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daser333 [38]
2 years ago
8

Ming is building an inexpensive computer to use for her online classes, and needs to purchase Windows. What is the most cost-eff

ective way Ming can purchase and activate a selected version of Windows?
Computers and Technology
1 answer:
kodGreya [7K]2 years ago
5 0

The correct answer is; She can purchase OEM codes from e-commerce sites such as Amazon or eBay.

Further Explanation:

There are some sites where OEM codes cost around 110$ or higher. it will depend on which edition of Windows she plans on purchasing. The official Microsoft website sells the codes for much higher than other e-commerce sites.

There is some ways to get the older Windows for free online using a software key from a previous purchase from a friend or one you have purchased in the past. There is also a free trial that can be used for 7 days and possibly 30 days.

Learn more about Windows at brainly.com/question/1705478

#LearnwithBrainly

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What is retrieved from a search containing two terms separated<br> by the AND operator?
egoroff_w [7]

Answer:

A AND B= 1 or 0

1 1  1

0 1  0

1 0  0

0 0 0

So, as explained above if both are 1 we then only get 1, or else we get 0 always in case of AND which is a logical operator, whose output can be 0 or 1 only. This is being depicted above.

Explanation:

If both are 1 we get 1 or always else, we get the output =0.

8 0
2 years ago
Write the 8-bit signed-magnitude, two's complement, and ones' complement representations for each decimal number: +25, + 120, +
pshichka [43]

Answer:

Let's convert the decimals into signed 8-bit binary numbers.

As we need to find the 8-bit magnitude, so write the powers at each bit.

      <u>Sign -bit</u> <u>64</u> <u>32</u> <u>16</u> <u>8</u> <u>4</u> <u>2</u> <u>1</u>

+25 - 0 0 0 1 1 0 0 1

+120- 0 1 1 1 1 0 0 0

+82 - 0 1 0 1 0 0 1       0

-42 - 1 0 1 0 1 0 1 0

-111 - 1 1 1 0 1 1 1 1

One’s Complements:  

+25 (00011001) – 11100110

+120(01111000) - 10000111

+82(01010010) - 10101101

-42(10101010) - 01010101

-111(11101111)- 00010000

Two’s Complements:  

+25 (00011001) – 11100110+1 = 11100111

+120(01111000) – 10000111+1 = 10001000

+82(01010010) – 10101101+1= 10101110

-42(10101010) – 01010101+1= 01010110

-111(11101111)- 00010000+1= 00010001

Explanation:

To find the 8-bit signed magnitude follow this process:

For +120

  • put 0 at Sign-bit as there is plus sign before 120.
  • Put 1 at the largest power of 2 near to 120 and less than 120, so put 1 at 64.
  • Subtract 64 from 120, i.e. 120-64 = 56.
  • Then put 1 at 32, as it is the nearest power of 2 of 56. Then 56-32=24.
  • Then put 1 at 16 and 24-16 = 8.
  • Now put 1 at 8. 8-8 = 0, so put 0 at all rest places.

To find one’s complement of a number 00011001, find 11111111 – 00011001 or put 0 in place each 1 and 1 in place of each 0., i.e., 11100110.

Now to find Two’s complement of a number, just do binary addition of the number with 1.

6 0
2 years ago
Value is always _____________ aligned in a cell. ​
Nadya [2.5K]

Answer:

Right

Explanation:

7 0
1 year ago
Lynn runs the locate command and the results include many files from a directory that she doesn't want to include in her search.
Zinaida [17]

Answer:

C) /etc/updatedb.conf

Explanation:

The locate command actually uses the configuration file located at /etc/updated.conf.

5 0
2 years ago
Read 2 more answers
Write a method named lastFirst that accepts a string as its parameter representing a person's first and last name. The method sh
Usimov [2.4K]

I'm going to assume this is Java, because you said "method" meaning it will be some sort of object oriented language, and Java's really common. Here would be the full program, but you can just take the method out isolated if you need it.

package lastname;

public class LastName {

   public static void main(String[] args) {

       // Example usage:

       String name = LastName.lastName("Garrett Acord");

       System.out.println(name);

       // Output: Acord G.

   }

   public static String lastName(String fullName)

   {

       String[] splitName = fullName.split(" ");

       return String.format("%s %s.", splitName[1], splitName[0].substring(0,1) );

       

   }

   

}

7 0
2 years ago
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