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VLD [36.1K]
1 year ago
11

One of the most toxic components of a computer is the

Computers and Technology
1 answer:
Cloud [144]1 year ago
6 0
The most common is usually lead found in the glass or some circuits in rare cases
You might be interested in
Which command suppresses the visibility of a particular Row or column in a worksheet?
leonid [27]

Answer:

Ctrl+Space is the keyboard shortcut to select an entire column.

Explanation:

When you press the Shift+Space shortcut the first time it will select the entire row within the Table.  Press Shift+Space a second time and it will select the entire row in the worksheet.

The same works for columns.  Ctrl+Space will select the column of data in the Table.  Pressing the keyboard shortcut a second time will include the column header of the Table in the selection.  Pressing Ctrl+Space a third time will select the entire column in the worksheet.

You can select multiple rows or columns by holding Shift and pressing the Arrow Keys multiple times.

4 0
1 year ago
A painting company has determined that for every 115 square feet or wall space, one gallon of paint and eight hours of labor wil
Kay [80]

The program to calculate the total paint cost and other values is given below.

#include <iostream>

using namespace std;

int main() {  

 int rooms, laborChrg = 18;

 float paintChrg;

 float feetPerRoom[rooms];  

 float paintReq, laborHrs, paintCost, laborCost, totalCost, totalsqft=0;  

 cout<<"Enter the number of rooms to be painted "<<endl;

 cin>>rooms;  

 for(int i=0; i <= rooms; i++)

 {

 cout<<"Enter the square feet in room "<<endl;

 cin>>feetPerRoom[i];  

 // shortcut operator which is equivalent to totalsqft = totalsqft +     feetPerRoom[i];

 totalsqft += feetPerRoom[i];

 }  

 cout<<"Enter the cost of the paint per gallon "<<endl;

 cin>>paintChrg;  

 laborHrs = (totalsqft/115)*8;

 laborCost = laborHrs * laborChrg;  

 paintReq = totalsqft/115;

 paintCost = paintReq * paintChrg;  

 totalCost = laborCost + paintCost;  

 cout<<"The number of gallons of paint required "<<paintReq<<endl;

 cout<<"The hours of labor required "<<laborHrs<<endl;

 cout<<"The cost of the paint is "<<paintCost<<endl;

 cout<<"The labor charges are "<<laborHrs<<endl;

 cout<<"The Total cost of the paint job is "<<totalCost<<endl;  

 return 0;

}

Explanation:

The header files for input and output are imported.

#include <iostream>

using namespace std;

All the variables are taken as float except labour charge per hour and number of rooms.

The user is asked to input the number of rooms to be painted. An array holds the square feet in each room to be painted.

cout<<"Enter the number of rooms to be painted "<<endl;

cin>>rooms;  

for(int i=0; i <= rooms; i++)

{

cout<<"Enter the square feet in room "<<endl;

cin>>feetPerRoom[i];  

totalsqft += feetPerRoom[i];

}  

The above code asks for square feet in each room and calculates the total square feet to be painted simultaneously.

All the data to be displayed is calculated based on the values of labor charge per hour and gallons of paint needed, given in the question.

laborHrs = (totalsqft/115)*8;

laborCost = laborHrs * laborChrg;

paintReq = totalsqft/115;

paintCost = paintReq * paintChrg;

totalCost = laborCost + paintCost;

All the calculated values are displayed in the mentioned order.

7 0
2 years ago
BlockPy: #35.2) Animal Splits Write a function all_cats that consumes a comma-separated string of animals and prints whether all
maks197457 [2]

Answer:

def all_cats(data):

 dataArray = data.split(',')

 if(data==""):

   return True

 for i in dataArray:

   if('cat' not in i):

     return False

 

 return True

print(all_cats("gerbil,catfish,dog,cat"))

print(all_cats("cat,catfish"))

print(all_cats(""))

Explanation:

Step 1: define de function and the parameters

def all_cats(data):

Step 2: split the data by ,

dataArray = data.split(',')

Step 3 : validate if is an empty data and return true

if(data==""):

   return True

Step 4: Loop over de array data and validate if have cat in each data if not, then return false

for i in dataArray:

   if('cat' not in i):

     return False

Step 5 if have cat in each one return true

return True

Step 6 Validate with examples

print(all_cats("gerbil,catfish,dog,cat"))

print(all_cats("cat,catfish"))

print(all_cats(""))

6 0
1 year ago
A time-saving strategy that helps define unfamiliar words involves using
yuradex [85]

The correct answer is A. Familiar words for clues

Explanation:

Finding unfamiliar words is common while reading, especially in texts that belong to a specific field such as medicine, technology, etc. This can be handled through multiple strategies such as using a dictionary, guessing the meaning of the word based on its parts, and using context clues.

In this context, one of the easiest and most time-saving strategy is the use of context clues that implies using the familiar words as clues to guess the meaning of an unfamiliar word. This is effective because in most cases the meaning of an unknown word can be determined using the context of the word or words around the unknown word. Also, this strategy takes little time because you only need to analyze the sentence or paragraph where the unknown word is. Thus, the time-saving strategy to define unfamiliar words involves using familiar words for clues.

6 0
1 year ago
Read 2 more answers
Kayle is building a web form. He has included space where users can input their phone numbers and email addresses. However, he w
Digiron [165]

Answer:

D. javascript

Explanation:

use form validation method bro

8 0
1 year ago
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