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Svetach [21]
2 years ago
11

The code below assigns the 5th letter of each word in food to the new list fifth. However, the code currently produces errors. I

nsert a try/except clause that will allow the code to run and produce of list of the 5th letter in each word. If the word is not long enough, it should not print anything out. Note: The pass statement is a null operation; nothing will happen when it executes.
food = ["chocolate", "chicken", "corn
fifth = []
for x in food:
fifth.append(x[4])
Computers and Technology
1 answer:
Mrrafil [7]2 years ago
6 0

Answer:

Answered below

Explanation:

foods = ["chocolate", "chicken", "corn"]

fifth_char = []

for food in foods:

"""Add a try statement to add fifth character to fifth_char list. If word is not long enough, the except part executes the the pass and nothing is printed.""'

try:

fifth_char.append(food[4])

except:

pass

#print out elements in new list

for c in fifth_char:

print(c)

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#Write a function called fancy_find. fancy_find should have #two parameters: search_within and search_for. # #fancy_find should
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Answer:

Here is the Python program:

def fancy_find(search_within , search_for):  # function definition of fancy_find function that takes two parameters

   index = 0  #to store the index of search_within where the search_for string is found

   if search_for in search_within:  #checks if the string search_for is present in string search_within

       sf = search_for[0]  #points to the first character of the search_for

       for sw in search_within:  #iterates through search_within

           if sw == sf:  #if the first character of search_for is equal to the character at sw index of search_within

               if search_within[index:index+len(search_for)] == search_for:  #checks if the value of search_for is found in search_within

                   print(search_for,"found at index",index,"!")  #if above condition is true prints the message "[search_for] found at index [index]!", with [search_for] and [index] replaced by the value of search_for and the index at which it is found

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#following two statements are used to test the working of above function

print(fancy_find("ABCDEF", "DEF"))  #calls fancy_find() passing "ABCDEF" as search_within and "DEF" as search_for

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Explanation:

The program is well explained in the comments. I will explain the working of the function with the help of an example:

Suppose

search_within = "ABCDEF"

search_for = "DEF"

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sw contains the second character of search_within  i.e. B

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index += 1 This increases the value of index by 1. index was initialized to 0 so now it becomes  2. Hence index=2

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sw contains the third character of search_within  i.e. C

if sw == sf: condition checks if the first character of the search_for i.e. D is equal to sw i.e. C Its not true so the program control moves to this statement:

index += 1 This increases the value of index by 1. index was initialized to 0 so now it becomes  3. Hence index=3

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sw contains the third character of search_within  i.e. D

if sw == sf: condition checks if the first character of the search_for i.e. D is equal to sw i.e. D. Its true so so the program control moves to this statement:

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search_for = DEF so

if search_within[3:3+3] == search_for: checks if

search_within[3:3+3] = DEF is equals to search_for = DEF

Yes it is true so

print(search_for,"found at index",index,"!") statement is executef which prints the following message:

DEF found at index 3!

This output is because search_for = "DEF" and index=3

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