import java.util.Scanner;
public class U2_L3_Activity_Four {
public static void main(String[] args) {
Scanner scan = new Scanner(System.in);
System.out.println("Enter a sentence.");
String sent = scan.nextLine();
int count = 0;
for (int i = 0; i < sent.length(); i++){
char c = sent.charAt(i);
if (c != ' '){
count++;
}
else{
break;
}
}
System.out.println("The first word is " + count +" letters long");
}
}
We check to see when the first space occurs in our string and we add one to our count variable for every letter before that. I hope this helps!
Answer:
The RAM Modules.
Explanation:
If the power supply is working properly, the next thing that could cause an auto-shutdown could be the RAM.
Sometimes static electricity, a faulty slot, or even a faulty memory module could be causing the RAM to fail. And as the OS needs to read from the RAM in order to boot, at the moment the processor can't find the RAM information, it shuts down the system.
Changing the RAM modules to a different slot, switching slots, or cleaning the memory module pins with a regular eraser can help solve the problem. If not, then Lin might need to buy a new module, or keep going forward with the diagnostic process.
I am not sure but i think it is 2 or 4 because a pc can withstand the power of volts, drive, ram, and data
Answer:
Option (B) is the correct answer of this question.
Explanation:
Packet analyzer is a software application or set of infrastructure capable of unencrypted and recording communication that travels through a virtual system of a computer system.A packet analyzer used to detect network activity is recognized as a broadband monitoring system.
A packet analyzer is a code application that is used for monitoring, intercepting, and recording http requests with the help of a virtual interface.
Other options are incorrect because they are not related to the given scenario.
Answer:
I get 0x55 and this the linking address of the main function.
use this function to see changes:
/* bar6.c */
#include <stdio.h>
char main1;
void p2()
{
printf("0x%X\n", main1);
}
Output is probably 0x0
you can use your original bar6.c with updaated foo.c
char main;
int main() // error because main is already declared
{
p2();
//printf("Main address is 0x%x\n",main);
return 0;
}
Will give u an error
again
int main()
{
char ch = main;
p2(); //some value
printf("Main address is 0x%x\n",main); //some 8 digit number not what printed in p2()
printf("Char value is 0x%x\n",ch); //last two digit of previous line output
return 0;
}
So the pain in P2() gets the linking address of the main function and it is different from address of the function main.
Now char main (uninitialized) in another compilation unit fools the compiler by memory-mapping a function pointer on a char directly, without any conversion: that's undefined behavior. Try char main=12; you'll get a multiply defined symbol main...
Explanation:
