Answer:
The correct answer to the following question will be "Instruction set architecture".
Explanation:
The Instruction Series Design is a component of the system that is accessible to the compiler and the programmer. It is also the distinction between hardware and software. We will describe in detail the set of instructions used in most of the microprocessors that are used today.
The processor ISA can be represented using 5 categories, these are as follows:
- The RAM Running Memory.
- Amount of clear operating names.
- Location of operands.
- Operations
- Size and type of the operand.
Therefore, Instruction set architecture is the right answer.
<span>The part of the computer that contains the brain, or central processing unit is also known as System Unit.Because Cpu plays a vital role and it is the central component in computer.Without Cpu calculations are not performed by computer.It directs the entire computer system to carry out stored program instructions.</span>
Answer:
EMI (Electromagnetic Interference).
RFI (Radio Frequency Interference).
Explanation:
The new ethernet cable is installed near the ceiling and it is close to fluorescent lights and electrical equipment.Since the ethernet cable is carrying corrupt and distorted data so it needs protection.The protection should be from EMI(Electromagnetic Interference) and RFI(Radio Frequency Interference).
Format and mount the drive.
Formatting erases the drive and sets it up so the system can read and write to it.
Mounting the drive allows the system to have access to the drive and read and write to it.
If you want to get more specific in Windows you can open registry editor and change the paths of the drive to save in the new location.
The below code will help you to solve the given problem and you can execute and cross verify with sample input and output.
#include<stdio.h>
#include<string.h>
int* uniqueValue(int input1,int input2[])
{
int left, current;
static int arr[4] = {0};
int i = 0;
for(i=0;i<input1;i++)
{
current = input2[i];
left = 0;
if(current > 0)
left = arr[(current-1)];
if(left == 0 && arr[current] == 0)
{
arr[current] = input1-current;
}
else
{
for(int j=(i+1);j<input1;j++)
{
if(arr[j] == 0)
{
left = arr[(j-1)];
arr[j] = left - 1;
}
}
}
}
return arr;
}