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2 years ago

15

This exercise shows why each pivot (in eli1nination by pivoting) must be in a different row. (a) In Example 7, make the third pi

vot on entry (3, 3) instead of on entry (3, 2). Can you still read off the solution

Computers and Technology

1 answer:

Darya [45]2 years ago

8 0

Answer:gghggggggggggggg

Explanation:

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Suppose that you need to maintain a collection of data whose contents are fixed- i.e., you need to search for and retrieve exist

Keith_Richards [23]

Answer:

Option a: a sorted array

Explanation:

Since the expectation on the data structure never need to add or delete items, a sorted array is the most desirable option. An array is known for its difficulty to modify the size (either by adding item or removing item). However, this disadvantage would no longer be a concern for this task. This is also the reason, linked list, binary search tree and queue is not a better option here although they offer much greater efficiency to add and remove item from collection.

On another hand, any existing items from the sorted array can be easily retrieved using address indexing and therefore the data query process can be very fast and efficient.

4 0

2 years ago

Digital cellphones use __________ to reduce the size of the channels that are required by scattering the digital fragments of co

Yuri [45]

Digital cellphones use Digital Compression to reduce the size of the channels that are required, by scattering the digital fragments of conversations over many channels

7 0

2 years ago

Java languageThe cost to ship a package is a flat fee of 75 cents plus 25 cents per pound.1. Declare a constant named CENTS_PER_

Sophie [7]

Answer:

// Here is code in Java.

// import package

import java.util.*;

// class definition

class Main

{

// main method of the class

public static void main (String[] args) throws java.lang.Exception

{

try{

// variables

final int CENTS_PER_POUND = 25;

final int FLAT_FEE_CENTS = 75;

// Scanner object to read input

Scanner sr=new Scanner(System.in);

System.out.print("Enter the shipping weight:");

// read the input weight

int shipWeightPounds=sr.nextInt();

// calculate total cost

int shipCostCents = (shipWeightPounds * CENTS_PER_POUND) + FLAT_FEE_CENTS;

// print Weight

System.out.println("shipping Weight: " + shipWeightPounds);

// print flat fee

System.out.println("flat fee of shipping in cents : " + FLAT_FEE_CENTS);

// print cents per round

System.out.println("Cents/pound for shipping: " + CENTS_PER_POUND);

// print cost of Shipping

System.out.println("total cost of shipping in cents: " + shipCostCents);

}catch(Exception ex){

return;}

}

}

Explanation:

Declare and initialize two constant variables "CENTS_PER_POUND=25" & "FLAT_FEE_CENTS = 75". Read the input weight from user with the help of Scanner class object. Then calculate the cost of shipping by multiply weight with cent per pound and add flat fee. Then print each of them.

Output:

Enter the shipping weight:12

shipping Weight : 12

flat fee of shipping in cents: 75

Cents/pound for shipping: 25

total cost of shipping in cents: 375

8 0

2 years ago

Read 2 more answers

BlockPy: #35.2) Animal Splits Write a function all_cats that consumes a comma-separated string of animals and prints whether all

maks197457 [2]

Answer:

def all_cats(data):

dataArray = data.split(',')

if(data==""):

return True

for i in dataArray:

if('cat' not in i):

return False

return True

print(all_cats("gerbil,catfish,dog,cat"))

print(all_cats("cat,catfish"))

print(all_cats(""))

Explanation:

Step 1: define de function and the parameters

def all_cats(data):

Step 2: split the data by ,

dataArray = data.split(',')

Step 3 : validate if is an empty data and return true

if(data==""):

return True

Step 4: Loop over de array data and validate if have cat in each data if not, then return false

for i in dataArray:

if('cat' not in i):

return False

Step 5 if have cat in each one return true

return True

Step 6 Validate with examples

print(all_cats("gerbil,catfish,dog,cat"))

print(all_cats("cat,catfish"))

print(all_cats(""))

6 0

2 years ago

g Suppose the information content of a packet is the bit pattern 1110 0110 1001 1101 and an even parity scheme is being used. Wh

erma4kov [3.2K]

Answer: see description

Explanation:

first we accommodate the bit pattern in a matrix of 4x4 which is the minimum length checksum field, now with even parity two-dimensional scheme we need to complete this matrix by adding one row and one column by adding at the end of each row a 1 or a 0 to complete pairs of 1's:

we have

$\left[\begin{array}{cccc}1&1&1&0\\0&1&1&0\\1&0&0&1\\1&1&0&1\end{array}\right]$

so we complete with this, adding a row at the end which matches a pair number of 1's

$\left[\begin{array}{ccccc}1&1&1&0&1\\0&1&1&0&0\\1&0&0&1&0\\1&1&0&1&1\\1&1&0&0&0\end{array}\right]$

4 0

2 years ago