This is all you need to do for this one add quotes around the number to make it a string. Then for the question I don't know if you need to answer it but I said that when there is only one string it creates and addition problem of 24 + 24 and then when there are two strings it puts them right next to each other making it look like the number 2424.
COMPLETE QUESTION
Which of the following is false?
a. A subclass is often larger than its super class.
b. A super class is object is a subclass object.
c. The class following the extends keyword in a class declaration is that direct super class of the class being declared.
d. Java uses interfaces to provide the benefits of multiple inheritance
Answer:
B) A super class is object is a subclass object.
Explanation:
In object oriented programming, the concept of inheritance is greatly utilized, this refers to deriving a class from another class. The derived class is the sub-class and it is derived from its super class, as a matter of fact in Java programming language, all classes are derived from some other class. Objects are made from classes with their state (fields) and behavior (methods) since objects are made from classes, the objects of the super class will not be the same as that of the subclass.
Solution :
class Employee:
#Define the
#constructor.
def __
__(
, ID_number, 
, email):
#Set the values of
#the data members of the class.
= name
_number = ID_number
= salary
self.email_address = email
#Define the function
#make_employee_dict().
def make_employee_dict(list_names, list_ID, list_salary, list_email):
#Define the dictionary
#to store the results.
employee_dict = {}
#Store the length
#of the list.
list_len = len(list_ID)
#Run the loop to
#traverse the list.
for i in range(list_len):
#Access the lists to
#get the required details.
name = list_names[i]
id_num = list_ID[i]
salary = list_salary[i]
email = list_email[i]
#Define the employee
#object and store
#it in the dictionary.
employee_dict[id_num] = Employee(name, id_num, salary, email)
#Return the
#resultant dictionary.
return employee_dict
Answer:
Available Options are :
A <b>
B <l>
C <body>
D <small>
Ans : A <b>
Explanation:
Normally AD and BC are written in bold letters.
for example : The terms anno Domini (AD) and before Christ (BC).
Within available option the best option to choose is <b>
The <body> element used to define the document body.
The <small> tag used to defines smaller text
But, the best option to choose is in case if they are using the HTML5 then html <time> element will be used to display BC date and AD dates.
for ex : <time datetime="-314-07-01"
calendar="Ancient Roman">1 July 314 BC</time>
Answer:
I get 0x55 and this the linking address of the main function.
use this function to see changes:
/* bar6.c */
#include <stdio.h>
char main1;
void p2()
{
printf("0x%X\n", main1);
}
Output is probably 0x0
you can use your original bar6.c with updaated foo.c
char main;
int main() // error because main is already declared
{
p2();
//printf("Main address is 0x%x\n",main);
return 0;
}
Will give u an error
again
int main()
{
char ch = main;
p2(); //some value
printf("Main address is 0x%x\n",main); //some 8 digit number not what printed in p2()
printf("Char value is 0x%x\n",ch); //last two digit of previous line output
return 0;
}
So the pain in P2() gets the linking address of the main function and it is different from address of the function main.
Now char main (uninitialized) in another compilation unit fools the compiler by memory-mapping a function pointer on a char directly, without any conversion: that's undefined behavior. Try char main=12; you'll get a multiply defined symbol main...
Explanation:
