Answer:
sidebar
Explanation:
The part of the webpage that is being described in this question is known as a sidebar. These are the far left/right sides of the webpage and are usually used for networking feeds, ads, related information, major points of the main page, biographical info, as well as persuasive information. This section of the webpage serves two main purposes to provide the viewer with advertisements and to encourage the reader to read the more detailed main article.
Answer:
"public static void passAList(ArrayList<Integer> myList, int[] intArr)", is the correct answer for the above question.
Explanation:
Missing information :
- The option is missing but the question states "choose from the following". The correct defining syntax is defined above.
Detailed Explantion :
- The above question asked about syntax which takes the value of list and array as an argument.
- It is already defined in the above syntax.
- And the value is passed by the user at the time of function call.
- The array list is defined by the help of the ArrayList class and the array is defined by the help of the "[]" symbol.
Answer:
The answer is "Using the DoD 5220.22-M method and Degauss media with a magnet".
Explanation:
The "DoD Standard" is a term used during the data sanitizing industry and refers to DoD 5220.22-M. The simplest ways are being used to help eliminate the previously stored data, by deleting hard disc storage facilities with the same data wherever that used a sequence of all zeros.
The sparging eliminates statistics to entirely delete the gravitational flux from electronic media. Hard drives as well as other data storage devices, for example, computer tapes, retain magnetic data. It could no longer be seen as storage after a disk is degaussed.
Answer:
// here is code in C++
#include <bits/stdc++.h>
using namespace std;
// main function
int main()
{
// variables
int n,no_open=0;
cout<<"enter the number of lockers:";
// read the number of lockers
cin>>n;
// initialize all lockers with 0, 0 for locked and 1 for open
int lock[n]={};
// toggle the locks
// in each pass toggle every ith lock
// if open close it and vice versa
for(int i=1;i<=n;i++)
{
for(int a=0;a<n;a++)
{
if((a+1)%i==0)
{
if(lock[a]==0)
lock[a]=1;
else if(lock[a]==1)
lock[a]=0;
}
}
}
cout<<"After last pass status of all locks:"<<endl;
// print the status of all locks
for(int x=0;x<n;x++)
{
if(lock[x]==0)
{
cout<<"lock "<<x+1<<" is close."<<endl;
}
else if(lock[x]==1)
{
cout<<"lock "<<x+1<<" is open."<<endl;
// count the open locks
no_open++;
}
}
// print the open locks
cout<<"total open locks are :"<<no_open<<endl;
return 0;
}
Explanation:
First read the number of lockers from user.Create an array of size n, and make all the locks closed.Then run a for loop to toggle locks.In pass i, toggle every ith lock.If lock is open then close it and vice versa.After the last pass print the status of each lock and print count of open locks.
Output:
enter the number of lockers:9
After last pass status of all locks:
lock 1 is open.
lock 2 is close.
lock 3 is close.
lock 4 is open.
lock 5 is close.
lock 6 is close.
lock 7 is close.
lock 8 is close.
lock 9 is open.
total open locks are :3
I think it’s cropping could be wrong though
