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Bumek [7]
1 year ago
13

Define a function UpdateTimeWindow() with parameters timeStart, timeEnd, and offsetAmount. Each parameter is of type int. The fu

nction adds offsetAmount to each of the first two parameters. Make the first two parameters pass by pointer. Sample output for the given program:

Computers and Technology
1 answer:
NARA [144]1 year ago
8 0

Answer:

Here is a UpdateTimeWindow() method with parameters timeStart, timeEnd, and offsetAmount

// the timeEnd and timeStart variables are passed by pointer

void UpdateTimeWindow(int* timeStart, int* timeEnd, int offsetAmount){

// this can also be written as  *timeStart = *timeStart + offsetAmount;

*timeStart += offsetAmount;  //adds value of offsetAmount to that of //timeStart

// this can also be written as  *timeEnd = *timeEnd + offsetAmount;

  *timeEnd += offsetAmount;  } //adds value of offsetAmount to that of //timeEnd

Explanation:

The function has three int parameters timeStart, timeEnd, and offsetAmount.

First two parameters timeStart and End are passed by pointer. You can see the asterisk sign with them. Then in the body of the function there are two statements *timeStart += offsetAmount; and *End+= offsetAmount; in these statements the offsetAmount is added to the each of the two parameters timeStart and timeEnd.

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Explanation:

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Consider a single-platter disk with the following parameters: rotation speed: 7200 rpm; number of tracks on one side ofplatter:
horsena [70]

Answer:

Given Data:

Rotation Speed = 7200 rpm

No. of tracks on one side of platter = 30000

No. of sectors per track = 600

Seek time for every 100 track traversed = 1 ms

To find:

Average Seek Time.

Average Rotational Latency.

Transfer time for a sector.

Total Average time to satisfy a request.

Explanation:

a) As given, the disk head starts at track 0. At this point the seek time is 0.

Seek time is time to traverse from 0 to 29999 tracks (it makes 30000)

Average Seek Time is the time taken by the head to move from one track to another/2

29999 / 2 = 14999.5 ms

As the seek time is one ms for every hundred tracks traversed.  So the seek time for 29,999 tracks traversed is

14999.5 / 100 = 149.995 ms

b) The rotations per minute are 7200

1 min = 60 sec

7200 / 60 = 120 rotations / sec

Rotational delay is the inverses of this. So

1 / 120 = 0.00833 sec

          = 0.00833 * 100

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So there is  1 rotation is at every 0.833 ms

Average Rotational latency is one half the amount of time taken by disk to make one revolution or complete 1 rotation.

So average rotational latency is: 1 / 2r

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So transfer time for a sector is: one disk revolution time / number of sectors

8.333 / 600 = 0.01388 ms = 13.88 μs

d)  Total average time to satisfy a request is calculated as :

Average seek time + Average rotational latency + Transfer time for a sector

= 149.99 ms + 4.165 ms + 0.01388 ms

= 154.168 ms

4 0
2 years ago
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