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zlopas [31]
2 years ago
11

What output is produced by the following program segment? Why? (Recall that name.charAt(i) is the i-th character in the string,

name.)
String name;
int i;
boolean startWord;

name = "Richard M. Nixon";
startWord = true;
for (i = 0; i < name.length(); i++) {
if (startWord)
System.out.println(name.charAt(i));
if (name.charAt(i) == ' ')
startWord = true;
else
startWord = false;
}
Computers and Technology
1 answer:
vekshin12 years ago
8 0

Answer:

The output is:

R

M

N

Explanation:

The code snippet print the beginning letter of each word in the given name.

In the for loop snippet:

first the program check if startWord is true and it is true, then it print the value of the character at index 0. Then it check if value of character is empty. If it is empty, startWord is initialized to true else it is initialized to false.

The loop only print a character when the value of i are 0, 8 and 11 which are also the beginning character of a word.

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Olin [163]

Answer:

A.  grep -E "(John|Bob)" salesemployees.csv

Explanation:

The grep command is used to search text. It searches the given file for lines containing a match to the given strings or words.

How to use Grep Command:

grep 'letter' filename – Search any line that contains word 'letter' in filename on Linux

grep -i 'Alphabet' file1 – A case-insensitive search for the word ‘Alphabet’ in Linux and Unix

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2 years ago
The __________ vulnerability assessment is a process designed to find and document selected vulnerabilities that are likely to b
forsale [732]
The risk vulnerability assessment is the answer
5 0
2 years ago
A file concordance tracks the unique words in a file and their frequencies. Write a program that displays a concordance for a fi
neonofarm [45]

Answer:

Python file with appropriate comments given below

Explanation:

#Take the input file name

filename=input('Enter the input file name: ')

#Open the input file

inputFile = open(filename,"r+")

#Define the dictionary.

list={}

#Read and split the file using for loop

for word in inputFile.read().split():

  #Check the word to be or not in file.

  if word not in list:

     list[word] = 1

  #increment by 1

  else:

     list[word] += 1

#Close the file.

inputFile.close();

#print a line

print();

#The word are sorted as per their ASCII value.

fori in sorted(list):

  #print the unique words and their

  #frequencies in alphabetical order.

  print("{0} {1} ".format(i, list[i]));

3 0
2 years ago
Produce a list named prime_truths which contains True for prime numbers and False for nonprime numbers in the range [2,100]. We
LenKa [72]

Answer:

  1. def is_prime(n):
  2.    for i in range(2, n):
  3.        if(n % i == 0):
  4.            return False  
  5.    return True  
  6. prime_truths = [is_prime(x) for x in range(2,101)]
  7. print(prime_truths)

Explanation:

The solution code is written in Python 3.

Presume there is a given function is_prime (Line 1 - 5) which will return True if the n is a prime number and return False if n is not prime.

Next, we can use the list comprehension to generate a list of True and False based on the prime status (Line 7). To do so, we use is_prime function as the expression in the comprehension list and use for loop to traverse through the number from 2 to 100. The every loop, one value x will be passed to is_prime and the function will return either true or false and add the result to prime_truth list.

After completion of loop within the comprehension list, we can print the generated prime_truths list (Line 8).

3 0
2 years ago
Suppose that you need to maintain a collection of data whose contents are fixed- i.e., you need to search for and retrieve exist
Keith_Richards [23]

Answer:

Option a: a sorted array

Explanation:

Since the expectation on the data structure never need to add or delete items, a sorted array is the most desirable option. An array is known for its difficulty to modify the size (either by adding item or removing item). However, this disadvantage would no longer be a concern for this task. This is also the reason, linked list, binary search tree and queue is not a better option here although they offer much greater efficiency to add and remove item from collection.

On another hand,  any existing items from the sorted array can be easily retrieved using address indexing and therefore the data query process can be very fast and efficient.

4 0
2 years ago
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