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Aleksandr [31]
2 years ago
5

5. Assume a computer has a physical memory organized into 64-bit words. Give the word address and offset within the word for eac

h of the following byte addresses: 0, 9, 27, 31,120, and 256.
6. Extend the above exercise by writing a computer program that computes the answer. The program should take a series of inputs that each consist of two values: a word size specified in bits and a byte address. For each input, the program should generate a word address and offset within the word. Note: although it is specified in bits, the word size must be a power of two bytes.

Computers and Technology
1 answer:
spin [16.1K]2 years ago
4 0

Answer:

see explaination and attachment

Explanation:

5.

To convert any byte address, By, to word address, Wo, first divide By by No, the no. of bytes/word, and ignores the remainder. To calculate a byte offset, O, in word, calculate the remainder of By divided by No.

i) 0 : word address = 0/8 = 0 and offset, O = 0 mod 8 = 0

ii) 9 : word address = 9/8 = 1 and offset, O = 9 mod 8 = 1

iii) 27 : word address = 27/8 = 3 and offset, O = 27 mod 8 = 3

iv) 31 : word address = 31/8 = 3 and offset, O = 31 mod 8 = 7

v) 120 : word address = 120/8 = 15 and offset, O = 120 mod 8 = 0

vi) 256 :word address = 256/8 = 32 and offset, O = 256 mod 8 = 0

6. see attachment for the python programming screen shot and output

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Megan has written the following rough draft for her assignment. Choose the correct way to complete each sentence. Sarah is creat
atroni [7]

Answer:

I. hatching

II. filter

Explanation:

Sarah is creating an image. She wants to achieve tonal effects with parallel lines by varying their densities and distribution patterns. She will use <u>hatching</u> to do this. She also wants to add special effects on the image. Therefore, she will use <u>filters</u>.

Hatching refers to an art technique in which parallel lines are used to shade by drawing them closely together.

Stippling is an art technique used in the making of patterns by using small dots.

Filters is a technique of changing image characteristics. It is used to change the picture characteristics & to add special effects to an image such as the shade, contrast, tone, brightness etc.

We therefore see that, <u>hatching</u> and <u>filter</u> are the correct answers respectively

3 0
2 years ago
Mark and John are developing a program using Python. They name a variable 24_hour_mart, but then recognize that this name violat
77julia77 [94]

Answer:

Option 2: Variable names can not begin with a number.

Explanation:

As given Mark and John named a variable as 24_hour_mart while writing a program in python.

While it is forbidden to name a variable starting with any digit, only alphabets (capital and smaller) and underscore can be the first letter of the variable name.

Moreover, by considering the other options given:

  • Variable name can include the underscore (_) between the words. It is used instead of spaces that are not allowed.
  • There is no upper limit for variable length, it can be of any reasonable length and more than 10 characters say 11 or 12 are reasonable.
  • There is no lower limit for variable length, it can be any reasonable length , even it can be of 1 character.

Variables named in python language must not be the keywords as they are reserved for other purposes.

i hope it will help you!

3 0
2 years ago
There are three seating categories at a stadium. Class A seats cost $20, Class B seats cost $15, and Class C seats cost $10. Wri
Westkost [7]

Answer:

Following are the program to this question:

def calculate_income(num,seat):#defining method calculate_income

   if seat=="A": #defining condition for seat a

       return num * 20 #return value

   if seat=="B": #defining condition for seat b

       return num * 15 #return value

   if seat=="C": #defining condition for seat c

       return num * 10 #return value

def show_income(a,b,c): #defining method show_Income

   sum=a+b+c # add total seats income

   print("Income for A class seats: $",a) #print value

   print("Income for B class seats: $",b) #print value

   print("Income for C class seats: $",c) #print value

   print("Total Income: $",sum) #print value

def main(): # defining main method

   a=int(input("Enter class A seats: ")) #input seats a value

   b=int(input("Enter class B seats: ")) #input seats b value

   c=int(input("Enter class C seats: ")) #input seats c value

   a_income=calculate_income(a,"A")  #call method for seat a

   b_income=calculate_income(b,"B") #call method for seat b

   c_income=calculate_income(c,"C") #call method for seat c

   show_income(a_income,b_income,c_income) # call method show_income for print all seat value

main()

Output:

Enter class A seats: 2

Enter class B seats: 3

Enter class C seats: 2

Income for A class seats: $ 40

Income for B class seats: $ 45

Income for C class seats: $ 20

Total Income: $ 105

Explanation:

The description of the above program can be described as follows:

  • In the above python program, three methods "calculate_income, show_income, and the main method" were defined.  
  • The method "calculate_income" accepts two-variable "num and seat" as the parameter, inside the method a three if block is used, that calculate all types of seat class rate and returns its value.
  • In the "show_income", we add all the seat value in the sum variable and use the print method, that prints all seat cost, and total cost.
  • In the main method, we input all seat value from user input and pass into the calculate_income method and collect all the return value, after calculating calculate_income we pass its return value into the show_income method, that prints all value.
5 0
2 years ago
Write two methods: encrypt and decrypt. encrypt should #take as input a string, and return an encrypted version #of it according
Harman [31]

Answer:

The code is given below with appropriate comments

Explanation:

CIPHER = (("D", "A", "V", "I", "O"),

         ("Y", "N", "E", "R", "B"),

         ("C", "F", "G", "H", "K"),

         ("L", "M", "P", "Q", "S"),

         ("T", "U", "W", "X", "Z"))

# Add your code here!

def encrypt(plaintext):

   theList = []

   for char in plaintext:

       if char.isalpha():

           char = char.upper()

           if char == "J":

               char = "I"

           theList.append(char)

   if len(theList) % 2 == 1:

       theList.append("X")

   for i in range(0, len(theList), 2):

       if theList[i] == theList[i + 1]:

           theList[i + 1] = "X"

       findex = [-1, -1]

       sindex = [-1, -1]

       for j in range(len(CIPHER)):

           for k in range(len(CIPHER)):

               if theList[i] == CIPHER[j][k]:

                   findex = [j, k]

               if theList[i + 1] == CIPHER[j][k]:

                   sindex = [j, k]

       # same row

       if (findex[0] == sindex[0]):

           findex[1] += 1

           sindex[1] += 1

           if findex[1] == 5:

               findex[1] = 0

           if sindex[1] == 5:

               sindex[1] = 0

           theList[i] = CIPHER[findex[0]][findex[1]]

           theList[i + 1] = CIPHER[sindex[0]][sindex[1]]

       # same column

       elif (findex[1] == sindex[1]):

           findex[0] += 1

           sindex[0] += 1

           if findex[0] == 5:

               findex[0] = 0

           if sindex[0] == 5:

               sindex[0] = 0

           theList[i] = CIPHER[findex[0]][findex[1]]

           theList[i + 1] = CIPHER[sindex[0]][sindex[1]]

       else:

           theList[i] = CIPHER[findex[0]][sindex[1]]

           theList[i + 1] = CIPHER[sindex[0]][findex[1]]

   return "".join(theList)

def decrypt(ciphertext):

   theString = ""

   findex = [-1, -1]

   sindex = [-1, -1]

   for i in range(0, len(ciphertext), 2):

       for j in range(len(CIPHER)):

           for k in range(len(CIPHER)):

               if ciphertext[i] == CIPHER[j][k]:

                   findex = [j, k]

               if ciphertext[i + 1] == CIPHER[j][k]:

                   sindex = [j, k]

       if (findex[0] == sindex[0]):

           findex[1] -= 1

           sindex[1] -= 1

           if findex[1] == -1:

               findex[1] = 4

           if sindex[1] == -1:

               sindex[1] = 4

           theString += CIPHER[findex[0]][findex[1]]

           theString += CIPHER[sindex[0]][sindex[1]]

       # same column

       elif (findex[1] == sindex[1]):

           findex[0] -= 1

           sindex[0] -= 1

           if findex[0] == -1:

               findex[0] = 4

           if sindex[0] == -1:

               sindex[0] = 4

           theString += CIPHER[findex[0]][findex[1]]

           theString += CIPHER[sindex[0]][sindex[1]]

       else:

           theString += CIPHER[findex[0]][sindex[1]]

           theString += CIPHER[sindex[0]][findex[1]]

   return theString

# Below are some lines of code that will test your function.

# You can change the value of the variable(s) to test your

# function with different inputs.

#

# If your function works correctly, this will originally

# print: QLGRQTVZIBTYQZ, then PSHELXOWORLDSX

print(encrypt("PS. Hello, worlds"))

print(decrypt("QLGRQTVZIBTYQZ"))

5 0
2 years ago
In an ISDN connection, what amount of throughput did a single B channel provide?
Flura [38]

Answer:

64 Kbps

Explanation:

ISDN stands for Integrated Services Digital Network. It makes use of two types of channels:

B type : which is used for carrying data/voice

D type : which carries control and signalling information.

ISDN supports two different service levels:

  • Basic Rate Interface (BRI) - home and small users
  • Primary Rate Interface(PRI) - larger enterprise scenarios

Both BRI and PRI make use of set of B and D type channels for data transfer.

Each B channel or Bearer channel has a throughput of 64 Kbps whereas D channel has a throughput of 16 Kbps.

3 0
2 years ago
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