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faust18 [17]
2 years ago
11

Produce a list named prime_truths which contains True for prime numbers and False for nonprime numbers in the range [2,100]. We

provide a function is_prime to assist you with this. Call it like this: is_prime( 5 ). Use lambda, map, filter, and list comprehensions as you see fit. You should not need to use a conventional for loop outside of a comprehension.
Computers and Technology
1 answer:
LenKa [72]2 years ago
3 0

Answer:

  1. def is_prime(n):
  2.    for i in range(2, n):
  3.        if(n % i == 0):
  4.            return False  
  5.    return True  
  6. prime_truths = [is_prime(x) for x in range(2,101)]
  7. print(prime_truths)

Explanation:

The solution code is written in Python 3.

Presume there is a given function is_prime (Line 1 - 5) which will return True if the n is a prime number and return False if n is not prime.

Next, we can use the list comprehension to generate a list of True and False based on the prime status (Line 7). To do so, we use is_prime function as the expression in the comprehension list and use for loop to traverse through the number from 2 to 100. The every loop, one value x will be passed to is_prime and the function will return either true or false and add the result to prime_truth list.

After completion of loop within the comprehension list, we can print the generated prime_truths list (Line 8).

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