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Salsk061 [2.6K]
2 years ago
11

given the numerical value 1010101.11, which of the following number systems is most likely represented.

Computers and Technology
1 answer:
nasty-shy [4]2 years ago
7 0

Answer:

u have to give me more points

Explanation:

sorry

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Write the 8-bit signed-magnitude, two's complement, and ones' complement representations for each decimal number: +25, + 120, +
pshichka [43]

Answer:

Let's convert the decimals into signed 8-bit binary numbers.

As we need to find the 8-bit magnitude, so write the powers at each bit.

      <u>Sign -bit</u> <u>64</u> <u>32</u> <u>16</u> <u>8</u> <u>4</u> <u>2</u> <u>1</u>

+25 - 0 0 0 1 1 0 0 1

+120- 0 1 1 1 1 0 0 0

+82 - 0 1 0 1 0 0 1       0

-42 - 1 0 1 0 1 0 1 0

-111 - 1 1 1 0 1 1 1 1

One’s Complements:  

+25 (00011001) – 11100110

+120(01111000) - 10000111

+82(01010010) - 10101101

-42(10101010) - 01010101

-111(11101111)- 00010000

Two’s Complements:  

+25 (00011001) – 11100110+1 = 11100111

+120(01111000) – 10000111+1 = 10001000

+82(01010010) – 10101101+1= 10101110

-42(10101010) – 01010101+1= 01010110

-111(11101111)- 00010000+1= 00010001

Explanation:

To find the 8-bit signed magnitude follow this process:

For +120

  • put 0 at Sign-bit as there is plus sign before 120.
  • Put 1 at the largest power of 2 near to 120 and less than 120, so put 1 at 64.
  • Subtract 64 from 120, i.e. 120-64 = 56.
  • Then put 1 at 32, as it is the nearest power of 2 of 56. Then 56-32=24.
  • Then put 1 at 16 and 24-16 = 8.
  • Now put 1 at 8. 8-8 = 0, so put 0 at all rest places.

To find one’s complement of a number 00011001, find 11111111 – 00011001 or put 0 in place each 1 and 1 in place of each 0., i.e., 11100110.

Now to find Two’s complement of a number, just do binary addition of the number with 1.

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else if operator is / do division of a and b and make answer c

else if operator is // do floor division of a and b and make answer c

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Write a program whose input is two integers and whose output is the two integers swapped. Place the values in an array, where x
Aliun [14]

Answer:

import java.util.Arrays;

public class swap{

   public static void main(String []args){

       int [] arr = {2,4};

       swapValues(arr);

   }

   public static void swapValues(int[] values){

       int temp;

       System.out.println(Arrays.toString(values));

       temp=values[0];

       values[0]=values[1];

       values[1] =temp;

       System.out.println(Arrays.toString(values));

   }

}

Explanation:

In the program above, we created the method swapValues that receives an array of integers as parameters. in the method definition, we created a temp variable that is used to swapp the element at index 0 and index 1. Java's Arrays.to string method is used to print the array before and after the swap.

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