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Natalka [10]
2 years ago
6

Skylar is viewing her personal and business calendar in a side-by-side fashion, but she would like to view a single calendar tha

t has appointments and meetings from both personal and business. What should she do?
Configure the Overlay option.
Create a third calendar.
Share the personal and business calendars.
Create a joint calendar and reenter all of the appointments.
Computers and Technology
1 answer:
pogonyaev2 years ago
8 0

Answer:

The solution for the current situation in which Skylar is viewing her personal and business calendar in a side-by-side fashion, but she would like to view a single calendar that has appointments and meetings from both personal and business. is:

Configure the Overlay option.

Explanation:

The reasons behind this answer are that in the first place, creating another calendar is too much work. In the second place, the share of the calendars is not going to help her because that would only allow someone else to watch her calendars. However, using the overlay option will allow her to mix them and create one calendar with all her information.

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natta225 [31]

Answer:

x = 5, the data type is integer( integer data type is for whole numbers)

2. The data type is string

3. The data type is float (float data type is for decimals)

Explanation:

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2 years ago
In this exercise you will debug the code which has been provided in the starter file. The code is intended to take two strings,
vampirchik [111]

Answer:

Here is the corrected program:

import java.util.Scanner; //to accept input from user

public class 02_14_Activity_one { //class name

    public static void main(String[] args) { //start of main method

    Scanner scan = new Scanner(System.in); //creates Scanner class object

  System.out.println("Enter first string"); //prompts user to enter first string

          String s1 = scan.nextLine(); //reads input string from user

  System.out.println("Enter second string"); //prompts user to enter second string

          String s2 = scan.nextLine(); //reads second input string from user

    System.out.println("Enter number of letters from each word"); //enter n

          int n = scan.nextInt(); //reads value of integer n from user

          System.out.println(s1.substring(0,n) + s2.substring(s2.length() - n ));

         } } //uses substring method to print a string made up of the first n letters of s1 and the last n letters of s2.

Explanation:

The errors were:

1.

Scanner scan = Scanner(System.in);

Here new keyword is missing to create object scan of Scanner class.

Corrected statement:

 Scanner scan = new Scanner(System.in);

2.

String s1 = nextLine();  

Here object scan is missing to call nextLine() method of class Scanner

Corrected statement:

String s1 = scan.nextLine();

3.

String s2 = Scanner.nextLine();

Here class is used instead of its object scan to access the method nextLine

Corrected statement:

String s2 = scan.nextLine();

4.

String n = scan.nextLine();

Here n is of type String but n is a whole number so it should be of type int. Also the method nextInt will be used to scan and accept an integer value

Corrected statement:

int n = scan.nextInt();

5.

System.out.println(s1.substring(1,n-1) + s2.substring(s1.length()-n));

This statement is also not correct

Corrected statement:

System.out.println(s1.substring(0,n) + s2.substring(s2.length() - n ));

This works as follows:

s1.substring(0,n) uses substring method to return a new string that is a substring of this s1. The substring begins at the 0th index of s1 and extends to the character at index n.

s2.substring(s2.length() - n ) uses substring method to return a new string that is a substring of this s2. The substring then uses length() method to get the length of s2 and subtracts integer n from it and thus returns the last n characters of s2.

The screenshot of program along with its output is attached.

7 0
2 years ago
Effective character encoding requires:
lidiya [134]

To answer your question the answer would be B compatible browsers

4 0
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Which telecommunications device is widely used in industries that require closed communication?
Stella [2.4K]

The telecommunications device that  is widely used in industries that require closed communication are walkie-talkies. Correct answer: D

Walkie-talkies are hand-held, portable, two-way radio transceivers which enable secure communication between the two points, without being part of a network.

3 0
2 years ago
Read 2 more answers
Return 1 if ptr points to an element within the specified intArray, 0 otherwise.
Paladinen [302]

Answer:

int withinArray(int * intArray, int size, int * ptr) {

      if(ptr == NULL) // if ptr == NULL return 0

            return 0;

      // if end of intArr is reached

      if(size == 0)

          return 0; // element not found

  else  

          {

            if(*(intArray+size-1) == *(ptr)) // check if (size-1)th element is equal to ptr

                   return 1; // return 1

            return withinArray(intArray, size-1,ptr); // recursively call the function with size-1 elements

         }

}

Explanation:

Above is the completion of the program.

4 0
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