#Write a function called string_finder. string_finder should #take two parameters: a target string and a search string. #The fun
ction will look for the search string within the #target string. # #The function should return a string representing where in #the target string the search string was found: # # - If search string is at the very beginning of target # string, then return "Beginning". For example: # string_finder("Georgia Tech", "Georgia") -> "Beginning" # # - If search string is at the very end of target string, # then return "End". For example: # string_finder("Georgia Tech", "Tech") -> "End" # # - If search string is in target string but not at the # very beginning or very end, then return "Middle. For # example: # string_finder("Georgia Tech", "gia") -> "Middle" # # - If search string is not in target string at all, then # return "Not found". For example: # string_finder("Georgia Tech", "Idaho") -> "Not found" # #Assume that we're only interested in the first instance #of the search string if it appears multiple times in the #target string, and that search string is definitely #shorter than target string. # #Hint: Don't be surprised if you find that the "End" case #is the toughest! You'll need to look at the lengths of #both the target string and the search string. #Write your function here!
1 answer:
Answer:
I am writing a Python program:
def string_finder(target,search): #function that takes two parameters i.e. target string and a search string
position=(target.find(search))# returns lowest index of search if it is found in target string
if position==0: # if value of position is 0 means lowers index
return "Beginning" #the search string in the beginning of target string
elif position== len(target) - len(search): #if position is equal to the difference between lengths of the target and search strings
return "End" # returns end
elif position > 0 and position < len(target) -1: #if value of position is greater than 0 and it is less than length of target -1
return "Middle" #returns middle
else: #if none of above conditions is true return not found
return "not found"
#you can add an elif condition instead of else for not found condition as:
#elif position==-1
#returns "not found"
#tests the data for the following cases
print(string_finder("Georgia Tech", "Georgia"))
print(string_finder("Georgia Tech", "gia"))
print(string_finder("Georgia Tech", "Tech"))
print(string_finder("Georgia Tech", "Idaho"))
Explanation:
The program can also be written in by using string methods.
def string_finder(target,search): #method definition that takes target string and string to be searched
if target.startswith(search): #startswith() method scans the target string and checks if the (substring) search is present at the start of target string
return "Beginning" #if above condition it true return Beginning
elif target.endswith(search): #endswith() method scans the target string and checks if the (substring) search is present at the end of target string
return "End" #if above elif condition it true return End
elif target.find(search) != -1: #find method returns -1 if the search string is not in target string so if find method does not return -1 then it means that the search string is within the target string and two above conditions evaluated to false so search string must be in the middle of target string
return "Middle" #if above elif condition it true return End
else: #if none of the above conditions is true then returns Not Found
return "Not Found"
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Answer:
Here is the corrected program:
import java.util.Scanner; //to accept input from user
public class 02_14_Activity_one { //class name
public static void main(String[] args) { //start of main method
Scanner scan = new Scanner(System.in); //creates Scanner class object
System.out.println("Enter first string"); //prompts user to enter first string
String s1 = scan.nextLine(); //reads input string from user
System.out.println("Enter second string"); //prompts user to enter second string
String s2 = scan.nextLine(); //reads second input string from user
System.out.println("Enter number of letters from each word"); //enter n
int n = scan.nextInt(); //reads value of integer n from user
System.out.println(s1.substring(0,n) + s2.substring(s2.length() - n ));
} } //uses substring method to print a string made up of the first n letters of s1 and the last n letters of s2.
Explanation:
The errors were:
1.
Scanner scan = Scanner(System.in);
Here new keyword is missing to create object scan of Scanner class.
Corrected statement:
Scanner scan = new Scanner(System.in);
2.
String s1 = nextLine();
Here object scan is missing to call nextLine() method of class Scanner
Corrected statement:
String s1 = scan.nextLine();
3.
String s2 = Scanner.nextLine();
Here class is used instead of its object scan to access the method nextLine
Corrected statement:
String s2 = scan.nextLine();
4.
String n = scan.nextLine();
Here n is of type String but n is a whole number so it should be of type int. Also the method nextInt will be used to scan and accept an integer value
Corrected statement:
int n = scan.nextInt();
5.
System.out.println(s1.substring(1,n-1) + s2.substring(s1.length()-n));
This statement is also not correct
Corrected statement:
System.out.println(s1.substring(0,n) + s2.substring(s2.length() - n ));
This works as follows:
s1.substring(0,n) uses substring method to return a new string that is a substring of this s1. The substring begins at the 0th index of s1 and extends to the character at index n.
s2.substring(s2.length() - n ) uses substring method to return a new string that is a substring of this s2. The substring then uses length() method to get the length of s2 and subtracts integer n from it and thus returns the last n characters of s2.
The screenshot of program along with its output is attached.
