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2 years ago

Given an alphabet, print all the alphabets up to and including the given alphabet.

Computers and Technology

2 answers:

sergij07 [2.7K]2 years ago

6 0

Answer:

//Write the printAlphaber method header;

//It takes a char as parameter and has a return type of void

public static void printAlphabet(char ch){

//Every char has its ASCII number representation

//For example, char 'A' = 65, 'B' = 66, 'a' = 97, 'c' = 99

//In essence, A to Z = 65 to 90 and a to z = 97 to 122

//Also, if comparing a char with an int will compare the ASCII representation of the char with the int

//For example, 'A' == 65 will return true.

//Using this technique, let's write an if..else statement that checks

//if char ch is between 65 and 90 both inclusive.

//If ch is between 65 and 90, then it is an uppercase letter

if(ch >= 65 && ch <=90){

//Therefore, write a for loop to print all capital letters from 65(which is A) to char

//starting from i=65 and ending at i=ch

for(int i = 65; i <= ch; i++){

//print the char representation of the ASCII number

//by type casting the ASCII number to a char

System.out.print((char)i);

//attempt to print a space char if i is not the last letter in the sequence

if (i != ch){

System.out.print(" ");

}

//If ch is between 97 and 122 both inclusive, then it is a lowercase letter

else if(ch >= 97 && ch <= 122){

//Therefore, write a for loop to print all capital letters from 97(which is a) to char

//starting from i=97 and ending at i=ch

for(int i = 97; i <= ch; i++){

//print the char representation of the ASCII number

//by type casting the ASCII number to a char

System.out.print((char)i);

if (i != ch){

System.out.print(" ");

}

else{

System.out.println("");

}

} // End of method printAlphabet

<h2>Sample Output:</h2>

<em><u>When printAlphabet is called with d i.e printAlphabet('d')</u></em>

>> a b c d

<em><u>When printAlphabet is called with K i.e printAlphabet('K')</u></em>

>> A B C D E F G H I J K

<h2>Explanation:</h2>

The code above has been written in Java and it contains comments explaining every segment of the code. Please kindly read the comments carefully. The source code file for the complete application has been attached to this response. Kindly download it.

<u><em>The code without comments</em></u>

public static void printAlphabet(char ch){

if(ch >= 65 && ch <=90){

for(int i = 65; i <= ch; i++){

System.out.print((char)i);

if (i != ch){

System.out.print(" ");

}

else if(ch >= 97 && ch <= 122){

for(int i = 97; i <= ch; i++){

System.out.print((char)i);

if (i != ch){

System.out.print(" ");

}

else{

System.out.println("");

}

} // End of method printAlphabet

Download java

anastassius [24]2 years ago

5 0

Answer:

Explanation:

public void printAlphabets(char c){

String capitals = "ABCDEFGHIJKLMNOPQRSTUVWXYZ";

String small = "abcdefghijklmnopqrstuvwxyz";

if(capitals.contains(""+c)){

for(int i=0; i<capitals.length();i++){

if (capitals.charAt(i)!=c)

System.out.print(capitals.charAt(i)+" ");

else

break;

}// end for

System.out.print(c);

}else if (small.contains(""+c)){

for(int i=0; i<small.length();i++){

if (small.charAt(i)!=c)

System.out.print(small.charAt(i)+" ");

else

break;

}// end for

System.out.print(c);

}// end else if

}// end printAlphabets method

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Which of the following is not an advantage of a flowchart?

ad-work [718]

Answer:

d) Improper documentation

Explanation:

A flowchart is a type of diagram in which it presents the flow of the work or how the process is to be followed. It is a diagram that represents an algorithm that defines step by step approach to solving the task. In this, there are various boxes that are linked with the arrows

There are various advantages like in this, there is a better communication, coding is to be done in an efficient way, system could be tested also there is a proper documentation

hence, the correct option is d

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2 years ago

I think you have been doing a great job but you haven’t been signing many people up for our new service feature I want you to se

STatiana [176]

Answer:

24 customers

Explanation:

Given

$Customers = 96$

$p = 25\%$ --- proportion to sign up

Required

The number of customers to sign up

This is calculated as:

$n = p * Customers$

So, we have:

$n = 25\% * 96$

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2 years ago

Modify the sentence-generator program of Case Study so that it inputs its vocabulary from a set of text files at startup. The fi

Snezhnost [94]

Answer:

Go to explaination for the program code.

Explanation:

Before running the program you need to have these files created like below in your unix box.

Unix Terminal> cat nouns.txt

BOY

GIRL

BAT

BALL

Unix Terminal> cat articles.txt

THE

Unix Terminal> cat verbs.txt

HIT

SAW

LIKED

Unix Terminal> cat prepositions.txt

WITH

Unix Terminal>

Code:

#!/usr/local/bin/python3

import random

def getWords(filename):

fp = open(filename)

temp_list = list()

for each_line in fp:

each_line = each_line.strip()

temp_list.append(each_line)

words = tuple(temp_list)

fp.close()

return words

articles = getWords('articles.txt')

nouns = getWords('nouns.txt')

verbs = getWords('verbs.txt')

prepositions = getWords('prepositions.txt')

def sentence():

return nounPhrase() + " " + verbPhrase()

def nounPhrase():

return random.choice(articles) + " " + random.choice(nouns)

def verbPhrase():

return random.choice(verbs) + " " + nounPhrase() + " " + prepositionalPhrase()

def prepositionalPhrase():

return random.choice(prepositions) + " " + nounPhrase()

def main():

number = int(input('Enter number of sentences: '))

for count in range(number):

print(sentence())

if __name__=='__main__':

main()

kindly check attachment for code output and onscreen code.

6 0

2 years ago

Modify the TimeSpan class from Chapter 8 to include a compareTo method that compares time spans by their length. A time span tha

My name is Ann [436]

Answer:

Check the explanation

Explanation:

Here is the modified code for

TimeSpan.java and TimeSpanClient.java.

// TimeSpan.java

//implemented Comparable interface, which has the compareTo method

//and can be used to sort a list or array of TimeSpan objects without

//using a Comparator

public class TimeSpan implements Comparable<TimeSpan> {

private int totalMinutes;

// Constructs a time span with the given interval.

// pre: hours >= 0 && minutes >= 0

public TimeSpan(int hours, int minutes) {

totalMinutes = 0;

add(hours, minutes);

}

// Adds the given interval to this time span.

// pre: hours >= 0 && minutes >= 0

public void add(int hours, int minutes) {

totalMinutes += 60 * hours + minutes;

}

// Returns a String for this time span such as "6h15m".

public String toString() {

return (totalMinutes / 60) + "h" + (totalMinutes % 60) + "m";

}

// method to compare this time span with other

// returns a negative value if this time span is shorter than other

// returns 0 if both have same duration

// returns a positive value if this time span is longer than other

public int compareTo(TimeSpan other) {

if (this.totalMinutes < other.totalMinutes) {

return -1; // this < other

} else if (this.totalMinutes > other.totalMinutes) {

return 1; // this > other

} else {

return 0; // this = other

}

// TimeSpanClient.java

public class TimeSpanClient {

public static void main(String[] args) {

int h1 = 13, m1 = 30;

TimeSpan t1 = new TimeSpan(h1, m1);

System.out.println("New object t1: " + t1);

h1 = 3;

m1 = 40;

System.out.println("Adding " + h1 + " hours, " + m1 + " minutes to t1");

t1.add(h1, m1);

System.out.println("New t1 state: " + t1);

// creating another TimeSpan object, testing compareTo method using the

// two objects

TimeSpan t2 = new TimeSpan(10, 20);

System.out.println("New object t2: " + t2);

System.out.println("t1.compareTo(t2): " + t1.compareTo(t2));

System.out.println("t2.compareTo(t1): " + t2.compareTo(t1));

System.out.println("t1.compareTo(t1): " + t1.compareTo(t1));

}

/*OUTPUT*/

New object t1: 13h30m

Adding 3 hours, 40 minutes to t1

New t1 state: 17h10m

New object t2: 10h20m

t1.compareTo(t2): 1

t2.compareTo(t1): -1

t1.compareTo(t1): 0

4 0

2 years ago

If byte stuffing is used to transmit Data, what is the byte sequence of the frame (including framing characters)? Format answer

Lerok [7]

Answer:

Correct Answers: 01h 79h 1Bh 78h 78h 1Bh 7Ah 04

Explanation:

Solution is attached below

4 0

2 years ago