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mart [117]
2 years ago
14

A signal travels from point A to point B. At point A, the signal power is 100 W. At point B, the power is 90 W. What is the atte

nuation in decibels?
Computers and Technology
1 answer:
11Alexandr11 [23.1K]2 years ago
7 0

Answer:

Attenuation = 0.458\ db

Explanation:

Given

Power at point A = 100W

Power at point B = 90W

Required

Determine the attenuation in decibels

Attenuation is calculated using the following formula

Attenuation = 10Log_{10}\frac{P_s}{P_d}

Where P_s = Power\ Input and P_d  = Power\ output

P_s = 100W

P_d = 90W

Substitute these values in the given formula

Attenuation = 10Log_{10}\frac{P_s}{P_d}

Attenuation = 10Log_{10}\frac{100}{90}

Attenuation = 10 * 0.04575749056

Attenuation = 0.4575749056

Attenuation = 0.458\ db <em>(Approximated)</em>

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       Counter counter2 = new Counter();

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}

class Counter{

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       return this.count;

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// reset method will set count to 0

   public void reset(){

       this.count = 0;

   }

}

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