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jeka57 [31]
2 years ago
11

A bunch of computer scientists take over an island and start their own country. They want the license plates to use binary numbe

rs. There's space for 7 digits on each license plate and the first plate starts at 000000000000000000000.
How many unique license plates can their country support? Answer in decimal:
Computers and Technology
1 answer:
Thepotemich [5.8K]2 years ago
5 0

Answer:

  • <em>Their country can support </em><u><em>   128   </em></u><em>unique license plates</em>

Explanation:

Since there is space for<em> 7 digits </em>on each <em>license plate</em>, the first plate starts at <em>0000000 </em>(seven 0).

<em>Binary numbers</em> contain only the digits 0 and 1.

Thus, there are only two possibilities for each digit.

Using the multiplication counting principle, the number of total different binary numbers, with seven digits is 2 multiplied seven times:

  • 2 × 2 × 2 × 2 × 2 × 2 × 2 = 2⁷ = 128 ← answer
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Answer:

Explanation:

   public class Temperature

   {

       double ftemp;

       public int Constructor(double fahrenheit)

       {

           ftemp = fahrenheit;

          return Convert.ToInt32(ftemp);

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       public void setFahrenheit(double fahrenheit)

       {

           ftemp = fahrenheit;

       }

       public void getFahrenheit()

       {

           ftemp = Constructor(ftemp);

       }

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       {

           ftemp = (ftemp - 32) * 5 / 9;

       }

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       {

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A city planner is using simulation software to study crowd flow out of a large arena after an event has ended. The arena is loca
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Answer:

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Write a recursive method called isReverse that accepts two strings as parameters and returns true if the two strings contain the
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Answer:

public static boolean isReverse(String s1, String s2)

{

if (s1.length() == 0 && s2.length() == 0)

{

return true;

}

else if (s1.length() == 0 || s2.length() == 0)

{

return false;

} else

{

String s1first = s1.substring(0, 1);

String s2last = s2.substring(s2.length() - 1);

return s1first.equalsIgnoreCase(s2last) &&

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}

public static boolean isReverse(String s1, String s2)

{

if (s1.length() != s2.length()) {

return false; // not same length

} else if (s1.length() == 0 && s2.length() == 0) {

return true;

} else

{

s1 = s1.toLowerCase();

s2 = s2.toLowerCase();

return s1.charAt(0) == s2.charAt(s2.length() - 1) &&

isReverse(s1.substring(1, s1.length()),

s2.substring(0, s2.length() - 1));

}

}

public static boolean isReverse(String s1, String s2)

{

if (s1.length() == s2.length())

{

return isReverse(s1.toLowerCase(), 0, s2.toLowerCase(), s2.length() - 1);

} else {

return false;

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}

}

private static boolean isReverse(String s1, int i1, String s2, int i2)

{

if (i1 >= s1.length() && i2 < 0) {

return true;

} else {

return s1.charAt(i1) == s2.charAt(i2) &&

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}

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return reverse(s1.toLowerCase()).equals(s2.toLowerCase());

}

private static String reverse(String s)

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if (s.length() == 0) {

return s;

} else {

return reverse(s.substring(1)) + s.charAt(0);

}

}

Explanation:

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