Answer:
// here is code in Java.
// package
import java.util.*;
// class definition
class Main
{
// method that return sum of two sale value
public static int Add(int euroSales,int asiaSales)
{
// return the sum
return euroSales+asiaSales;
}
//main method of the class
public static void main (String[] args) throws java.lang.Exception
{
try{
// variables
int euroSales=100;
int asiaSales=150;
int eurasiaSales;
// call the function
eurasiaSales=Add(euroSales,asiaSales);
// print the sum
System.out.println("total sale is:"+eurasiaSales);
}catch(Exception ex){
return;}
}
}
Explanation:
Declare and initialize two variables "euroSales=100" and "asiaSales=150". Declare another variable eurasiaSales. Call the method Add() with euroSales and asiaSales as parameter. This method will add both the value and return the sum.This sum will be assigned to variable eurasiaSales.Then print the sum.
Output:
total sale is:250
Answer:
Option a: a sorted array
Explanation:
Since the expectation on the data structure never need to add or delete items, a sorted array is the most desirable option. An array is known for its difficulty to modify the size (either by adding item or removing item). However, this disadvantage would no longer be a concern for this task. This is also the reason, linked list, binary search tree and queue is not a better option here although they offer much greater efficiency to add and remove item from collection.
On another hand, any existing items from the sorted array can be easily retrieved using address indexing and therefore the data query process can be very fast and efficient.
Answer: Virtual Organisations
Explanation: Virtual Organisations are Organisations that do not have any physical presence (brick and mortar). They exist in Internet platforms, social media and are known through the use telecommunications systems and facilities. This type of organisations continously conduct their businesses and liaise with their customers only through virtual Communication platforms like the computer Communication systems.
Answer:
public class GetInfo{
Beverage[] beverages=new Beverage[100];
int i=0;
GetInfo(Beverage b){
beverages[i]=b;
i++;
}
public void Display(){
for(int i=0;i<beverages.length;i++)
cout<<beverage[i].tostring();
}
Explanation:
we are taking Beverages array to store all values and in constructor we are adding that to the list and Display() function prints the vale
