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2 years ago

The final step of the DHCP Discovery process is known as...

Computers and Technology

1 answer:

aksik [14]2 years ago

5 0

<span>DHCP stands for the Dynamic Host Configuration Protocol (DHCP), which is a network management protocol. </span>

The final step of the DHCP Discovery process is known as DORA (Discover Offer Request and Acknowledgement). The DORA process is the process of assigning the IP addresses by the DHCP server.

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Given sphereRadius and piVal, compute the volume of a sphere and assign to sphereVolume. Look up the equation online (e.g., http

fenix001 [56]

Answer:

#include <stdio.h>
int main()
{
const double piVal = 3.14159;
double sphereVolume = 0.0;
double sphereRadius = 0.0;
sphereRadius = 1.0;
sphereVolume = 4.0/ 3.0 * piVal * sphereRadius * sphereRadius * sphereRadius;
printf("Sphere volume: %lf\n", sphereVolume);
return 0;
}

Explanation:

Firstly we can identify the formula to calculate volume of sphere which is

Volume = 4/3 $\pi r^{3}$

With this formula in mind, we can apply this formula to calculate the volume of sphere in Line 10. This is important to perform floating-point division 4.0/3.0 to ensure the resulting value is a floating value as well. Since we have been given piVal and sphereRadius, we can just multiply the result of floating-point division with piVal and sphereRadius and get the sphereVolume value.

At last, display the sphere volume using printf method (Line 13).

6 0

2 years ago

BlockPy: #35.2) Animal Splits Write a function all_cats that consumes a comma-separated string of animals and prints whether all

maks197457 [2]

Answer:

def all_cats(data):

dataArray = data.split(',')

if(data==""):

return True

for i in dataArray:

if('cat' not in i):

return False

return True

print(all_cats("gerbil,catfish,dog,cat"))

print(all_cats("cat,catfish"))

print(all_cats(""))

Explanation:

Step 1: define de function and the parameters

def all_cats(data):

Step 2: split the data by ,

dataArray = data.split(',')

Step 3 : validate if is an empty data and return true

if(data==""):

return True

Step 4: Loop over de array data and validate if have cat in each data if not, then return false

for i in dataArray:

if('cat' not in i):

return False

Step 5 if have cat in each one return true

return True

Step 6 Validate with examples

print(all_cats("gerbil,catfish,dog,cat"))

print(all_cats("cat,catfish"))

print(all_cats(""))

6 0

2 years ago

Two blue armies are each poised on opposite hills preparing to attack a single red army in the valley. The red army can defeat e

labwork [276]

Answer:

I would attack with one blue army and while all the chaos I would send the foot soldier to the second blue army and tell them to attack with the first. Idk like if the foot soldier is the only way of communication, so yeah

6 0

2 years ago

Read 2 more answers

) Consider a router that interconnects four subnets: Subnet 1, Subnet 2, Subnet 3 and Subnet 4. Suppose all of the interfaces in

erik [133]

Answer:

Check the explanation

Explanation:

223.1.17/24 indicates that out of 32-bits of IP address 24 bits have been assigned as subnet part and 8 bits for host id.

The binary representation of 223.1.17 is 11011111 00000001 00010001 00000000

Given that, subnet 1 has 63 interfaces. To represent 63 interfaces, we need 6 bits (64 = 26)

So its addresses can be from 223.1.17.0/26 to 223.1.17.62/26

Subnet 2 has 95 interfaces. 95 interfaces can be accommodated using 7 bits up to 127 host addresses can represented using 7 bits (127 = 27)

and hence, the addresses may be from 223.1.17.63/25 to 223.1.17.157/25

Subnet 3 has 16 interfaces. 4 bits are needed for 16 interfaces (16 = 24)

So the network addresses may range from 223.1.17.158/28 to 223.1.17.173/28

4 0

2 years ago

#You may modify the lines of code above, but don't move them! #When you Submit your code, we'll change these lines to #assign di

Musya8 [376]

Answer:

The solution code is written in Python:

mystery_string = "Programming"
output = ""
for x in mystery_string:
output += x
print(output)

Explanation:

Firstly, create a variable mystery_string to hold a random string (Line 1).

Create an output variable to hold an output string (Line 2).

Create a for-loop to traverse the mystery_string character by character (Line 4). In the iteration, get a character from the mystery_string, and concatenate it with output string (Line 5). Print the output string (Line 6) before proceed to the next iteration.

8 0

2 years ago