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guajiro [1.7K]
2 years ago
11

Design and document an IP addressing scheme to meet ElectroMyCycle’s needs. Specify which IP address blocks will be assigned to

different modules of your network design. Document whether you will use public or private addressing for each module. Document whether you will use manual or dynamic addressing for each module. Specify where (if anywhere) route summarization will occur.

Computers and Technology
1 answer:
noname [10]2 years ago
7 0

Answer:

Given that: Design scenario - page 197 has a continuation of the chapter 1 design scenario for ElectroMyCycle

Explanation:

See attached image

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Recall the problem of finding the number of inversions. As in the text, we are given a sequence of n numbers a1, . . . , an, whi
Kay [80]

Answer:

The algorithm is very similar to the algorithm of counting inversions. The only change is that here we separate the counting of significant inversions from the merge-sort process.

Algorithm:

Let A = (a1, a2, . . . , an).

Function CountSigInv(A[1...n])

if n = 1 return 0; //base case

Let L := A[1...floor(n/2)]; // Get the first half of A

Let R := A[floor(n/2)+1...n]; // Get the second half of A

//Recurse on L. Return B, the sorted L,

//and x, the number of significant inversions in $L$

Let B, x := CountSigInv(L);

Let C, y := CountSigInv(R); //Do the counting of significant split inversions

Let i := 1;

Let j := 1;

Let z := 0;

// to count the number of significant split inversions while(i <= length(B) and j <= length(C)) if(B[i] > 2*C[j]) z += length(B)-i+1; j += 1; else i += 1;

//the normal merge-sort process i := 1; j := 1;

//the sorted A to be output Let D[1...n] be an array of length n, and every entry is initialized with 0; for k = 1 to n if B[i] < C[j] D[k] = B[i]; i += 1; else D[k] = C[j]; j += 1; return D, (x + y + z);

Runtime Analysis: At each level, both the counting of significant split inversions and the normal merge-sort process take O(n) time, because we take a linear scan in both cases. Also, at each level, we break the problem into two subproblems and the size of each subproblem is n/2. Hence, the recurrence relation is T(n) = 2T(n/2) + O(n). So in total, the time complexity is O(n log n).

Explanation:

5 0
2 years ago
Information gathered from observing a plant grow 3 cm over a two-week period results in _______.a. inferences. b. variables. c.
Leya [2.2K]

Answer:

The answer is d. Data

Explanation:

information gathered from observing a plant grow 3 cm over a two-week period results in Data

data is facts and statistics collected together for reference or analysis.

Data is any information that has been collected, observed, generated or created to validate original research findings

6 0
2 years ago
Provide an example of each of the three primary information security areas: (1) authentication and authorization, (2) prevention
snow_lady [41]

Answer:

Explanation:

1. Authentication is a method for confirming users' identities. Once a system determines the authentication of a user, it can then determine the access privileges for that user. Authorization involves providing a user with permission, including access levels and abilities. For example file access, hours of access, and amount of allocated storage space.

2. Content filtering is a software organizations use that filters content, such as emails, to prevent the accidental or malicious transmission of unauthorized information. Encryption scrambles information into an alternative form that requires a key or password to decrypt. In a security branch, an intruder is then unable to read encrypted information. A firewall is hardware and/or software that guard a private network by analyzing incoming and outgoing information for the correct markings.

3. Intrusion detection software (IDS) features full-time monitoring tools that search for patterns in network traffic to identify intruders.

4 0
2 years ago
1⁰=?<br> Is equal to...........
Murrr4er [49]

Answer:

1

Explanation:

Anything to the 0th power is 1. However, 0⁰ is undefined.

5 0
2 years ago
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Compare the elements of the basic Software Development Life Cycle with 2 other models. How are they similar? How are they differ
Artemon [7]

Answer:

Explanation:

One of the basic notions of the software development process is SDLC models which stands for Software Development Life Cycle models. SDLC – is a continuous process, which starts from the moment, when it’s made a decision to launch the project, and it ends at the moment of its full remove from the exploitation. There is no one single SDLC model. They are divided into main groups, each with its features and weaknesses. The most used, popular and important SDLC models are given below:

1. Waterfall model

2. Iterative model

3. Spiral model

4. V-shaped model

5. Agile model

Stage 1. Planning and requirement analysis

Each software development life cycle model starts with the analysis, in which the stakeholders of the process discuss the requirements for the final product.

Stage 2. Designing project architecture

At the second phase of the software development life cycle, the developers are actually designing the architecture. All the different technical questions that may appear on this stage are discussed by all the stakeholders, including the customer.  

Stage 3. Development and programming

After the requirements approved, the process goes to the next stage – actual development. Programmers start here with the source code writing while keeping in mind previously defined requirements. The programming by itself assumes four stages

• Algorithm development

• Source code writing

• Compilation

• Testing and debugging

Stage 4. Testing

The testing phase includes the debugging process. All the code flaws missed during the development are detected here, documented, and passed back to the developers to fix.  

Stage 5. Deployment

When the program is finalized and has no critical issues – it is time to launch it for the end users.  

SDLC MODELS

Waterfall – is a cascade SDLC model, in which development process looks like the flow, moving step by step through the phases of analysis, projecting, realization, testing, implementation, and support. This SDLC model includes gradual execution of every stage completely. This process is strictly documented and predefined with features expected to every phase of this software development life cycle model.

ADVANTAGES  

Simple to use and understand

DISADVANTAGES

The software is ready only after the last stage is over

ADVANTAGES

Management simplicity thanks to its rigidity: every phase has a defined result and process review

DISADVANTAGES

High risks and uncertainty

Iterative SDLC Model

The Iterative SDLC model does not need the full list of requirements before the project starts. The development process may start with the requirements to the functional part, which can be expanded later.  

ADVANTAGES                                        

Some functions can be quickly be developed at the beginning of the development lifecycle

DISADVANTAGES

Iterative model requires more resources than the waterfall model

The paralleled development can be applied Constant management is required

Spiral SDLC Model

Spiral model – is SDLC model, which combines architecture and prototyping by stages. It is a combination of the Iterative and Waterfall SDLC models with the significant accent on the risk analysis.

4 0
2 years ago
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