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8090 [49]
1 year ago
12

The microprogram counter (MPC) contains the address of the next microcode statement for the Mic1 emulator to execute. The MPC va

lue is either the next sequential microcode instruction in the control store (PROM), or a microcode instruction in the control store pointed to by the ADDR bits in the current executing microinstruction. What part of the current executing microcode instruction determines the value placed in the MPC
Computers and Technology
1 answer:
Ray Of Light [21]1 year ago
6 0

Answer:

MAR bit

Explanation:

The MPC computers area set of software and hardware standards that was developed by the consortium of computer firms which is led by Microsoft. It contains the address of a next microcode for the Mic1 emulator foe execution.

The part of the executing microcode instruction that determines the value which is placed in the MOC is the MAR bit. The MAR is the memory address register in the CPU which stores the memory address or such addresses to which some data will be sent and also stored.

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A technician has been asked to test an inkjet printer purchased 6 months ago that is being pulled from stock and put into use fo
kodGreya [7K]

Answer:

The answer to the following question is to Replace the cartridge with a new one.

Explanation:

An inkjet cartridge or ink cartridge is the component or container of the inkjet printer which contains the ink that deposited on the paper during the printing.  

Each of the inkjet cartridge reserve the one or more ink and the other procedure also adds a chip and electronic contacts which communicates with printer.

6 0
2 years ago
A blood bank maintains two tables - DONOR, with information about people who are willing to donate blood and ACCEPTOR, with info
Kipish [7]

Answer:

The sql query is given below.

Since we need to count of males and females for a particular blood group, we put xxx for the blood group.

SELECT COUNT(SELECT DID FROM DONOR WHERE GENDER LIKE "M%") as Male_Donors,

COUNT(SELECT DID FROM DONOR WHERE GENDER LIKE "F%") as Female_Donors

FROM DONOR

WHERE BG = xxx;

Explanation:

The clauses in the query are as follows.

1. SELECT: all the columns required in the output are put in this clause.

2. FROM JOIN ON: the table(s) from which the above columns are taken are put in this clause.

3. WHERE: any condition required to filter the output is put in this clause.

The query is explained below.

1. Find the number of male donors. Number of anything can be found using COUNT() function. A query is required since gender is included in deciding the type of donor.

2. The query is defined to find number of male donors as follows.

COUNT( SELECT DID FROM DONOR WHERE GENDER LIKE "M%"; )

3. In the previous query, LIKE operator is used since it is not defined what value is stored for male donors.

4. Similarly, the query to find the number of female donors is formed.

COUNT( SELECT DID FROM DONOR WHERE GENDER LIKE "F%"; )

5. Next, the final query is formed as follows.

SELECT: both COUNT() functions will come here.

FROM: table name

WHERE: specific blood group will be put here

GROUP BY: this clause is optional and is not used in this query.

HAVING: this clause is optional and is not used in this query.

6. The query after putting all clauses is shown below.

SELECT COUNT(SELECT DID FROM DONOR WHERE GENDER LIKE "M%"),

COUNT(SELECT DID FROM DONOR WHERE GENDER LIKE "F%")

FROM DONOR

WHERE BG = xxx;

7. Alias is used in the above query for each column to get the final query.

SELECT COUNT(SELECT DID FROM DONOR WHERE GENDER LIKE "M%") as Male_Donors, COUNT(SELECT DID FROM DONOR WHERE GENDER LIKE "F%") as Female_Donors

FROM DONOR

WHERE BG = xxx;

7 0
2 years ago
Which is true for a hosted blog software
professor190 [17]
Since you have not provided the choices wherein I will have to choose from to arrive at an answer, I will just explain to you the concept revolving around a hosted blog software. Hosted blog software are basically installed by the owner of the web server in which among its famous platforms is the Blogger.
7 0
2 years ago
Read 2 more answers
The molecule 2,2-diisopropylheptane is incorrectly named. what is the correct name?
pentagon [3]
Isopropyl is: CH3 - CH - CH3
                                |

Heptane is: CH3 - CH2 - CH2 - CH2 - CH2 - CH2 - CH3

Then 2,2 isopropyl heptane is:

CH3 - CH - CH3
           |
CH3 - C - CH2 - CH2 - CH2 - CH2 - CH3
           |
CH3 - CH - CH3.

There you can count that the longest carbon chain has 8 carbon atoms.
So the right name is of an octane.

I will rearrange the chain to show the 8 carbon chain in a row:

           CH3   CH3
           |          |
CH3 - CH -   C - CH2 - CH2 - CH2 - CH2 - CH3
                      |
           CH3 - CH - CH3

Now, you can see that the right name is 3 isopropyl - 2, 3 dimethyl octane




5 0
2 years ago
Assume that you have a list of n home maintenance/repair tasks (numbered from 1 to n ) that must be done in numeric order on you
tangare [24]

Answer:

Explanation:

(a) The recurrence relation for the given problem is :

T(n) = T(n-1) + T(n-4) + 1

(b) The O(n) time recursive algorithm with memoization for the above recurrence is given below :

Create a 1-d array 'memo' of size, n (1-based indexing) and initialize its elements with -1.

func : a recursive function that accepts the cost array and startingJobNo and returns the minimum cost for doing the jobs from startingJobNo to n.

Algorithm :

func(costArr[], startingJobNo){

if(startingJobNo>n)

then return 0

END if

if(memo[startingJobNo] != -1)

then return memo[startingJobNo];

END if

int ans1 = func(costArr, startingJobNo+1) + costArr[startingJobNo]

int ans2 = func(costArr, startingJobNo+4) + h

memo[startingJobNo] = min(ans1,ans2);

return memo[startingJobNo];

}

(c)

First, Create a 1-d array 'dp' of size, N+1.

dp[0] = 0

bottomUp(int c[]){

for  i=1 till i = n

DO

dp[i] = min(dp[i-1] + c[i], dp[max(0,i-4)] + h);

END FOR

return dp[n];

}

(d)

Modifying the algorithm given in part (b) as follows to know which job to do yourself and in which jobs we need to hire a handyman.

First, Create a 1-d array 'memo' of size, n (1-based indexing) and initialize its elements with -1.

Next, Create another 1-d array 'worker' of size,n (1-based indexing) and initialize its elements with character 'y' representing yourself.

Algorithm :

func(costArr[], startingJobNo){

if(startingJobNo>n)

then return 0

END if

if(memo[startingJobNo] != -1)

then return memo[startingJobNo];

END if

int ans1 = func(costArr, startingJobNo+1) + costArr[startingJobNo]

int ans2 = func(costArr, startingJobNo+4) + h

if(ans2 < ans1)

THEN

for (i = startingJobNo; i<startingJobNo+4 and i<=n; i++)

DO

// mark worker[i] with 'h' representing that we need to hire a mechanic for that job

worker[i] = 'h';

END for

END if

memo[startingJobNo] = min(ans1,ans2);

return memo[startingJobNo];

}

//the worker array will contain 'y' or 'h' representing whether the ith job is to be done 'yourself' or by 'hired man' respectively.

4 0
1 year ago
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