Answer:
The AES decryption time is 8 minutes
Explanation:
GIVEN THAT:
The 1 GByte is equal to 230 bytes and equal to 233 bits
The RSA decryption time is calculated as = 233 / (100*230 )
= 83886. 06 seconds
= 23 hours
The RSA decryption time is 23 hours
The AES decryption time is calculated as = 233 / (17 * 230 )
= 481.81 seconds
= 8 minutes .
The AES decryption time is 8 minutes
Answer:
- m = 3
- n = 20
-
- triList = []
- current = 0
- for i in range(1, n + 1):
- current = current + i
- if(current >= m and current <= n):
- triList.append(current)
-
- print(triList)
Explanation:
The solution code is written in Python 3.
Firstly, create variable m and n and set the value 3 and 20 to the variables (Line 1 -2)
Create a triangle number list (Line 4) and another variable current to hold the value of current total of triangle number (Line 5).
Create a for loop and iterate through the number between m and n (Line 6). Calculate the current total of triangle number (Line 7) and proceed to check if the current triangle number is bigger or equal to m and smaller and equal to n, add the current triangle number to triList (Line 8-9).
Print the triList (Line 11) and we shall get [3, 6, 10, 15]
Answer:
The answer is "Contained in"
Explanation:
Its term refers to the classified information of the extraction process, even though outlined in an authorized categorization instruction origin without extra explanation or review, and incorporates these data in a new document.
In this concept, the information appears in the extracted word-for-word, its definition of 'in' will apply, or if its data has been paraphrased or restated from the current text, that's why we can say that this concept derivatively classifies the statement in new documents.
Answer:
Explanation:
The following code is written in Java. It is a very simple three line statement (assuming that the random library was imported) that chooses a random integer value between 5 and 5000 and prints it to the screen using the println statement.
Random rand = new Random();
int randomNum = rand.nextInt((5000 - 5) + 1) + 5;
System.out.println(randomNum);
The random number generator is initialized and given a value between 5 and 5000. Since random number Generator will generate a number between 0 and the given value then subtracting 5 from the initial generated number makes sure that it is not more than 5000 and then adding 1 and 5 after wards makes sure that it is more than 5 always.
Answer:
c.
Explanation:
I believe that in this scenario, the best option for this data would be a hash table using open addressing with 1,800 entries. Hash tables consume more memory than lists but it makes up for it with much faster response time speeds. This is because hash tables work on a key:value system therefore, the license plate can easily be grabbed from the database extremely quickly by just plugging in the plate number. Doing so will retrieve all of the saved information from that license plate. That is why hash tables have a constant time complexity of O(1)
