Answer:
D. nothing, as the alkyne would not react to an appreciable extent.
Explanation:
Nothing, as the alkyne would not react to an appreciable extent.
Answer:
// here is code in C++
#include <bits/stdc++.h>
using namespace std;
// main function
int main()
{
// variables
int n,no_open=0;
cout<<"enter the number of lockers:";
// read the number of lockers
cin>>n;
// initialize all lockers with 0, 0 for locked and 1 for open
int lock[n]={};
// toggle the locks
// in each pass toggle every ith lock
// if open close it and vice versa
for(int i=1;i<=n;i++)
{
for(int a=0;a<n;a++)
{
if((a+1)%i==0)
{
if(lock[a]==0)
lock[a]=1;
else if(lock[a]==1)
lock[a]=0;
}
}
}
cout<<"After last pass status of all locks:"<<endl;
// print the status of all locks
for(int x=0;x<n;x++)
{
if(lock[x]==0)
{
cout<<"lock "<<x+1<<" is close."<<endl;
}
else if(lock[x]==1)
{
cout<<"lock "<<x+1<<" is open."<<endl;
// count the open locks
no_open++;
}
}
// print the open locks
cout<<"total open locks are :"<<no_open<<endl;
return 0;
}
Explanation:
First read the number of lockers from user.Create an array of size n, and make all the locks closed.Then run a for loop to toggle locks.In pass i, toggle every ith lock.If lock is open then close it and vice versa.After the last pass print the status of each lock and print count of open locks.
Output:
enter the number of lockers:9
After last pass status of all locks:
lock 1 is open.
lock 2 is close.
lock 3 is close.
lock 4 is open.
lock 5 is close.
lock 6 is close.
lock 7 is close.
lock 8 is close.
lock 9 is open.
total open locks are :3
Answer:
Explanation:
The following code is written in Java. It is hard to fully create the code without the rest of the needed code including the T class and the Measurable interface. Regardless the following code can be implemented if you have that code available.
public static T minmax(ArrayList<T> mylist) {
T min = new T();
T max = new T();
for (int x = 0; x < mylist.size(); x++) {
if (mylist.get(x) > max) {
max = mylist.get(x);
} else if (mylist.get(x) < min) {
min = mylist.get(x);
}
}
return (min, max);
}
Hey there!
Let's assume that this question is referring to every digital calendar ever made. As in, even those made on devices without internet connectivity or any other fancy features that we utilize with many digital calendars today.
If a planning device that came with a digital calendar didn't have internet connectivity, it wouldn't be able to be connected to the cloud. Back when these devices were around, it wasn't even plausible to store things like calendar events and contacts in what we know as the "cloud". Also, these devices probably had to be hardwired to a computer and new software had to be downloaded to them, so the updates weren't automatic. Archaic, right?
Also, consider the fact that even reputable websites/companies such as Google with Google Calendars or Apple with iCalendar will never go without their malfunctions or threats. Sometimes, these websites can be hacked and the data that they contain can be compromised, especially if they're stored on the cloud. Also, even though it's not realistic, Google or Apple could one day decide to completely get rid of their calendar programs altogether. So, this means that digital calendars are definitely able to be destroyed or lost.
That just leaves "They can be used anywhere". This is true, even with those archaic devices specifically used for scheduling events and such. Nowadays, you have your phone and possibly a laptop on you at all times, which will likely have a calendar on it as a stock application. So, I think this is your answer.
Hope this helped you out! :-)
Answer:
C. Sitting in the right position
Explanation:
This is too easy man come on!
Have a great day!!
