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jeka57 [31]
2 years ago
11

A bunch of computer scientists take over an island and start their own country. They want the license plates to use binary numbe

rs. There's space for 7 digits on each license plate and the first plate starts at 000000000000000000000.
How many unique license plates can their country support? Answer in decimal:
Computers and Technology
1 answer:
Thepotemich [5.8K]2 years ago
5 0

Answer:

  • <em>Their country can support </em><u><em>   128   </em></u><em>unique license plates</em>

Explanation:

Since there is space for<em> 7 digits </em>on each <em>license plate</em>, the first plate starts at <em>0000000 </em>(seven 0).

<em>Binary numbers</em> contain only the digits 0 and 1.

Thus, there are only two possibilities for each digit.

Using the multiplication counting principle, the number of total different binary numbers, with seven digits is 2 multiplied seven times:

  • 2 × 2 × 2 × 2 × 2 × 2 × 2 = 2⁷ = 128 ← answer
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Which is true for a hosted blog software
professor190 [17]
Since you have not provided the choices wherein I will have to choose from to arrive at an answer, I will just explain to you the concept revolving around a hosted blog software. Hosted blog software are basically installed by the owner of the web server in which among its famous platforms is the Blogger.
7 0
2 years ago
Read 2 more answers
The budget process which emphasizes the achievement of goals and competition between alternatives is:
Maslowich

The question has multiple choices;


<span>A) </span>Incremental budgeting.
B) Performance budgeting.
C) Program budgeting.
D) Target based budgeting.


I’d say D is the answer; Target based budgeting


Target based budgeting focuses on the achievement of goals and competition. Prices in Target based budgeting are used as a tool to make or break sales. This method includes researching the markets to decide at what exact price a product will sell.






4 0
2 years ago
Computers represent color by combining the sub-colors red, green, and blue (rgb). Each sub-color's value can range from 0 to 255
maxonik [38]

Answer:

Follows are the code to this question:

#include <iostream>//defining a header file

using namespace std; //using namespace

int main() //defining main method

{

int red,green,blue,s; //defining integer variable

cout<<"Enter value: \n ";//print message

cin>>red>>green>>blue; //input value

if(red<green && red<blue)//defining if block that checks red value

s=red;//store red variable value to s variable

else if(green<blue)//defining else if block that checks green value less then blue

s=green;//store green variable value in s variable

else//defining else block

s=blue; //store blue variable value in s variable

//calculating red, green, blue value

red=red-s;//store red value

green=green-s;//store green value

blue=blue-s;//store blue value

cout<<red<<" "<<green<<" "<<blue;

}

Output:

Enter value:

130  

50

130

80 0 80

Explanation:

In the above code, inside the Main method, four integer variable "red, green, blue, and s" is defined, in which "red, green, and blue" is used for input the value from the user end.

  • In the next step, a conditional statement is used, that checks the red variable value, if the condition is true, it will store its value in the "s" variable, otherwise, it will go to else if block.
  • In this block, the green variable checks its value less than then blue variable value, if the condition is true, it will store the green value in the "s" variable, otherwise, it will goto else block.
  • In this block, it will store the blue variable value in the "s" variable, and subtract the value of "red, green, and blue" value from "s" and store its value, and at the last, it will print its value.    
4 0
2 years ago
Determine the value of base x if (211)x = (6A)16
elena-14-01-66 [18.8K]
211x=6A•16
211x=96A
211x=96A
___. ___
211. 211

x=96A
___
211


It's hard to show fractions on here :•)
7 0
2 years ago
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In Section 8.5.4, we described a situation in which we prevent deadlock by ensuring that all locks are acquired in a certain ord
ruslelena [56]

Answer:

See Explaination

Explanation:

Separating this critical section into two sections:

void transaction(Account from, Account to, double amount)

{

Semaphore lock1, lock2;

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lock2 = getLock(to);

wait(lock1);

withdraw(from, amount);

signal(lock1);

wait(lock2);

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signal(lock2);

}

will be the best solution in the real world, because separating this critical section doesn't lead to any unwanted state between them (that is, there will never be a situation, where there is more money withdrawn, than it is possible).

The simple solution to leave the critical section in one piece, is to ensure that lock order is the same in all transactions. In this case you can sort the locks and choose the smaller one for locking first.

4 0
2 years ago
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