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pychu [463]
2 years ago
12

Reputable firms often ask recent graduates to pay an up-front fee for a job.

Computers and Technology
2 answers:
dolphi86 [110]2 years ago
6 0

Answer:

hi your question is not complete it think the complete question you are asking is

"do reputable firms often ask for recent graduates to pay an up-front fee for a job true or false"

the answer is FALSE

Explanation:

Reputable firms are firms that are very much accountable to their customers, the good cause of the company and as well to their shareholders (stake holders)  reputable firms care a lot about their public image and more especially how they conduct their services including recruitment as well. based on this definition reputable firms does not ask recent graduates to pay an up-front fee for a job.

non-reputable firms are mostly fraudulent firms with little or no regard for stakeholders or the good cause of the company they don't as well care about their public image

koban [17]2 years ago
5 0

Answer:

What is your question?

Explanation:

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If a user was complaining about a "slow computer" due to a program that uses a significant amount of memory, what part or parts
Sedaia [141]

Answer:

The Random-Access Memory (RAM) should be upgraded.

Explanation:

Since the particuar apllication is taking alot of memory space it means that an ugrade/ installation of a bigger RAM would help the system work better while using the program

6 0
1 year ago
Write a method called makeStars. The method receives an int parameter that is guaranteed not to be negative. The method returns
serious [3.7K]

Answer:

// import the Scanner class

// to allow the program receive user input

import java.util.Scanner;

// The class Solution is defined

public class Solution{

   // main method to begin program execution

   public static void main(String[] args) {

       // scanner object scan is declared

       Scanner scan = new Scanner(System.in);

       // Prompt the user to enter a number

       System.out.println("Enter the number of stars you want: ");

       // user input is assigned to numOfStar

       int numOfStar = scan.nextInt();

       // call the makeStars method

       makeStars(numOfStar);

   }

   

   // makeStars method print stars using recursion

   // the method call itself till starNum == 0

   public static void makeStars(int starNum){

       if (starNum != 0){

           System.out.print("*");

           makeStars(starNum -1);

       }

   }

}

Explanation:

The code is well comment and solve the problem using recursion.

6 0
2 years ago
B.) Define latency and jitter for service flow in a fixed wireless system.
yuradex [85]
The answer would be between the base station and the subscriber station.
7 0
2 years ago
Generating a signature with RSA alone on a long message would be too slow (presumably using cipher block chaining). Suppose we c
boyakko [2]

Answer:

Following are the algorithm to this question:

Explanation:

In the RSA algorithm can be defined as follows:  

In this algorithm, we select two separate prime numbers that are the "P and Q", To protection purposes, both p and q combines are supposed to become dynamically chosen but must be similar in scale but 'unique in length' so render it easier to influence. Its value can be found by the main analysis effectively.  

Computing N = PQ.  

In this, N can be used for key pair, that is public and private together as the unit and the Length was its key length, normally is spoken bits. Measure,

\lambda (N) = \ lcm( \lambda  (P), \lambda (Q)) = \ lcm(P- 1, Q - 1)  where \lambda is the total function of Carmichaels. It is a privately held value. Selecting the integer E to be relatively prime from 1and gcd(E,  \lambda (N) ) = 1; that is E \ \ and  \ \ \lambda (N).  D was its complex number equivalent to E (modulo \lambda (N) ); that is d was its design multiplicative equivalent of E-1.  

It's more evident as a fix for d provided of DE ≡ 1 (modulo \lambda (N) ).E with an automatic warning latitude or little mass of bigging contribute most frequently to 216 + 1 = 65,537 more qualified encrypted data.

In some situations it's was shown that far lower E values (such as 3) are less stable.  

E is eligible as a supporter of the public key.  

D is retained as the personal supporter of its key.  

Its digital signature was its module N and the assistance for the community (or authentication). Its secret key includes that modulus N and coded (or decoding) sponsor D, that must be kept private. P, Q, and \lambda (N) will also be confined as they can be used in measuring D. The Euler totient operates \varphi (N) = (P-1)(Q - 1) however, could even, as mentioned throughout the initial RSA paper, have been used to compute the private exponent D rather than λ(N).

It applies because \varphi (N), which can always be split into  \lambda (N), and thus any D satisfying DE ≡ 1, it can also satisfy (mod  \lambda (N)). It works because \varphi (N), will always be divided by \varphi (N),. That d issue, in this case, measurement provides a result which is larger than necessary (i.e. D >   \lambda (N) ) for time - to - time). Many RSA frameworks assume notation are generated either by methodology, however, some concepts like fips, 186-4, may demand that D<   \lambda (N). if they use a private follower D, rather than by streamlined decoding method mostly based on a china rest theorem. Every sensitive "over-sized" exponential which does not cooperate may always be reduced to a shorter corresponding exponential by modulo  \lambda (N).

As there are common threads (P− 1) and (Q – 1) which are present throughout the N-1 = PQ-1 = (P -1)(Q - 1)+ (P-1) + (Q- 1)), it's also possible, if there are any, for all the common factors (P -1) \ \ \ and \ \ (Q - 1)to become very small, if necessary.  

Indication: Its original writers of RSA articles conduct their main age range by choosing E as a modular D-reverse (module \varphi (N)) multiplying. Because a low value (e.g. 65,537) is beneficial for E to improve the testing purpose, existing RSA implementation, such as PKCS#1, rather use E and compute D.

8 0
2 years ago
There are three seating categories at a stadium. Class A seats cost $20, Class B seats cost $15, and Class C seats cost $10. Wri
Westkost [7]

Answer:

Following are the program to this question:

def calculate_income(num,seat):#defining method calculate_income

   if seat=="A": #defining condition for seat a

       return num * 20 #return value

   if seat=="B": #defining condition for seat b

       return num * 15 #return value

   if seat=="C": #defining condition for seat c

       return num * 10 #return value

def show_income(a,b,c): #defining method show_Income

   sum=a+b+c # add total seats income

   print("Income for A class seats: $",a) #print value

   print("Income for B class seats: $",b) #print value

   print("Income for C class seats: $",c) #print value

   print("Total Income: $",sum) #print value

def main(): # defining main method

   a=int(input("Enter class A seats: ")) #input seats a value

   b=int(input("Enter class B seats: ")) #input seats b value

   c=int(input("Enter class C seats: ")) #input seats c value

   a_income=calculate_income(a,"A")  #call method for seat a

   b_income=calculate_income(b,"B") #call method for seat b

   c_income=calculate_income(c,"C") #call method for seat c

   show_income(a_income,b_income,c_income) # call method show_income for print all seat value

main()

Output:

Enter class A seats: 2

Enter class B seats: 3

Enter class C seats: 2

Income for A class seats: $ 40

Income for B class seats: $ 45

Income for C class seats: $ 20

Total Income: $ 105

Explanation:

The description of the above program can be described as follows:

  • In the above python program, three methods "calculate_income, show_income, and the main method" were defined.  
  • The method "calculate_income" accepts two-variable "num and seat" as the parameter, inside the method a three if block is used, that calculate all types of seat class rate and returns its value.
  • In the "show_income", we add all the seat value in the sum variable and use the print method, that prints all seat cost, and total cost.
  • In the main method, we input all seat value from user input and pass into the calculate_income method and collect all the return value, after calculating calculate_income we pass its return value into the show_income method, that prints all value.
5 0
2 years ago
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