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leva [86]
2 years ago
13

Question _.1 with 1 blankMiguel y Maru están muy cansados. Question 2 with 1 blankFelipe es muy joven. Question 3 with 1 blankJi

mena es muy inteligente. Question 4 with 1 blankLa madre de Marissa está muy contenta. Question 5 with 1 blankEstoy muy aburrido.
Computers and Technology
1 answer:
Alekssandra [29.7K]2 years ago
8 0

Answer:

Miguel y Maru están muy cansados.  - Miguel y Maru están cansadísimos

Felipe es muy joven. - Felipe es jovencísimo

Jimena es muy inteligente. - Jimena es inteligentísima

La madre de Marissa está muy contenta. - La madre de Marissa está contentísima

Estoy muy aburrido. - Estoy aburridísimo

Explanation:

In this activity we have to switch the statements to the absolute superlative of the expressions. In Spanish we can add the suffix -ísimo to an adjective to refer to the highest degree of something. It can be translated in ENglish to "really, extremely, super or quie". The statements in English are:

- Miguel and Maru are very tired - Miguel and Mary are extremely tired

- Felipe is very young - Felipe is super young

- Jimena is very smart - Jimena is really smart

- Marissa´s mother is very happy - Marissa´s mother is extremely happy

- I´m very bored - I´m super bored

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Answer:

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#include <iostream>

using namespace std;

double *sum_n_avg(double n1, double n2, double n3);

int main () {

   double n1, n2, n3;

   cout<<"Enter 3 inputs: ";

   cin>>n1>>n2>>n3;

   double *p;

   p = sum_n_avg(n1,n2,n3);

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double *sum_n_avg(double n1, double n2, double n3) {

  static double arr[2];

  arr[0] = n1 + n2 + n3;

  arr[1] = arr[0]/3;

  return arr;

}

Explanation:

This defines the function prototype

double *sum_n_avg(double n1, double n2, double n3);

The main begins here

int main () {

This declares variables for input

   double n1, n2, n3;

This prompts the user for 3 inputs

   cout<<"Enter 3 inputs: ";

This gets user inputs

   cin>>n1>>n2>>n3;

This declares a pointer to get the returned values from the function

   double *p;

This passes n1, n2 and n3 to the function and gets the sum and average, in return.

   p = sum_n_avg(n1,n2,n3);

Print sum and average

<em>    cout<<"Sum: "<<*(p + 0) << endl;</em>

<em>    cout<<"Average: "<<*(p + 1) << endl;</em>

  return 0;

}

The function begins here

double *sum_n_avg(double n1, double n2, double n3) {

Declare a static array

  static double arr[2];

Calculate sum

  arr[0] = n1 + n2 + n3;

Calculate average

  arr[1] = arr[0]/3;

Return the array to main

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}

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