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Rudiy27
1 year ago
7

A mobile device user has tried to install a new app numerous times without success. She has closed all unused apps, disabled liv

e wallpapers, and restarted the device in an attempt to get the app to install.
Which of the following steps should the user take next?
A. Back up all user data and perform a factory reset.
B. Check for sufficient available storage space.
C. Disable full device encryption.
D. Generate a new public key.
Computers and Technology
1 answer:
elena-14-01-66 [18.8K]1 year ago
6 0

The correct answer is B. Check for sufficient available storage space.  

Explanation:

One of the factors that can cause it is not possible to install a new app is insufficient storage as space in the mobile device is needed to save the app. This can be easily solved either by deleting apps and other content or expanding the memory available through a Micro SD card. Also, before attempting any major procedure such as a complete reset it is important to check the storage space availability. In this context, the user should check for sufficient available storage space (option B) because this might be the cause of the issue she is experiencing; also, this is a basic step before considering others such as performing a factory reset.

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Write multiple if statements: If carYear is before 1968, print "Probably has few safety features." (without quotes). If after 19
jekas [21]

Answer:

Following is the statement in the C language :

if(carYear < 1968)

printf("\nProbably has a few safety features.\n");

if(carYear > 1970 && carYear <=1991 )

printf("\nProbably has head rests.\n");

if(carYear > 1991 && carYear <=2002)

printf("\nProbably has anti-lock brakes\n.");

if(carYear > 2002)

printf("\nProbably has airbags.\n");

Explanation:

Following is the description of the statement:

  • In the given question we used if block. The if block is only executed when their condition is true.
  • if(carYear < 1968) In this we check we the value of "carYear" variable is less then 1968 then it prints "Probably has a few safety features." in the console window.
  • if(carYear > 1970 && carYear <=1991) In this we check we the value of "carYear" variable is greater then 1970 and less then 1992 it prints "Probably has head rests" in the console window.
  • if(carYear > 1991 && carYear <=2002 ) In this we check we the value of "carYear" variable is greater then 1991 and less then 2003 it prints "Probably has anti-lock brakes" in the console window.
  • if(carYear > 2002) In this we check we the value of "carYear" variable is greater then 2002 then it prints "Probably has airbags" in the console window.

6 0
2 years ago
Use the single-server drive-up bank teller operation referred to in Problems 1 and 2 to determine the following operating charac
elena-s [515]

Answer:

This question is incomplete, here's the complete question:

1. Willow Brook National Bank operates a drive-up teller window that allows customers to complete bank transactions without getting out of their cars. On weekday mornings, arrivals to the drive-up teller window occur at random, with an arrival rate of 24 customers per hour or 0.4 customers per minute. 3. Use the single-server drive-up bank teller operation referred to in Problems 1 to determine the following operating characteristics for the system: a.) The probability that no customers are in the system. b.) The average number of customers waiting. c.) The average number of customers in the system. d.) The average time a customer spends waiting. e.) The average time a customer spends in the system. f.) The probability that arriving customers will have to wait for service.

Explanation:

Arrival rate \lambda = 24 customers per hour or 0.4 customers per minute

Service rate \mu​ = 36 customers per hour or 0.6 customers per minute (from problem 1)

a.) The probability that no customers are in the system , P0 = 1 - \lambda / \mu

= 1 - (24/36) = 1/3 = 0.3333

b.) The average number of customers waiting

Lq = \lambda^2 / [\mu(\mu - \lambda)] = 242 / [36 * (36 - 24)] = 1.33

c.) The average number of customers in the system.

L = Lq + \lambda / \mu = 1.33 + (24/36) = 2

d.) The average time a customer spends waiting.

Wq = \lambda / [\mu(\mu - \lambda)] = 24 / [36 * (36 - 24)] = 0.0555 hr = 3.33 min

e.) The average time a customer spends in the system

W = Wq + 1/\mu = 0.0555 + (1/36) = 0.0833 hr = 5 min

f.) The probability that arriving customers will have to wait for service.

= 1 - P0 = 1 - 0.3333 = 0.6667

3 0
1 year ago
Determining the Services Running on a Network Alexander Rocco Corporation has multiple OSs running in its many branch offices. B
Sladkaya [172]

Answer: provided in the explanation section

Explanation:

 Network’s vulnerabilities:

           Vulnerability is a weak spot in your network that might be exploited by a security threat. Risks are the potential consequences and impacts of unaddressed vulnerabilities. In other words, failing to do Windows Updates on your Web server is vulnerability.

           Regularly scheduled network vulnerability scanning can help an organization identify weaknesses in their network security before the bad guys can mount an attack. The goal of running a vulnerability scanner or conducting an external vulnerability assessments is to identify devices on your network that are open to known vulnerabilities without actually compromising your systems.

           The overall objective of a Vulnerability Assessment is to scan, investigate, analyze and report on the level of risk associated with any security vulnerabilities discovered on the public, internet-facing devices and to provide your organization with appropriate mitigation strategies to address those discovered vulnerabilities.

         

Network topology issues:

Coverage Topology

           Coverage problem reflects how well an area is monitored or tracked. The coverage and connectivity problems in networks have received considerable attention in the research community in recent years

 

Geographic routing

           Geographic routing uses geographic and topological information of the network to achieve optimal routing schemes with high routing efficiency and low power consumption

Port Numbers

           Port Numbers While IP addresses determine the physical endpoints of a network connection, port numbers determine the logical endpoints of the connection. Port numbers are 16-bit integers with a useful range from 1 to 65535.

Port numbers are assigned by an organization called IANA and ports are allocated to various needs to avoid confusion.

Ports are classified into 3 main categories.

Well Known Ports (Port numbers 0 - 1023)

           In a client-server application, the server usually provides its service on a well-known port number. Well-known port numbers are a subset of the numbers which are assigned to applications. According to RFC1700 [5], well-known port numbers are managed by the Internet Assigned Numbers Authority (IANA). They used to be in the range from 1 to 255, but in 1992 the range was increased up to 1023.

Registered Ports (Port numbers1024 - 49151)

Such ports are used by programs run by users in the system.

           In addition to the well-known ports below 1024 there are more port numbers assigned to applications but are located anywhere from 1024 to 65535.

Private or Dynamic Ports (Port numbers 49152 - 65535)

           Private ports are not assigned for any specific purpose.

         

Discuss the concepts of well-known ports and give a brief description of the most commonly used ports: 20, 21, 23, 25, 53, and 110.

Commonly Used Port Numbers

The following port numbers are unofficial list of commonly used for linux/unix based servers.

         

20&21               TCP                FTP (File server protocol)

           FTP is one of the most commonly used file transfer protocols on the Internet and within private networks. An FTP server can easily be set up with little networking knowledge and provides the ability to easily relocate files from one system to another. FTP control is handled on TCP port 21 and its data transfer can use TCP port 20 as well as dynamic ports depending on the specific configuration.

23                   TCP/UDP          Telnet

           Telnet is the primary method used to manage network devices at the command level. Unlike SSH which provides a secure connection, Telnet does not, it simply provides a basic unsecured connection. Many lower level network devices support Telnet and not SSH as it required some additional processing. Caution should be used when connecting to a device using Telnet over a public network as the login credentials will be transmitted in the clear.

25                   TCP/UDP         SMTP   (for sending outgoing emails)

           SMTP is used for two primary functions, it is used to transfer mail (email) from source to destination between mail servers and it is used by end users to send email to a mail system.

53         TCP/UDP        DNS Server (Domain name service for DNS request)

           The DNS is used widely on the public internet and on private networks to translate domain names into IP addresses, typically for network routing. DNS is hieratical with main root servers that contain databases that list the managers of high level Top Level Domains (TLD) (such as .com). T

110             TCP                 POP3 (For receiving emails)

           POP version 3 is one of the two main protocols used to retrieve mail from a server. POP was designed to be very simple by allowing a client to retrieve the complete contents of a server mailbox and then deleting the contents from the server.

4 0
2 years ago
What is printed by the following program provided all necessary standard header files are included? Explain each line of the out
Ostrovityanka [42]

<u>Output:</u>

f1 in A

f2 in A

f1 in B

f2 in A

f1 in A

f2 in A

f1 in B

f2 in B  

<u>Explanation:</u>

In this snippet, the code makes use of virtual functions. A virtual function is defined as a function that is defined in the base class and redefined in the derived class. If the derived function accesses the virtual function, the program will get executed with the derived class’s version of the function.

In this code, we define the virtual function f1() in class A and also redefine it in class B which is the derived class of A. While executing the program, the function g which takes the object b (class B’s object) as a parameter. It will print class B’s version of f1() rather than class A’s version. This is working off the virtual function.

8 0
1 year ago
Why would Network Systems employees be employed by the government?
Ghella [55]
Well knowing how the government is with security id go with A. as it makes a lot of sense unlike B and D and if they were looking for software the question would mention it
8 0
1 year ago
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