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Elden [556K]
2 years ago
8

Matt is a senior developer for Cyber Protect, a company that helps secure management information systems. Matt's new task is to

break into the computer system of one of Cyber Protect's top clients to identify system vulnerabilities and plug the holes. What type of hacker is Matt?
Computers and Technology
1 answer:
Len [333]2 years ago
4 0

Answer:

white-hat hacker

Explanation:

The white-hat hacker is also called as ethical hacking. The white hat hacker is the security of the computer in an ethical manner by some experts it specializing in system testing and other test modules of computer is to ensure the security of the information security of an organization.

As Matt is a  developer for protecting the Cyber in a company The Matt creates secure management information systems. it divides the new task into the computer So Matt is a white-hat hacker in that organization

You might be interested in
Leena needs to manually update the TOC and would prefer not to change the styles in the document.
Lady_Fox [76]

<u>Answer:</u>

<em>Using References tab. Table of Contents group, Update Table </em>

<u>Explanation:</u>

Changes in the table of content is easy to do in word application. The changes might be only for a page number or heading or it might be anything. Based on the need, word allows you to do by using References tab.

<em>Step 1:</em><em> Goto References tab Contents group Update table </em>

<em>Step 2:</em><em> Choose Update Page number only to update only the page numbers in TOC. This would ignore the changes in headings. </em>

<em>Step 3:</em><em> Update Entire table would update the whole table. </em>

8 0
2 years ago
Read 2 more answers
Do Exercise 6.4 from your textbook using recursion and the is_divisible function from Section 6.4. Your program may assume that
Reika [66]

Answer:

Here is the python method:

def is_power(n1, n2): # function that takes two positive integers n1 and n2 as arguments

   if(not n1>0 and not n2>0): #if n1 and n2 are not positive integers

       print("The number is not a positive integer so:") # print this message if n1 and n2 are negative

       return None # returns none when value of n1 and n2 is negative.

   elif n1 == n2: #first base case: if both the numbers are equal

       return True #returns True if n1=n2

   elif n2==1: #second base case: if the value of n2 is equal to 1

       return False #returns False if n2==1

   else: #recursive step

       return is_divisible(n1, n2) and is_power(n1/n2, n2) #call divisible method and is_power method recursively to determine if the number is the power of another

Explanation:

Here is the complete program.

def is_divisible(a, b):

   if a % b == 0:

       return True

   else:

       return False

def is_power(n1, n2):

   if(not n1>0 and not n2>0):

       print("The number is not a positive integer so:")  

       return None  

   elif n1 == n2:

       return True

   elif n2==1:

       return False

   else:

       return is_divisible(n1, n2) and is_power(n1/n2, n2)  

print("is_power(10, 2) returns: ", is_power(10, 2))

print("is_power(27, 3) returns: ", is_power(27, 3))

print("is_power(1, 1) returns: ", is_power(1, 1))

print("is_power(10, 1) returns: ", is_power(10, 1))

print("is_power(3, 3) returns: ", is_power(3, 3))

print("is_power(-10, -1) returns: ", is_power(-10, -1))  

The first method is is_divisible method that takes two numbers a and b as arguments. It checks whether a number a is completely divisible by number b. The % modulo operator is used to find the remainder of the division. If the remainder of the division is 0 it means that the number a is completely divisible by b otherwise it is not completely divisible. The method returns True if the result of a%b is 0 otherwise returns False.

The second method is is_power() that takes two numbers n1 and n2 as arguments. The if(not n1>0 and not n2>0) if statement checks if these numbers i.e. n1 and n2 are positive or not. If these numbers are not positive then the program prints the message: The number is not a positive integer so. After displaying this message the program returns None instead of True of False because of negative values of n1 and n2.

If the values of n1 and n2 are positive integers then the program checks its first base case: n1 == n2. Suppose the value of n1 = 1 and n2 =1 Then n1 is a  power of n2 if both of them are equal. So this returns True if both n1 and n2 are equal.

Now the program checks its second base case n2 == 1. Lets say n1 is 10 and n2 is 1 Then the function returns False because there is no positive integer that is the power of 1 except 1 itself.

Now the recursive case return is_divisible(n1, n2) and is_power(n1/n2, n2)  calls is_divisible() method and is_power method is called recursively in this statement. For example if n1 is 27 and n2 is 3 then this statement:

is_divisible(n1, n2) returns True because 27 is completely divisible by 3 i.e. 27 % 3 = 0

is_power(n1/n2,n2) is called. This method will be called recursively until the base condition is reached. You can see it has two arguments n1/n2 and n2. n1/n2 = 27/3 = 9 So this becomes is_power(9,3)

The base cases are checked. Now this else statement is again executed  return is_divisible(n1, n2) and is_power(n1/n2, n2) as none of the above base cases is evaluated to true. when is_divisible() returns True as 9 is completely divisible by 3 i.e. 9%3 =0 and is_power returns (9/3,3) which is (3,3). So this becomes is_power(3,3)

Now as value of n1 becomes 3 and value of n2 becomes 3. So the first base case elif n1 == n2: condition now evaluates to true as 3=3. So it returns True. Hence the result of this statement print("is_power(10, 2) returns: ", is_power(10, 2))  is:                                                                                                

is_power(27, 3) returns:  True

7 0
2 years ago
Which of the following is NOT a method in which a macro can be run?
liubo4ka [24]
C....................
7 0
2 years ago
Company A is setting up a network of mostly Windows machines. Which networking file system protocol would you recommend for maxi
maxonik [38]

Answer:

For maximum interoperability, NFSv4 is recommended.

Explanation:

When setting up a network of mostly windows machines, it is better to use NFSv4 because it includes performance improvements, mandates strong security, and a stateful protocol.

4 0
2 years ago
python (Business: check ISBN-10) An ISBN-10 (International Standard Book Number) consists of 10 digits: d1d2d3d4d5d6d7d8d9d10. T
iogann1982 [59]

Answer:

<em>The programming language is not stated;</em>

<em>However, I'll answer this question using C++ programming language</em>

<em>The program uses few comments; See explanation section for more detail</em>

<em>Also, the program assumes that all input will always be an integer</em>

#include<iostream>

#include<sstream>

#include<string>

using namespace std;

int main()

{

string input;

cout<<"Enter the first 9 digits of an ISBN as a string: ";

cin>>input;

//Check length

if(input.length() != 9)

{

 cout<<"Invalid input\nLength must be exact 9";

}

else

{

 int num = 0;

//Calculate sum of products

for(int i=0;i<9;i++)

{

 num += (input[i]-'0') * (i+1);    

}

//Determine checksum

if(num%11==10)

{

 input += "X";

 cout<<"The ISBN-10 number is "<<input;

}

else

{

 ostringstream ss;

 ss<<num%11;

 string dig = ss.str();

 cout<<"The ISBN-10 number is "<<input+dig;

}

}  

 return 0;

}

Explanation:

string input;  -> This line declares user input as string

cout<<"Enter the first 9 digits of an ISBN as a string: ";  -> This line prompts the user for input

cin>>input;  -> The user input is stored here

if(input.length() != 9)  { cout<<"Invalid input\nLength must be exact 9";  }  -> Here, the length of input string is checked; If it's not equal to then, a message will be displayed to the screen

If otherwise, the following code segment is executed

else  {

int num = 0; -> The sum of products  of individual digit is initialized to 0

The sum of products  of individual digit is calculated as follows

for(int i=0;i<9;i++)

{

num += (input[i]-'0') * (i+1);

}

The next lines of code checks if the remainder of the above calculations divided by 11 is 10;

If Yes, X is added as a suffix to the user input

Otherwise, the remainder number is added as a suffix to the user input

if(num%11==10)  {  input += "X";  cout<<"The ISBN-10 number is "<<input; }

else

{

ostringstream ss;

ss<<num%11;

string dig = ss.str();

cout<<"The ISBN-10 number is "<<input+dig;

}

}  

5 0
2 years ago
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