Answer:
Calculate the average processing time of the new software
Explanation:
Since the average processing time of the old software is already known, the simplest test to see if the new software is faster than the old software will be to calculate the average processing time for the new software and compare it with the average processing time of the old software.
If the new software have an average processing time lower/smaller than that of the old software; we conclude that the new software is faster.
If the new software have an average processing time higher/larger than that of the old software; we conclude that the old software is faster.
Answer:
RAX = 333000h (16 bits with preceding zeros removed)
RDX = 20h (also 16 bits with preceding zeros removed)
Explanation:
The "div" opcode in the assembly language source code is used to divide operands. It accepts a divisor ( the denominator) and divides the content of the AX register. The result is saved in the AX register while the remainder (if any) is saved in the DX register. If the DX register holds any data, the data is replaced with the divisor remnant.
The code above divides the content of the RAX register with the divisor variable and saves the result and remainder in the RAX and RDX respectively.
<u>Answer:</u>
<em>1. The loop will run unless the value of answer equals to Capital N.</em> The method equals is “case-sensitive” that is lower case letter and upper case letters are considered different. That “a” and “A” means the same to us, but for the method equals it is different and equals method will return false if the case is not matching.
<em>2. a (int)(Math.random() * (upper − lower) ) + lower </em>
Since we need to consider the lower limit value together to get the desired results we need to add the value of lower limit to the multiplied answer.
<em>3. b while(userGuess != secretNumber || userGuess >= lowerLimit && userGuess <= upperLimit)</em>
Here the program is required to check the while loop and exit when user guess the number or we can say the loop should continue until the user guess the number, so that is why we have taken <em>userGuess!=secretNumber. </em>Next the loop should be exited if it is not within the range or we can say that the loop should run only if the guessed number is within the upper and lower limit.<em> That is why we have opted for the condition userGues>=lowerlimit && userGuess<=upperlimit.</em> Why we have taken && as the operator is that, it’s a range of values so && operator best suit for this kind of logical condition.
Well, CEOs are on the top of the food chain. It takes a lot of work and ambition to become one, and once they are one, <span>CEOs accept a huge amount of responsibility - that means having to take blame if things go wrong and </span><span>having more tasks to complete such as having to attend numerous meetings, make decisions. They are also on the board of directors.</span>
Assistants do not have to do as much, they likely won't have that much responsibility or experience, their tasks revolve around ensuring meetings are scheduled and performing other ad-hoc duties.
