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zepelin [54]
2 years ago
5

Which method allows a computer to react accordingly when it requests data from a server and the server takes too long to respond

?
(A) response timeout
(B) encapsulation
(C) flow control
(D) access method
Computers and Technology
1 answer:
Rina8888 [55]2 years ago
6 0

Answer:

A. Request timeout.

Explanation:

The end devices like the computer systems in a network seeks to share resources with one another and/ or request resources from central server.

With this, there are two ways computers in a network can communicate. They are peer to peer network communication and client-server network communication.

The client-server communication requires a dedicated central server where computers in the network require data. Peer to peer describes a network where computers serve as both client and server to each other.

Request timeout is a message sent to a source when the time to live period (TTL) of a packet expires.

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Use the single-server drive-up bank teller operation referred to in Problems 1 and 2 to determine the following operating charac
elena-s [515]

Answer:

This question is incomplete, here's the complete question:

1. Willow Brook National Bank operates a drive-up teller window that allows customers to complete bank transactions without getting out of their cars. On weekday mornings, arrivals to the drive-up teller window occur at random, with an arrival rate of 24 customers per hour or 0.4 customers per minute. 3. Use the single-server drive-up bank teller operation referred to in Problems 1 to determine the following operating characteristics for the system: a.) The probability that no customers are in the system. b.) The average number of customers waiting. c.) The average number of customers in the system. d.) The average time a customer spends waiting. e.) The average time a customer spends in the system. f.) The probability that arriving customers will have to wait for service.

Explanation:

Arrival rate \lambda = 24 customers per hour or 0.4 customers per minute

Service rate \mu​ = 36 customers per hour or 0.6 customers per minute (from problem 1)

a.) The probability that no customers are in the system , P0 = 1 - \lambda / \mu

= 1 - (24/36) = 1/3 = 0.3333

b.) The average number of customers waiting

Lq = \lambda^2 / [\mu(\mu - \lambda)] = 242 / [36 * (36 - 24)] = 1.33

c.) The average number of customers in the system.

L = Lq + \lambda / \mu = 1.33 + (24/36) = 2

d.) The average time a customer spends waiting.

Wq = \lambda / [\mu(\mu - \lambda)] = 24 / [36 * (36 - 24)] = 0.0555 hr = 3.33 min

e.) The average time a customer spends in the system

W = Wq + 1/\mu = 0.0555 + (1/36) = 0.0833 hr = 5 min

f.) The probability that arriving customers will have to wait for service.

= 1 - P0 = 1 - 0.3333 = 0.6667

3 0
2 years ago
RFID tags are used in secure environments primarily due to the fact they are impossible to counterfeit.
denis23 [38]

Answer: True

Explanation:

 Yes, the given statement is true that the RFID tags are basically used in the secure system because it is impossible to counterfeit.

RFID basically stand for the radio frequency identification that provide a method to retrieve the data or information quickly from the system. It basically used as radio wave technology in which we can easily track the objects and people by using proper programmed data.

The tag is basically placed in the object for unique identification. There are basically two types of tags in the RFID that is active and passive.

4 0
2 years ago
Consider a disk that rotates at 3600 rpm. The seek time to move the head between adjacent tracks is 2 ms. There are 32 sectors p
jasenka [17]

Answer:

19.71 ms

Explanation:

The disk rotates at 3600 rpm, hence the time for one revolution = 60 / 3600 rpm = 16.67 ms.

Hence time to read or write on a sector = time for one revolution / number of sectors per track = 16.67 ms / 32 sectors = 0.52 ms

Head movement time from track 8 to track  9 = seek time = 2 ms

rotation time to head up sector 1 on track 8 to sector 1 on track 9 = 16.67 * 31/32 = 16.15 ms

The total time = sector read time +head movement time + rotational delay + sector write time = 0.52 ms + 2 ms + 16.15 ms + 0.52 ms = 19.19 ms

3 0
2 years ago
Summary: Given integer values for red, green, and blue, subtract the gray from each value. Computers represent color by combinin
Dmitry_Shevchenko [17]

Answer:

Follows are the code to this question:

#include<iostream>//defining header file

using namespace std;// use package

int main()//main method

{

int red,green,blue,x;//declaring integer variable

cin>> red >>green>>blue;//use input method to input value

if(red<green && red<blue)//defining if block that check red value is greater then green and blue  

{

x = red;//use x variable to store red value

}

else if(green<blue)//defining else if block that check green value greater then blue  

{

x= green; //use x variable to store green value

}

else//defining else block

{

x=blue;//use x variable to store blue value

}

red -= x;//subtract input integer value from x  

green -=x; //subtract input integer value from x

blue -= x;//subtract input integer value from x

cout<<red<<" "<<green<<" "<<blue;//print value

return 0;

}

Output:

130 50 130

80 0 80

Explanation:

In the given code, inside the main method, four integers "red, green, blue, and x" are defined, in which "red, green, and blue" is used for input the value from the user end. In the next step, a conditional statement is used, in the if block, it checks red variable value is greater than then "green and blue" variable. If the condition is true, it will store red variable value in "x", otherwise, it will goto else if block.

  • In this block, it checks the green variable value greater than the blue variable value. if the condition is true it will store the green variable value in x variable.
  • In the next step, else block is defined, that store blue variable value in x variable, at the last step input variable, is used that subtracts the value from x and print its value.      
5 0
2 years ago
Shirley was unsure about what career to go into. Her high school counselor suggested a personal assessment to point out Shirley’
Alex73 [517]
<span>I think that she would be well suited in going into law enforcement or fire fighting. Since she loves to stay active and is cool under pressure, both of those jobs would be very well suited for her personality. Those 2 jobs demand to stay cool into delicate situations. Also, she would be able to come in to help people in need.</span>
4 0
2 years ago
Read 2 more answers
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