Answer:
Start the algorithm and check the weight of the ship. Load the crystalline to the ship. Check to see if the ship weighs ship weight + k pound crystalline, if less, add more crystalline. If excess, remove the excess crystalline, but if the weight meets the condition, then take off with the loaded ship to planet sigma.
Explanation:
The algorithm continuously checks the weight of the ship on loading with the calculated sum of the ship and k pound crystalline weight. The ship is able to load the correct maximum amount of crystalline to the planet sigma.
Answer:
Electrical potential.
Explanation:
RADIAC Meter or instruments ( also known as radiation monitoring instruments) are measuring instruments that uses the principles of gaseous ionisation to conduct electricity flow internally to deflect the pointer for its Meter readings. These instruments can be analogue or digital.
They are used in industries to monitor the operation of certain equipments and processes. The level of electrical potential flow in the system determines the state or category of the instrument. Out of six, there are three main categories of electrical potential level.
Answer:
double arrow shape
Explanation:
To adjust the height of the cells
1. We have to position the mouse pointer over one of the column line or the one of the row line.
2. As we place the pointer between the dividing lines, the cursor of the mouse pointer change from singe bold arrow to double arrow symbol.
3.Now press or click the left mouse button and drag the dividing lines of the cells to the desired position to have the required width or height of the cell.
Answer:
Check the explanation
Explanation:
public String replace(String sentence){
if(sentence.isEmpty()) return sentence;
if(sentence.charAt(0) == ' ')
return '*' + replace(sentence.substring(1,sentence.length()));
else
return sentence.charAt(0) + replace(sentence.substring(1,sentence.length()));
Answer:
O(n^2)
Explanation:
The number of elements in the array X is proportional to the algorithm E runs time:
For one element (i=1) -> O(1)
For two elements (i=2) -> O(2)
.
.
.
For n elements (i=n) -> O(n)
If the array has n elements the algorithm D will call the algorithm E n times, so we have a maximum time of n times n, therefore the worst-case running time of D is O(n^2)
