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sergey [27]
2 years ago
12

Write a program that generates 1,000 random integers between 0 and 9 and displays the count for each number. (Hint: Use a list o

f ten integers, say counts, to store the counts for the number of 0s, 1s, ..., 9s.)
Computers and Technology
1 answer:
masya89 [10]2 years ago
5 0

Answer:

import random

count0, count1, count2, count3,

count4, count5, count6, count7,

count8, count9, i = [0 for _ in range(11)]

while i < 1000:

   number = random.randint(0,9)

   if number == 0:

       count0 = count0 + 1

   if number == 1:

       count1 = count1 + 1

   if number == 2:

       count2 = count2 + 1

   if number == 3:

       count3 = count3 + 1

   if number == 4:

       count4 = count4 + 1

   if number == 0:

       count5 = count5 + 1

   if number == 6:

       count6 = count6 + 1

   if number == 7:

       count7 = count7 + 1

   if number == 0:

       count8 = count8 + 1

   if number == 9:

       count9 = count9 + 1

   

   i = i+1

print("0's: "+ str(count0) + "\n"+ "1's: "+ str(count1) + "\n"+

"2's: "+ str(count2) + "\n"+ "3's: "+ str(count3) + "\n"+

"4's: "+ str(count4) + "\n"+ "5's: "+ str(count5) + "\n"+

"6's: "+ str(count6) + "\n"+ "7's: "+ str(count7) + "\n"+

"8's: "+ str(count8) + "\n"+ "9's: "+ str(count9) + "\n")

Explanation:

- Initialize variables to hold the count for each number

- Initialize <em>i</em> to control the while loop

- Inside the while loop, check for the numbers and increment the count values when matched.

- Print the result

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Define a function PyramidVolume with double parameters baseLength, baseWidth, and pyramidHeight, that returns as a double the vo
posledela

Answer:

The Program to this question can be given as:

Program:

#include <iostream> //header file.

using namespace std;

double PyramidVolume(double baseLength, double baseWidth, double pyramidHeight)  //define a method PyramidVolume

{

   double baseArea,Volume; //declare variable.

   baseArea= baseLength * baseWidth;  //calculate baseArea

   Volume = ((baseArea * pyramidHeight) * 1/3);  //calculate Volume

   return Volume; //return Volume

}

int main() //define main method.

{

double x,baseLength,baseWidth,pyramidHeight; //define variable.

cout<<"Enter baseLength :"; //message.

cin>>baseLength; //input value.

cout<<"Enter baseWidth :";//message.

cin>>baseWidth;  //input value.

cout<<"Enter pyramidHeight :";//message.

cin>>pyramidHeight;  //input value.

x=PyramidVolume(baseLength,baseWidth,pyramidHeight); //calling

cout << "Volume of given value is :"<<x; //print value.

return 0;

}

Output:

Enter baseLength :1.0

Enter baseWidth :1.0

Enter pyramidHeight :1.0

Volume of given value is :0.333333

Explanation:

The description of the above program can be given as:

  • In the above c++ language program firstly we include the header file. Then we define a function that is " PyramidVolume". The return type of this function is double because it return value and in this function, we pass three-parameter that is baseLength, baseWidth, and pyramidHeight. The data type of this variable is double.
  • In this function, we define two variable that is "baseArea and Volume" that is used for holding the calculated value. The variable baseArea holds the area of the pyramid and the volume variable holds the volume of the pyramid.
  • Then we define a main function. In this function, we define four variables that is "x, baseLength, baseWidth, and pyramidHeight". The baseLength, baseWidth, and pyramidHeight variable are used to take input from the user and pass into the function. The variable x is used to hold the return value of the function and we print this variable.

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A colleague sent you an awesome article about using proper ergonomics while sitting at the computer. You don't have time to read
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Answer: Select the article attachment and save it to your computer.

Explanation:

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2 years ago
Given three dictionaries, associated with the variables, canadian_capitals, mexican_capitals, and us_capitals, that map province
Nookie1986 [14]

Answer:

The Python code to combine the three dictionaries are is given as follows:

  1. canadian_capital = {
  2.    cash: "SOME VALUES",
  3.    assets: "SOME VALUES"
  4. }
  5. mexican_capital = {
  6.    cash: "SOME VALUES",
  7.    assets: "SOME VALUES"
  8. }
  9. us_capital = {
  10.    cash: "SOME VALUES",
  11.    assets: "SOME VALUES"
  12. }
  13. nafta_capital = {
  14.    canadian: canadian_capital,
  15.    mexican : mexican_capital,
  16.    us: us_capital
  17. }

Explanation:

<u>Line 1 - 14 :</u>

Create three Python dictionaries and name them as <em>canadian_capitals, mexican_capital </em>and<em> us_capitals</em>. Please note a Python dictionaries should be enclosed in curly braces { }.  

We just define two samples of relevant keys (<em>cash </em>and <em>asset</em>) in each of the dictionaries. Python dictionary can map a key to a value.

Since we are not given any capital values from the question,  a dummy string "<em>SOME VALUES</em>" is tentatively set as the value for each of the keys.

In practice, we should replace those dummy strings with the real values of capital. The values can be a number, a string, a list and even a nested dictionary.

<u>Line 16 - 20 : </u>

Create one more Python dictionary and name it as <em>nafta_capital</em>.

Since our aim is to combine the three previous dictionaries (<em>canadian_capitals, mexican_capital </em>and <em>us_capitals</em>) and associate it with <em>nafta_capital</em>, we can define three different keys (<em>canadian, mexican </em>and <em>us</em>) in our dictionary nafta_capital.

As mentioned, a value associated with a key can be a nested dictionary. Hence, we just map <em>canadian_capitals, mexican_capital </em>and <em>us_capitals</em> as the value of the keys (<em>canadian, mexican </em>and<em> us</em>) in dictionary<em> nafta_capital,</em> respectively,

By doing so, we have managed to combine three target dictionaries (<em>canadian_capitals, mexican_capital </em>and <em>us_capitals</em> ) into a single dictionary, <em>nafta_capital</em>.

4 0
2 years ago
Replace any alphabetic character with '_' in 2-character string passCode. Ex: If passCode is "9a", output is: 9_
oksian1 [2.3K]

Answer:

if(isalpha(passCode[0]))

{

passCode[0] = '_';

}

if(isalpha(passCode[1]))

{

passCode[1] = '_';  

}

         

Explanation:

The first if statement uses isalpha() function which checks if the character passed in this function is an alphabet. If the character stored in 0-th position (which is the first position whose index is 0) of the variable passCode is an alphabet then it is replaced with the '_'

The next if statement checks if the second character in the passCode variable is an alphabet. This means the function isalpha() checks if the character stored in second position (index 1) of the variable passCode is an alphabet then it is replaced with the '_'

The  complete activity with this chunk of code added and the output is attached in a screen shot.

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