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daser333 [38]
2 years ago
8

Ming is building an inexpensive computer to use for her online classes, and needs to purchase Windows. What is the most cost-eff

ective way Ming can purchase and activate a selected version of Windows?
Computers and Technology
1 answer:
kodGreya [7K]2 years ago
5 0

The correct answer is; She can purchase OEM codes from e-commerce sites such as Amazon or eBay.

Further Explanation:

There are some sites where OEM codes cost around 110$ or higher. it will depend on which edition of Windows she plans on purchasing. The official Microsoft website sells the codes for much higher than other e-commerce sites.

There is some ways to get the older Windows for free online using a software key from a previous purchase from a friend or one you have purchased in the past. There is also a free trial that can be used for 7 days and possibly 30 days.

Learn more about Windows at brainly.com/question/1705478

#LearnwithBrainly

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Access to sensitive or restricted information is controlled describes which of the key communications and information systems pr
Viktor [21]

Answer:

C: Security

Explanation:

Communications and information systems principles need to be, among other things, secure. They need to be able to protect sensitive information from those who intentionally not need to know. Some incident information like voice, networks, and data, are very sensitive and thus, should be secure to the right levels and should comply with privacy laws and data protection.

4 0
2 years ago
Write the definition of a function named quadratic that receives three double parameters a, b, c. If the value of a is 0 then th
VMariaS [17]

Answer:

#include <iostream>

#include <cmath>

using namespace std;

//initialize function quadratic

void quadratic(double, double, double);

int main() {

   //declare double variables a, b and c

   double a,b,c;

   //take input from user

   cin>>a>>b>>c;

   //call function quadratic

   quadratic(a,b,c);

return 0;

}

void quadratic(double a, double b, double  c){

   double root,n;

   //check if variable a is equal to zero

   if(a==0){

       cout<<"no solution for a=0"<<endl;

       return;

   }

   //check if b squared - 4ac is less than zero

   else

   if(((b*b)-(4*a*c))<0){

       cout<<"no real solutions"<<endl;

       return;

   }

   //print the largest root if the above conditions are not satisfied

   else{

       n=((b*b)-(4*a*c));

       root=(-b + sqrt(n)) / (2*a);

       cout<<"Largest root is:"<<root<<endl;

   }

   return ;

}

Explanation:

Read three double variables a, b and c from the user and pass it to the function quadratic. Check if the value of variable a is equal to zero. If true, print "no solution for a=0". If this condition is false, check if b squared - 4ac is less than zero. If true, print "no real solutions". If this condition is also false, calculate the largest solution using the following formula:

largest root = (-b + square root of (b squared - 4ac)) / (2*a)

Input 1:

2 5 3

Output 2:

Largest root is:-1

Input 2:

5 6 1

Output 2:

Largest root is:-0.2

5 0
2 years ago
Write a while loop that prints userNum divided by 2 (integer division) until reaching 1. Follow each number by a space. Example
jasenka [17]

Answer:

public class Main

{

public static void main(String[] args) {

    int userNum = 40;

    while(userNum > 1){

        userNum /= 2;

        System.out.print(userNum + " ");

    }

}

}

Explanation:

*The code is in Java.

Initialize the userNum

Create a while loop that iterates while userNum is greater than 1. Inside the loop, divide the userNum by 2 and set it as userNum (same as typing userNum = userNum / 2;). Print the userNum

Basically, this loop will iterate until userNum becomes 1. It will keep dividing the userNum by 2 and print this value.

For the values that are smaller than 1 or even for 1, the program outputs nothing (Since the value is not greater than 1, the loop will not be executed).

4 0
2 years ago
Read first a user's given name followed by the user's age from standard input. Then use an ofstream object named outdata to writ
Stells [14]

Answer:

/*

* Program to write data to text file.

*/

#include<iostream>

#include<fstream>

#include<string.h>

using  namespace std;

int main()

{

//Variable to name and age of a person.

string name;

int age;

cout<<"Enter your name"<<endl;

cin>>name;

cout<<"Enter your age"<<endl;

cin>>age;

     //Creating object of ofstream.

   ofstream file;

   file.open ("outdata.txt");

   //Writing data to file named outdata.txt

   file<<name<<" "<<age;

   file.close();

 

}

Output:

Enter your name

John

Enter your age

25

Content of Output.txt:

John 25

Explanation:

To write data to a file  ofstream object is used. An ofstream object file is created first and then using this object a file named "outdata.txt" is created.

Finally using shift operator (<<), by means  of operator overloading, name and age of  person is transferred to file outdata.txt.

8 0
2 years ago
Consider the following sequence of instructions:
omeli [17]

Answer:

i think the answer is c hope this helps!!!!!

Explanation:

8 0
2 years ago
Read 2 more answers
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