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Vinvika [58]
1 year ago
9

A workgroup database is a(n) _____ database

Computers and Technology
1 answer:
Step2247 [10]1 year ago
8 0
It is a shared database
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What is one major structural difference between a decision structure (such as a decoder) and a storage structure (such as an RS
Andrej [43]

Answer:

B. The storage structure requires a clock input.

Explanation:

Logic circuits are circuits in electronics that give output based on the logic gate principle and its inputs. It can be a sequential logic circuit or a combinational logic circuit.

Decoders RS latches are combinational logic circuits because they both comprise of a combination of several sequential circuits to make their systems. The difference between decoders and RS latches is that the RS is a storage structure which is made up of flip-flops which require a clock input

8 0
1 year ago
To keep from overwriting existing fields with your Lookup you can use the ____________ clause.
Radda [10]
I believe the answer is <span>outputnew
</span>The main difference between the output new and the output is that outputnew won't overrite the alredy existing description field.
If you don't put this clause, <span>Splunk would adds all the field names and values to your events by through the lookup.</span>
3 0
1 year ago
Read 2 more answers
Describe how computers are used to access, retrieve, organize, process, maintain, interpret, and evaluate data and information.
Sonja [21]

Information refers to the meaningful output obtained after processing the data. Data processing therefore refers to the process of transforming raw data into meaningful output i.e. information.Mechanically using simple devices like typewriters or electronically using modern data processing tools such as computers.

8 0
1 year ago
Although the optical discs are all 5 ¼”, a CD drive can not read a DVD disc, and a DVD drive can not read a Blu-ray disc. Why no
otez555 [7]

Answer:

For storing the data into a CD, we need to burn it. And the surface of the CD is comprised of the polycarbonate layer that is molded as the spiral tracks over the surface of the CD. And the Data is being stored as a sequence of minute grooves that are called the pits which are encoded on the spiral tracks. And the region in between the pits is known as lands.

The DVD or the digital video dos is based on the optical data storage which is almost the same as the CD. The analog data is transformed into the digital data, and this is encoded on the disc starting from the inside edge, and towards out. This digital information is being encoded into the surface as pits, and the surface acts as the recording layer. A DVD can hold data up to 4.77 to 8 GB.

Since DVD size is bigger than CD, A DVD drive can read CD, but the CD drive cannot read the DVD,

And unlike the above two, which make use of the red laser for reading and writing, the blu ray makes use of the blue laser. Also, it has the smaller pits, tiny beam as well as small track that together make it possible to store around 25 GB of data in one single blue ray disc. And this is five times more than the size of a DVD.  

The Blu ray Discs are good for playing the CD as well as DVD. However, the opposite is not possible due to the size.

Explanation:

Please check the answer section.

4 0
2 years ago
Driving is expensive. Write a program with a car's miles/gallon and gas dollars/gallon (both doubles) as input, and output the g
I am Lyosha [343]

Answer:

#program in Python.

#function to calculate driving cost

def driving_cost(d_miles, m_per_gallon, doll_per_gallon):

   #calculate cost and return the value

   return (d_miles / m_per_gallon) * doll_per_gallon

#read the miles per gallon  

m_per_gallon = float(input("Enter car's miles/gallon:"))

#read dollars per gallon

doll_per_gallon = float(input("Enter gas dollars/gallon:"))

#call function to find cost for 10 miles

print('%0.2f' % driving_cost(10, m_per_gallon, doll_per_gallon))

#call function to find cost for 50 miles

print('%0.2f' % driving_cost(50, m_per_gallon, doll_per_gallon))

#call function to find cost for 400 miles

print('%0.2f' % driving_cost(400, m_per_gallon, doll_per_gallon))

Explanation:

Read the value of miles per gallon and assign it to variable "m_per_gallon". Then read dollars per gallon from user and assign it to variable "doll_per_gallon". Call the function driving_cost() with parameter miles, m_per_gallon and doll_per_gallon. This function will find the cost of driving and return the cost.Call function for  10, 50 and 400 miles.

Output:

Enter car's miles/gallon:20                                                                                                

Enter gas dollars/gallon:3.1599                                                                                            

1.58                                                                                                                      

7.90                                                                                                                      

63.20

5 0
1 year ago
Read 2 more answers
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