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2 years ago

Using information from the lesson, explain how new technologies change your experience as a consumer.

2 answers:

6 0

Technological improvements allow me to have greater access to goods around the world. I can buy instantly and communicate instantly with producers. Technology can also help me to monitor economic trends, both in my country and in my own life. In summary, technology helps to give me more freedom to make economic choices.

On e2020

vagabundo [1.1K]2 years ago

4 0

Technological improvements allow me to have greater access to goods around the world. I can buy instantly and communicate instantly with producers. It allows us to be able to purchase something faster or maybe even cheaper. Instead of having to go out and buy something. But it also gives you more options then what you would have in a store. It makes it to where if you don't have time to go to the store, you can just pull out your phone and hit a button. Epically, if you have an amazon. You just half to search what you want, and when you find it, add it to chart or buy it with one click.

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In this problem we consider sending real-time voice from Host A to Host B over a packet-switched network (VoIP). Host A converts

Minchanka [31]

Answer:

The total time elapsed from the time a bit is created (from the original analog signal at Host A) until the bit is decoded (as part of the analog signal at Host B is 25.11 ms

Explanation:

Host A first converts the analog signal to a digital 64kbps stream and then groups it into 56-byte packets. The time taken for this can be calculated as:

time taken 1= $\frac{Packet Size in Bits}{Bit Rate}$

= (56 x 8) bits / 64 x 10³ bits/s

= 7 x 10⁻³s

time taken 1= 7 ms

The transmission rate of the packet from Host A to Host B is 4 Mbps. The time taken to transfer the packets can be calculated as:

time taken 2= (56 x 8) bits / 4 x 10⁶ bits/s

= 1.12 x 10⁻⁴ s

time taken 2= 112 μs

The propagation delay is 18 ms.

To calculate the total time elapsed, we need to add up all the time taken at each individual stage.

$Time_{total}$ = Time taken 1 + Time taken 2 + Propagation Delay

= 7 ms + 112 μs + 18 ms

= 0.025112 s

$Time_{total}$ = 25.11 ms

5 0

2 years ago

What does the following function return? void index_of_smallest(const double all, int startindex, int numberOfSlots); A. a doubl

Flauer [41]

Answer:

nothing

Explanation:

Because the return type of the function is void. void means does not return any thing.

The syntax of the function:

type name( argument_1, argument_2,......)

{

statement;

}

in the declaration the type define the return type of the function.

it can be int, float, double, char, void etc.

For example:

int count( int index);

the return type of above function is int. So, it return integer.

similarly,

void count(int index);

it return type is void. So, it does not return any thing.

7 0

2 years ago

Write a method called printRangeOfNumbers that accepts a minimum, maximum numbers as parameters and prints each number from mini

timama [110]

Answer:

The method in python is as follows:

class myClass:

def printRange(min,max):

for i in range(min, max+1):

print("{"+str(i)+"} ", end = '')

Explanation:

This line declares the class

class myClass:

This line defines the method

def printRange(min,max):

This line iterates from min to max

for i in range(min, max+1):

This line prints the output in its required format

print("{"+str(i)+"} ", end = '')

5 0

2 years ago

The __________ contains a list of all the resources owned by the library.

Ira Lisetskai [31]

The catalog contains a list of all the resources owned by the library.

- Mabel <3

5 0

2 years ago

Let S be the set of all strings from A* in which there is no b before an a. For example, the strings λ, aa, bbb, and aabbbb all

alexdok [17]

Answer:

Check the explanation

Explanation:

A recurvsive defintion for $A^{*}$ which contains all possible strings over the alphabet $A=\{a,b\}$ is \lambda\in $A^*$ (contains the null strings) and $A^{*}=\{uv:u\in A^*,v\in A\}$

A recurvsive defintion for $A^{+}$ which contains all possible strings over the alphabet $A=\{a,b\}$ is $a,b\in$ $A^+$ (contains the strings of lengths 1) and $A^{+}=\{uv:u\in A^+,v\in A\}$