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ValentinkaMS [17]
2 years ago
12

A search box does all of the following EXCEPT ________.

Computers and Technology
2 answers:
Rudik [331]2 years ago
6 0
The answer is the first one
shusha [124]2 years ago
6 0

The answer is option 4. Displays in all windows

A search box acts as a field for a query search for the user to retrieve information from the database. A search box supports instant search whenever possible and returns relevant results within a few seconds.  So option 1 and 2 are correct. You can retrieve your files and folders hidden anywhere on your operating System by quickly doing a search from the start menu. This leaves us with the last option as the correct answer.

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This question involves the creation of user names for an online system. A user name is created based on a user’s first and last
Evgen [1.6K]

Answer:

See explaination

Explanation:

import java.util.*;

class UserName{

ArrayList<String> possibleNames;

UserName(String firstName, String lastName){

if(this.isValidName(firstName) && this.isValidName(lastName)){

possibleNames = new ArrayList<String>();

for(int i=1;i<firstName.length()+1;i++){

possibleNames.add(lastName+firstName.substring(0,i));

}

}else{

System.out.println("firstName and lastName must contain letters only.");

}

}

public boolean isUsed(String name, String[] arr){

for(int i=0;i<arr.length;i++){

if(name.equals(arr[i]))

return true;

}

return false;

}

public void setAvailableUserNames(String[] usedNames){

String[] names = new String[this.possibleNames.size()];

names = this.possibleNames.toArray(names);

for(int i=0;i<usedNames.length;i++){

if(isUsed(usedNames[i],names)){

int index = this.possibleNames.indexOf(usedNames[i]);

this.possibleNames.remove(index);

names = new String[this.possibleNames.size()];

names = this.possibleNames.toArray(names);

}

}

}

public boolean isValidName(String str){

if(str.length()==0) return false;

for(int i=0;i<str.length();i++){

if(str.charAt(i)<'a'||str.charAt(i)>'z' && (str.charAt(i)<'A' || str.charAt(i)>'Z'))

return false;

}

return true;

}

public static void main(String[] args) {

UserName person1 = new UserName("john","smith");

System.out.println(person1.possibleNames);

String[] used = {"harta","hartm","harty"};

UserName person2 = new UserName("mary","hart");

System.out.println("possibleNames before removing: "+person2.possibleNames);

person2.setAvailableUserNames(used);

System.out.println("possibleNames after removing: "+person2.possibleNames);

}

}

8 0
2 years ago
Write the definition of a function named quadratic that receives three double parameters a, b, c. If the value of a is 0 then th
VMariaS [17]

Answer:

#include <iostream>

#include <cmath>

using namespace std;

//initialize function quadratic

void quadratic(double, double, double);

int main() {

   //declare double variables a, b and c

   double a,b,c;

   //take input from user

   cin>>a>>b>>c;

   //call function quadratic

   quadratic(a,b,c);

return 0;

}

void quadratic(double a, double b, double  c){

   double root,n;

   //check if variable a is equal to zero

   if(a==0){

       cout<<"no solution for a=0"<<endl;

       return;

   }

   //check if b squared - 4ac is less than zero

   else

   if(((b*b)-(4*a*c))<0){

       cout<<"no real solutions"<<endl;

       return;

   }

   //print the largest root if the above conditions are not satisfied

   else{

       n=((b*b)-(4*a*c));

       root=(-b + sqrt(n)) / (2*a);

       cout<<"Largest root is:"<<root<<endl;

   }

   return ;

}

Explanation:

Read three double variables a, b and c from the user and pass it to the function quadratic. Check if the value of variable a is equal to zero. If true, print "no solution for a=0". If this condition is false, check if b squared - 4ac is less than zero. If true, print "no real solutions". If this condition is also false, calculate the largest solution using the following formula:

largest root = (-b + square root of (b squared - 4ac)) / (2*a)

Input 1:

2 5 3

Output 2:

Largest root is:-1

Input 2:

5 6 1

Output 2:

Largest root is:-0.2

5 0
2 years ago
PYTHON PROGRAMMING: At one college, the tuition for a full-time student is $8,000 per semester.
lozanna [386]

Answer:

Try :

Semester_Fee = 8000.0

for x in range(1, 6):

   import decimal

   Semester_Fee = Semester_Fee + Semester_Fee *(3/(100*1.0))

   if x==1:

       print("In",x,"year, the tuition will be" ,'$', Semester_Fee, end='.')

   else:

       print("In",x,"years, the tuition will be" ,'$', Semester_Fee, end='.')

6 0
2 years ago
python Consider this data sequence: "3 11 5 5 5 2 4 6 6 7 3 -8". Any value that is the same as the immediately preceding value i
Vika [28.1K]

int firstNumber,secondNumber = -1, duplicates = 0;

do {

cin >> firstNumber;

if ( secondNumber == -1) {

secondNumber = firstNumber;

}else {

if ( secondNumber == firstNumber )

duplicates++;

else

secondNumber = firstNumber;

}

} while(firstNumber > 0 );

cout << duplicates;

7 0
2 years ago
In the simulation, player 2 will always play according to the same strategy. The number of coins player 2 spends is based on wha
baherus [9]

The simulation, player 2 will always play according to the same strategy.

Method getPlayer2Move below is completed by assigning the correct value to result to be returned.

Explanation:

  • You will write method getPlayer2Move, which returns the number of coins that player 2 will spend in a given round of the game. In the first round of the game, the parameter round has the value 1, in the second round of the game, it has the value 2, and so on.

#include <bits/stdc++.h>  

using namespace std;

bool getplayer2move(int x, int y, int n)  

{

   int dp[n + 1];  

   dp[0] = false;  

   dp[1] = true;  

   for (int i = 2; i <= n; i++) {  

       if (i - 1 >= 0 and !dp[i - 1])  

           dp[i] = true;  

       else if (i - x >= 0 and !dp[i - x])  

           dp[i] = true;  

       else if (i - y >= 0 and !dp[i - y])  

           dp[i] = true;  

       else

           dp[i] = false;  

   }  

   return dp[n];  

}  

int main()  

{  

   int x = 3, y = 4, n = 5;  

   if (findWinner(x, y, n))  

       cout << 'A';  

   else

       cout << 'B';  

   return 0;  

}

8 0
2 years ago
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