print(cab.odometer) # will print 8 3+4+1 = 8

5 0
2 years ago
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