Answer:
Start the algorithm and check the weight of the ship. Load the crystalline to the ship. Check to see if the ship weighs ship weight + k pound crystalline, if less, add more crystalline. If excess, remove the excess crystalline, but if the weight meets the condition, then take off with the loaded ship to planet sigma.
Explanation:
The algorithm continuously checks the weight of the ship on loading with the calculated sum of the ship and k pound crystalline weight. The ship is able to load the correct maximum amount of crystalline to the planet sigma.
Answer:
The method in python is as follows:
class myClass:
def printRange(min,max):
for i in range(min, max+1):
print("{"+str(i)+"} ", end = '')
Explanation:
This line declares the class
class myClass:
This line defines the method
def printRange(min,max):
This line iterates from min to max
for i in range(min, max+1):
This line prints the output in its required format
print("{"+str(i)+"} ", end = '')
<span>Level : 1,2,3,4,5,6,7,8,9,10,11,12
Gems : 13 to 123
We have to increase from 13 to 123 over a span of 11 levels.
That's an increase of 110 over 11 levels.
110 / 11 = 10
So we go up 10 gems each level
Level : 1,2,3,4,5,6,7,8,9,10,11,12
Gems : 13 23 33 43 53 63 73 83 93 103 113 123</span>
Answer:
The answer is "Using the DoD 5220.22-M method and Degauss media with a magnet".
Explanation:
The "DoD Standard" is a term used during the data sanitizing industry and refers to DoD 5220.22-M. The simplest ways are being used to help eliminate the previously stored data, by deleting hard disc storage facilities with the same data wherever that used a sequence of all zeros.
The sparging eliminates statistics to entirely delete the gravitational flux from electronic media. Hard drives as well as other data storage devices, for example, computer tapes, retain magnetic data. It could no longer be seen as storage after a disk is degaussed.
Answer:
n = int(input("Enter the n (positive odd integer): "))
for i in range(1, n+1, 2):
print(i*"*")
for i in range(n-2, 0, -2):
print(i*"*")
Explanation:
*The code is in Python.
Ask the user to enter the n
Create a for loop that iterates from 1 to n, incrementing by 2 in each iteration. Print the corresponding number of asterisks in each iteration
Create another for loop that iterates from n-2 to 1, decrementing by 2 in each iteration. Print the corresponding number of asterisks in each iteration
