Answer:
See explaination for the program code
Explanation:
code:
public static int[] countLastDigits(int[] list) {
int[] count = new int[10];
for (int i = 0; i < list.length; i++) {
int digit = list[i] % 10;
count[digit]++;
}
return count;
}
Option A because the environment should be selected for which the changes are to be applied. In a time Force IDE has many project environments for example maybe a java project and C++ project would be there on sandbox, so the environment selection is important.
Option B because the related changed sets should be specified so that other developers that have access to the project can see the changes being made.
Option D The data fields that are needed to be deployed should also be provided so that the updated version can be seen by other developers.
Rejected Options :
Option C user name and password has nothing to do with the production environment because if the user has it only then it can come and make changes.
Answer:
The working principle of the computer system. Computers do the work primarily in the machine and we can not see, a control center that converts the information data input to output. This control center, called the central processing unit (CPU), How Computers Work is a very complex system.
Explanation:
Answer:
See explaination
Explanation:
StackExample.java
public class StackExample<T> {
private final static int DEFAULT_CAPACITY = 100;
private int top;
private T[] stack = (T[])(new Object[DEFAULT_CAPACITY]);
/**
* Returns a reference to the element at the top of this stack.
* The element is not removed from the stack.
* atreturn element on top of stack
* atthrows EmptyCollectionException if stack is empty
*/
public T peek() throws EmptyCollectionException
{
if (isEmpty())
throw new EmptyCollectionException("stack");
return stack[top-1];
}
/**
* Returns true if this stack is empty and false otherwise.
* atreturn true if this stack is empty
*/
public boolean isEmpty()
{
return top < 0;
}
}
//please replace "at" with the at symbol
Note:
peek() method will always pick the first element from stack. While calling peek() method when stack is empty then it will throw stack underflow error. Since peek() method will always look for first element ffrom stack there is no chance for overflow of stack. So overflow error checking is not required. In above program we handled underflow error in peek() method by checking whether stack is an empty or not.
#include <stdio.h>
int main(void) {
// your code goes here
//unsigned a =float_times_four(0x80000000);
unsigned float_times_four(unsigned uf){
unsigned expn = (uf >> 23) & 0xFF;
printf(expn);
unsigned sign = uf & 0x80000000;
unsigned frac = uf & 0x007FFFFF;
if(expn == 255 ||(expn == 0 && frac ==0))
return uf;
if(expn){
expn<<2;
}else if(frac == 0x007FFFFF){
//here 0x7FFFFF given by you that is wrong you place this 0x007FFFFF will excute
frac>>2;
expn<<2;
}else{
frac<<=2;
}
return (sign) | (expn <<23) | (frac);
}
return 0;
}
