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Marina CMI [18]
3 years ago
13

1.1.5 practice: analyzing business culture

Computers and Technology
1 answer:
USPshnik [31]3 years ago
3 0

Answer:

 

A positive culture is an advantage when changes need to be made in the company. Making organisational changes and maintaining a positive culture a mutually complementary rather than mutually exclusive.

In a positive culture environment, people are happy and feel valued. When people feel happy and valued, it makes it easy for management to garner their buy-in cooperation when changes need to be made within the business.

In a culture that is negative, people don't feel valued and as such are always after their own interest rather than that of the company. There is also a tendency to always be on the defensive side of any change that is about to come looking out for one's self rather than what is best for the collective good. In this case, staff are much likely to sabotage new initiatives and changes rather than work to actuate them.

The obverse is true for a business with a positive culture.

Cheers!

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Which of the following describes ETL? a) A process that transforms information using a common set of enterprise definitions b) A
andrezito [222]

Answer:

The correct answer is d) All of these are correct.

Explanation:

ETL stands for Extract, Transform and Load. An ETL system extracts data from the sources, enforces data quality and consistency standards, conforms data so that separated and maybe unrelated sources can be used together, and as a final step delivers data in presentation-ready formats so that developers can build applications and end users can take decisions.

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XYZ Corp.’s facilities in Nashua, New Hampshire, are two office buildings 400 feet apart, each with its own LAN. To connect the
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Answer:

a: Twisted pair won't span a 400-foot distance.

Explanation:

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Hence option (a) is the correct reason for installing an optic fiber cable rather than a twisted pair cable.

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Accenture has partnered with a global construction company that specializes in building skyscrapers. The company wants better ma
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C++
nikitadnepr [17]

Answer:

Check the explanation

Explanation:

<u>The Code</u>

#include <fstream>

#include <iostream>

#include <cmath>

#include <cstring>

#include <cstdlib>

#include <ctime>

using namespace std;

//Function Declarations

void fillArrayWithRandNos(int nos[],int size);

void displayArray(int nos[],int size);

double mean(int nos[],int size);

double variance(int nos[],int size);

double median(int nos[],int size);

int mode(int nos[],int size);

void histogram(int nos[],int size);

int main() {

  //Declaring variables

const int size=100;

srand(time(NULL));

 

// Creating array dynamically

int* nos = new int[size];

 

//Calling the functions

fillArrayWithRandNos(nos,size);

displayArray(nos,size);

cout<<"Mean :"<<mean(nos,size)<<endl;

cout<<"variance :"<<variance(nos,size)<<endl;

cout<<"Median :"<<median(nos,size)<<endl;

cout<<"Mode :"<<mode(nos,size)<<endl;

histogram(nos,size);

 

  return 0;

}

void fillArrayWithRandNos(int nos[],int size)

{

  for(int i=0;i<size;i++)

  {

      nos[i]=rand()%(45) + 55;

  }

}

void displayArray(int nos[],int size)

{

  cout<<"Displaying the array elements :"<<endl;

  for(int i=0;i<size;i++)

  {

      cout<<nos[i]<<" ";

      if((i+1)%10==0)

      cout<<endl;

  }

}

double mean(int nos[],int size)

{

  double sum=0;

  for(int i=0;i<size;i++)

  {

      sum+=nos[i];

  }

  return sum/size;

}

double variance(int nos[],int size)

{

  double avg=mean(nos,size);

 

double variance,sum=0;

for(int i=0;i<size;i++)

{

sum+=pow(nos[i]-avg,2);

}

//calculating the standard deviation of nos[] array

variance=(double)sum/(size);

return variance;

}

double median(int nos[],int size)

{

      //This Logic will Sort the Array of elements in Ascending order

  int temp;

  for (int i = 0; i < size; i++)

{

for (int j = i + 1; j < size; j++)

{

if (nos[i] > nos[j])

{

temp = nos[i];

nos[i] = nos[j];

nos[j] = temp;

}

}

}

 

int middle;

float med;

middle = (size / 2.0);

if (size % 2 == 0)

med = ((nos[middle - 1]) + (nos[middle])) / 2.0;

else

med = (nos[middle]);

return med;

}

int mode(int nos[],int size)

{

  int counter1 = 0, counter2, modevalue;

for (int i = 0; i < size; i++) {

counter2 = 0;

for (int j = i; j < size; j++) {

if (nos[i] == nos[j]) {

counter2++;

}

if (counter2 > counter1) {

counter1 = counter2;

modevalue = nos[i];

}

}

}

if (counter1 > 1)

return modevalue;

else

return 0;

}

void histogram(int nos[],int size)

{

  int hist[9]={0};

  for(int i=0;i<size;i++)

  {

      if(nos[i]>=55 && nos[i]<=59)

      {

      hist[0]++;

      }

      else if(nos[i]>=60 && nos[i]<=64)

      {

      hist[1]++;

      }

      else if(nos[i]>=65 && nos[i]<=69)

      {

      hist[2]++;

      }

      else if(nos[i]>=70 && nos[i]<=74)

      {

      hist[3]++;

      }

      else if(nos[i]>=75 && nos[i]<=79)

      {

      hist[4]++;

      }

      else if(nos[i]>=80 && nos[i]<=84)

      {

      hist[5]++;

      }

      else if(nos[i]>=85 && nos[i]<=89)

      {

      hist[6]++;

      }

      else if(nos[i]>=90 && nos[i]<=94)

      {

      hist[7]++;

      }

      else if(nos[i]>=95 && nos[i]<=99)

      {

      hist[8]++;

      }

  }

     

  cout<<"Displaying the count of numbers in each interval:"<<endl;

 

      int cnt=0;

  for(int i=55;i<=99;i+=5)

  {

  cout<<i<<"-"<<i+4<<"|"<<hist[cnt]<<endl;

 

      cnt++;

  }

 

  cout<<"Displaying the histogram :"<<endl;

  cnt=0;

  for(int i=55;i<=99;i+=5)

  {

  cout<<i<<"-"<<i+4<<"|";

  for(int j=0;j<hist[cnt];j++)

  {

      cout<<"*";

  }  

      cout<<endl;

      cnt++;

  }          

     

 

 

}

#########

___________________________

The output can be seen in the attached image below.

8 0
2 years ago
Write a function that computes the average and standard deviation of four scores. The standard deviation is defined to be the sq
ZanzabumX [31]

Answer:

#include<iostream>

#include<cmath>

using namespace std;

double calAvg(double s1, double s2,double s3, double s4);

double calStandardDeviation(double s1, double s2,double s3, double s4,double average,int n);

void main()

{

 double s1,s2,s3,s4;

double avg,StandardDeviation;

char option;

   do

{

 cout<<"Enter s1:";

 cin>>s1;

 cout<<"Enter s2:";

 cin>>s2;

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         cin>>option;

}

       while (option='y');

}

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sd=sqrt(sd);

return sd;

}

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